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Posted by Nivedhya Kailas 21 minutes ago

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ANSWER

Posted by Vansika Madaan 42 minutes ago

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Posted by Ruchika Kardam an hour ago

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Posted by Dhruv Patel 3 hours ago

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Posted by Aaa Aab 12 hours ago

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Sia 🤖 12 hours ago

Let the measure of the smaller angle be x°.

Then, the measure of the larger angles = x° + 44°

Since, these two angles are supplementary,

therefore, x° + (x° + 44°) = 180°

{tex}\Rightarrow{/tex} 2x° + 44° = 180°

{tex}\Rightarrow{/tex} 2x° = 180° – 44°

{tex}\Rightarrow{/tex} 2x° = 136°

{tex}\Rightarrow{/tex} x° = {tex}\frac{136^{\circ}}{2}{/tex}= 68^{o}

{tex}\Rightarrow{/tex} x° + 44° = 68° + 44° = 112°

Hence, the measures of the two supplementary angles are 112° and 68°.

Posted by Vijander Dhariwal 13 hours ago

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Beena Norbert 8 hours ago

A linear pair is a pair of adjacent angles whose non common sides are opposite rays

Posted by Kathir Kathiravan 15 hours ago

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Posted by Gauri Rubi Sahu 2 days, 2 hours ago

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Bishal Shah 2 days, 1 hour ago

The ratio=2:5:7
The sum of the ratio=2+5+7=14
The total sweets=98
So ,the share of first part=98×2/14=14 sweets
The share of second part=98×5/14=35sweets
The share of third part=98×7/14=49sweets.

Posted by Smita Singh 2 days, 3 hours ago

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Posted by M.Pradeep Mohandoss 2 days, 10 hours ago

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Bishal Shah 2 days, 1 hour ago

Two angles with the same vertex, one arm common and the other arms lying on opposite side of the common arm are called adjacent angles.

Posted by Yashi Karn 2 days, 10 hours ago

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Posted by Yashi Karn 1 day, 8 hours ago

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Sia 🤖 1 day, 8 hours ago

The given equation is

3s + 12 = 0

Subtract –12 from both sides

3s + 12 – 12 = 0 – 12

{tex}\therefore{/tex} 3s = – 12

Divide both sides by 3,

{tex}\frac{35}{3}=-\frac{12}{3}{/tex}

{tex}\therefore{/tex} s = –4

It is the required solution

Posted by Arya Ballamwar 3 days, 2 hours ago

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