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Sia 🤖 5 days, 18 hours ago
The cube root of 42 is the number which when multiplied by itself three times gives the product as 42. Since 42 can be expressed as 2 × 3 × 7. Therefore, the cube root of 42 = ∛(2 × 3 × 7) = 3.476.
Sheetal Kumari 4 days, 19 hours ago
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Posted by Aku Binu 5 days, 21 hours ago
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Sheetal Kumari 3 days, 22 hours ago
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Sia 🤖 1 week, 1 day ago
When multiplying like bases, keep the base the same and add the exponents.
When raising a base with a power to another power, keep the base the same and multiply the exponents.
When dividing like bases, keep the base the same and subtract the denominator exponent from the numerator exponent.
Posted by Shreya Gupta 1 week, 2 days ago
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Sia 🤖 1 week, 2 days ago
(x + 3)(x + 3) = (x + 3)2
= (x)2 + 2 {tex}\times{/tex} x {tex}\times{/tex} 3 + (3)2 [Using identity (a + b)2 = a2 + 2ab + b2]
= x2 + 6x + 9
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Sia 🤖 1 week, 4 days ago
P = ₹ 42000
R = 8% per annum
n = 1 year
{tex}\therefore{/tex} {tex}A = P{\left( {1 - \frac{R}{{100}}} \right)^n}{/tex}
{tex} = 42000{\left( {1 - \frac{8}{{100}}} \right)^1}{/tex}
{tex} = 42000\left( {1 - \frac{2}{{25}}} \right){/tex}
{tex} = 42000 \times \frac{{23}}{{25}}{/tex}
= ₹ 38640
Hence, its value after 1 year is ₹ 38640.
Posted by Nishid Gahane 1 week, 4 days ago
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Sia 🤖 1 week, 4 days ago
The formula to calculate the discount rate is: Discount % = (Discount/List Price) × 100.
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Sia 🤖 1 week, 5 days ago
P = Rs. 10500
R = 5% per annum
h = 1 year
{tex}\therefore A = P{\left( {1 - \frac{R}{{100}}} \right)^n}{/tex}
{tex} = 10500{\left( {1 - \frac{5}{{100}}} \right)^1}{/tex}
{tex} = 10500\left( {1 - \frac{1}{{20}}} \right){/tex}
{tex} = 10500 \times \frac{{19}}{{20}}{/tex}
= 9975
Hence, value after 1 years is Rs. 9975
Posted by Suha Mariyam 1 week, 6 days ago
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Darshan Mithapara 1 week, 4 days ago
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Posted by Nandini Pandey 1 week, 6 days ago
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Darshan Mithapara 1 week, 4 days ago
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