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Saloni Thakur 6 days, 4 hours ago

Yes studying form byjus is good
Also you may prefer unacademy
Or physics wallah classes from youtube

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King K. Tyagi Ji 😘 1 week ago

Ara bhi jb tm suspend ho jao to kisi or id sa chala na ya ap

King K. Tyagi Ji 😘 1 week ago

🤔🤔vapis ka to pta nee kyouki ma b 5 times suspend ho chuka hu pr dusari id sa account bana kr tbi vapis aa jata hu 🤣🤣

King K. Tyagi Ji 😘 1 week ago

Agar tm dobara suspend ho jao to dusari id sa account bana , jo id chala rha ho us sa mt bana okk

King K. Tyagi Ji 😘 1 week ago

Or dusri baat ya ki ma to tma janata v nee hu tm muza kaisa janta ho

King K. Tyagi Ji 😘 1 week ago

Phala tm ya bato ki tm na ya app usi id sa cahliya hua ha kya

*** A 1 week ago

mere ko kisi ne 1 month phle report kr diya tha aur m khuch msg bhi nhi likh pa rha usme 30 days suspend dikha rha tha

King K. Tyagi Ji 😘 1 week ago

Or thumara frend ka bara ma mana jo likha ha vo to bato shi ha ya nhi

King K. Tyagi Ji 😘 1 week ago

Ankit kumar 🤔🤔ha kya vo yha pr aaiya ha kya kabhi tma pta ho to

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Yogita Ingle 1 week ago

As the name represents, **the finite set is a set having finite or countable number of elements.**

__ Example __set of all English alphabets.

**A set which is not a finite set is called an Infinite Set**. Or if you cannot count the number of elements of a particular set then it is said to be an infinite set.

N is a set of all natural numbers starting from zero. Its number of elements is not countable so we use the three dots to represent itsinfinity.

Posted by Ujjwal Pandey 1 week, 1 day ago

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Ujjwal Pandey 1 week, 1 day ago

First equation is upto 38 and second is upto 72 . It is a reasoning question.

Posted by *** A 1 week, 2 days ago

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*** A 1 week, 2 days ago

Hard work krna pdega kya math ke liye math lena future ke liye important h kya

Posted by Aayush Chaudhary 1 week, 3 days ago

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Drake Verma 1 week, 3 days ago

Sorry Anjali u r wrong here, correct explain is that if u r forming natural no. Less then 1000 so we will select any first no. From the given set and we can do it in 5 ways same goes for second and third no. Because repetition is allowed so,
The req. No. Will be-5*5*5=125.
Ur ans will be correct if repetition is not allowed.

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Posted by Lucifer💞💞 Morningstar😎😎 1 week, 4 days ago

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Drake Verma 1 week, 4 days ago

Bro open ur scientific calculator and get the value....as here i can't describe u the exact value of log 3...or if u want to learn then go on YouTube u will get easy method to calculate values of log ones.
And r u waiting for season 5 of Lucifer 😂?

Posted by Kaustubh Agrawal 1 week, 4 days ago

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*** A 1 week, 2 days ago

Equivalent sets = two finite sets A and B are equivalent, if their cardinal numbers are same.
Equal sets = two sets A and B are said to be equal if they have exactly the same element

Anjali Goyal 1 week, 3 days ago

Equivalent sets refers to equal of elements
But equal sets refer to same elements

Yogita Ingle 1 week, 4 days ago

Two sets A and B can be equal only if each element of set A is also the element of the set B. Also if two sets are the subsets of each other, they are said to be equal. This is represented by:

A = B

To be equivalent, the sets should have the same cardinality. This means that there should be one to one correspondence between elements of both the sets. Here, one to one correspondence means that for each element in the set A, there exists an element in the set B till the sets get exhausted.

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Posted by Suman Sharma 2 weeks ago

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Yogita Ingle 2 weeks ago

Since x-coordinate of every point in yz-plane is zero. Let P (0, y, z) be a point on the yz-plane such that PA = PB = PC.

Now PA = PB

(0 – 2)^{2} + (y – 0)^{2} + (z – 3^{)2} = (0 – 0)^{2} + (y – 3)^{2} + (z – 2)^{2}

i.e. z – 3y = 0

and PB = PC

⇒ y^{2} + 9 – 6y + z^{2} + 4 – 4z = y^{2} + z^{2} + 1 – 2z ,

i.e. 3y + z = 6 Simplifying the two equating, we get y = 1, z = 3

Here, the coordinate of the point P are (0, 1, 3).

Posted by Suman Sharma 2 weeks ago

- 2 answers

Yogita Ingle 2 weeks ago

let the point p be (h, k)

Now 2PA,=3PB

PA=√[h^2+k^2]

pb=√[h-4]^2+[k+3]^2

given 2PA=3PB

SQ. both sides

4PAsq. =9PBsq

4(h^2+k^2)=9[(h-4)^2+(k+3)^2]

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