Ask questions which are clear, concise and easy to understand.

Anyone can learn maths whether they're in higher maths at school or just looking to brush up on the basics.After discussing ways to be a good math student ,this article will teach you the basic progression of maths courses and will give you the basic elements that you'll need to learn in each course.then the article will go through the basics of learning arthimetic which will help both kids and elementary school and anyone else who needs to brush up on the fundamentals.
You can not learn maths u have to undrestand it😆😆😆

Jagtar Mistri 3 hours ago

What ?
1486.64 rupees she will charge

Jagtar Mistri 3 hours ago

12 yaar
12
😂😂what type of question is it bro .....
12

Jagtar Mistri 1 day, 2 hours ago

Mathematical induction is a mathematical proof technique. It is used to prove things.

Jagtar Mistri 1 day, 3 hours ago

Hello Akash .

Jagtar Mistri 1 day, 3 hours ago

Domain is 3 and range is -6

Jagtar Mistri 1 day, 3 hours ago

Hello Geetika .

Sia 🤖 1 day, 4 hours ago

The velocity of an object is the rate of change of its position with respect to a frame of reference, and is a function of time.

Jagtar Mistri 1 day, 3 hours ago

Sia is right

Divya Garg😉 1 day, 3 hours ago

(3tanx - tan^3x)/(1 - 3tan^2x)

English Maths 1 day, 4 hours ago

sin5π\12 - sinπ\12 \cos5π\12 + cosπ\12

Harsh Mishra 1 day, 19 hours ago

It is given in the summary of our NCERT book......

Sia 🤖 2 days, 7 hours ago

1, A1, A2, A3, ----- Am, 31 are in AP.
a = 1
an = 31

{tex}a _ { m + 2 } = 314{/tex}

an = a + (n - 1)d
31 = a + (m + 2 - 1)d

{tex}d = \frac { 30 } { m + 1 }{/tex}

{tex}\frac { A 7 } { A _ { n - 1 } } = \frac { 5 } { 9 }{/tex} (Given)

{tex}\frac { 1 + 7 \left( \frac { 30 } { m + 1 } \right) } { 1 + ( m - 1 ) \left( \frac { 30 } { m + 1 } \right) } = \frac { 5 } { 9 }{/tex}

m = 1

Jheel Tippan 1 day, 23 hours ago

R u asking for complex no.

Gaurav Seth 3 days, 7 hours ago

uppose,

A={1,2,3,4,5,6}

B={2,4,6}

In this condition, every element in B is contained in A so,

B(A

But however, B is the set of even numbers and A is the set of natural numbers and thus they are very different in terms of n.

We write even number as 2n whereas natural number just n.

So, B doesn't belong to A.

Ayush Vishwakarma😊🌊 3 days, 11 hours ago

Agar aditi Angel mile th plzz contact with me

Rahul Raj 3 days, 12 hours ago

1. "Belongs to".....if we say a belongs to A , it means a is itself an element of A or a is a member of A. 2."subset"......it is defined as part of a set.If we say set B is a subset of set A it means each element of B is a member of set A. Btt meanings r same nearly btt what is different in both......ex- if A ={1,2,3,4} then u can simply write 2 belongs to A btt to write as a subset u will have to write { 2} is a subset of A. ......well it is a nice question.it made think a little longer😊😊 hope u will understand...

Ayush Vishwakarma😊🌊 3 days, 1 hour ago

Changing of order of any object or things

Gaurav Seth 3 days, 14 hours ago

Any of the ways we can arrange things, where the order is important.

Example: You want to visit the homes of three friends ("a"), ("b") and ("c"), but haven't decided in what order. What choices do you have?

Answer: {a,b,c} {a,c,b} {b,a,c} {b,c,a} {c,a,b} {c,b,a}

Navneet Singh 3 days, 17 hours ago

All formula chpater 3

Sia 🤖 3 days, 11 hours ago

Let P(n) = a + ar + ar2 + ..... + arn-1{tex} = \frac{{a({r^n} - 1)}}{{r - 1}}{/tex}.
For n = 1
{tex}P(1) = a{r^{1 - 1}} = \frac{{a({r^1} - 1)}}{{r - 1}} \Rightarrow a = a{/tex}
{tex}\therefore {/tex} P(1) is true
Let P(n) be true for n = k
{tex}\therefore P(k) = a + ar + a{r^2} + .... + a{r^{k - 1}}{/tex}{tex} = \frac{{a({r^k} - 1)}}{{r - 1}}{/tex} .... (i)
For n = k + 1
R.H.S. {tex} = \frac{{a({r^{k + 1}} - 1)}}{{r - 1}}{/tex}
L.H.S. {tex} = \frac{{a({r^k} - 1)}}{{r - 1}} + a{r^k}{/tex} [ Using (i)]
{tex} = \frac{{a{r^k}}}{{r - 1}} - \frac{a}{{r - 1}} + a{r^k}{/tex}
{tex} = a{r^k} \cdot \left( {\frac{1}{{r - 1}}+1} \right) - \frac{a}{{r - 1}} = \frac{{a{r^{k + 1}}}}{{r - 1}} - \frac{a}{{r - 1}}{/tex}{tex} = \frac{{a{r^{k + 1}} - a}}{{r - 1}}{/tex}
{tex} = \frac{{a({r^{k + 1}} - 1)}}{{r - 1}}{/tex}
{tex}\therefore {/tex} P(k + 1) is true
Thus P(k) is true {tex} \Rightarrow {/tex} P(k + 1) is true
Hence by principle of mathematical induction, P(n) is true for all {tex}n \in N{/tex}.

Nitin Tiwari 3 days ago

Taking RHS side Sin2x sin10x Sin(6x-4x) sin(6x+4x) (Sin6xcos4x - cos6xsin4x)(sin6xcos4x+cos6xsin4x) : (since-sin(A+B)=sinAcosB+sinBcosA)(sin(A+B)=sinAcosB- sinBcosA) Sin^2(6x)cos^2(4x) - cos^2(6x)sin^2(4x) Sin^2(6x)(1 - sin^2(4x)) - (1 - sin^2(6x))sin^2(4x) Sin^2(6x) - sin^2(4x)sin^2(4x) - sin^2(4x) + sin^2(6x )sin^2(4x) Sin^2(6x) - sin^2(4x) Hence . Proved

Tripti Verma 4 days, 4 hours ago

Thank you🙂

Rahul Raj 4 days, 5 hours ago

LHS= sin(6x-4x)sin(6x+4x) =sin2xsin10x = RHS

Hemant Kumar 4 days, 13 hours ago

Sin.cot98*2cosec/17tan
Bro just solve rd sharma and u will get all types of questions of complex no.s

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