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Sia ? 4 years, 2 months ago
Microsoft Access is a database management system (DBMS) from Microsoft that combines the relational Microsoft Jet Database Engine with a graphical user interface and software-development tools.
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Sia ? 4 years, 2 months ago
Personal area network is a computer network that is mainly created for an individual .
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In personal computers, the most commonly used network connection is an Ethernet connection.
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The formula to calculate the discount rate is: Discount % = (Discount/List Price) × 100.
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CC: principal@abcpublic school.com
Subject: Invitation for Van Mahotsav
Dear sir,
On behalf of ABC public school, we would like to proudly invite you to be our guest on the occasion of Van Mahotsav. We would like you to honor this program with your presence on 28th February 2019. The event will consist of tree plantation drive wherein, every student, staff and guests will be planting tress. The event will begin at 10 am. Please revert if you accept our invitation.
Yours faithfully,
XYZ
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Interest-based child learning opportunities include activities where child preferences, things a child likes to do, and things that make a child smile and laugh are the building blocks for learning new skills and abilities.
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The boy's experience in school is full of fear and discouragement. The authoritarian way of teaching makes the boy sigh in dismay. His boredom and fear are reflected in the drooping manner in which he sits and the restlessness that he exhibits. The books give him no joy and the school makes him feel worn out.
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Given: A square ABCD.
To Prove : (i) AC = BD and (ii) Diagonals bisect each other at right angles.
Proof :
- In {tex}\triangle{/tex}ADB and {tex}\triangle{/tex}BCA, we have
AD = BC ...[As sides of a square are equal]
{tex}\angle{/tex}BAD = {tex}\angle{/tex}ABC ...[All interior angles are of 90o]
AB = BA ...[Common]
{tex}\triangle{/tex}ADB {tex}\cong{/tex} {tex}\triangle{/tex}BCA ...[By SAS rule]
AC = BD ...[c.p.c.t.] - Now in {tex}\triangle{/tex}AOB and {tex}\triangle{/tex}COD, we have
AB = CD ...[Sides of a square]
{tex}\angle{/tex}AOB = {tex}\angle{/tex}COD ...[Vertically opp. angles]
{tex}\angle{/tex}OBA = {tex}\angle{/tex}ODC ...[Alternate interior angles are equal]
{tex}\triangle{/tex}AOB {tex}\cong{/tex} {tex}\triangle{/tex}COD ...[By ASA rule]
OA = OC and OB = OD ...[c.p.c.t.] ...(1)
Now consider {tex}\triangle{/tex}s AOD and COD.
AD = CD ...[Sides of square]
OA = OC ...[As proved above]
OD = OD ...[Common]
{tex}\triangle{/tex}AOD {tex}\cong{/tex} {tex}\triangle{/tex}COD ...[By SSS rule]
{tex}\angle{/tex}AOD = {tex}\angle{/tex}COD ...[c.p.c.t.]
But {tex}\angle{/tex}AOD + {tex}\angle{/tex}COD = 180° ...[linear pair]
or {tex}\angle{/tex}AOD + {tex}\angle{/tex}AOD = 180° ...[As {tex}\angle{/tex}AOD = {tex}\angle{/tex}COD]
or 2{tex}\angle{/tex}AOD = 180° {tex}\therefore{/tex} {tex}\angle{/tex}AOD = 90° ...(2)
From equation (1) and (2) it is clear that diagonals of a square bisect each other at right angles.
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Samyak Bhujade 4 years, 2 months ago
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