Ask questions which are clear, concise and easy to understand.

Ask Question
  • 1 answers

Ishitha Ishitha 42 minutes ago

Bronchial respiration
  • 1 answers

Sumit Yadav an hour ago

palisade mesophyll cell
  • 0 answers
  • 1 answers

Jatin Kushwaha 15 hours ago

If two distances are equal and the points are not collinear then points form a isosceles triangle. To prove that it is also right triangle , use the converse of Pythagoras Check that is square of longest sides equal to sum of square of two shorter side. H^2=P^2+B^2
  • 2 answers

Jatin Kushwaha 14 hours ago

Napoleon code was implemented by Napoleon . It abolished the fedual system privileges based on birth and established equality before law and provide right to property.
Help me
  • 0 answers
  • 0 answers
  • 0 answers
Mcq
  • 0 answers
  • 1 answers

Sumit Yadav 16 hours ago

A(-1,0)B(3,1)C(2,2)D(x, y) ABCD is a diagonal apply mid point method AC and BD and 4th vertex (-2,1)
  • 2 answers

Aditya Choudhary 19 hours ago

Yes, there are some parents like Mrs Pumphrey who spoil their children by over-indulging and pampering them. They try to overfeed their children or pets despite knowing the ill-effects of overeating on their health. Mark me perfect ...
Ya there are parents like Mrs. Pumphery. But she is a pet owner in chapter they use to talk about pet his name was Tricki.
  • 1 answers

Sumit Yadav 16 hours ago

the y axis divides the line joining the points (-2, -3) and (3, 7) be k : 1. point of intersection line to y axis to be (0, y). Apply section formula and answer 2:3
  • 3 answers

The Mystery 20 hours ago

Learn more:
[tex]\sf \color{aqua}{Trigonometry\: Table}\\ \blue{\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|} \sf \red{\angle A} & \red{\sf{0}^{ \circ} }&\red{ \sf{30}^{ \circ} }& \red{\sf{45}^{ \circ} }& \red{\sf{60}^{ \circ}} &\red{ \sf{90}^{ \circ}} \\ \hline \\ \rm \red{sin A} & \green{0} & \green{\dfrac{1}{2}}& \green{\dfrac{1}{ \sqrt{2} }} &\green{ \dfrac{ \sqrt{3}}{2} }&\green{1} \\ \hline \\ \rm \red{cos \: A} & \green{1} &\green{ \dfrac{ \sqrt{3} }{2}}&\green{ \dfrac{1}{ \sqrt{2} }} & \green{\dfrac{1}{2}} &\green{0} \\ \hline \\\rm \red{tan A}& \green{0} &\green{ \dfrac{1}{ \sqrt{3} }}&\green{1} & \green{\sqrt{3}} & \rm \green{\infty} \\ \hline \\ \rm \red{cosec A }& \rm \green{\infty} & \green{2}& \green{\sqrt{2} }&\green{ \dfrac{2}{ \sqrt{3} }}&\green{1} \\ \hline\\ \rm \red{sec A} & \green{1 }&\green{ \dfrac{2}{ \sqrt{3} }}& \green{\sqrt{2}} & \green{2} & \rm \green{\infty} \\ \hline \\ \rm \red{cot A }& \rm \green{\infty} & \green{\sqrt{3}}& \green{1} & \green{\dfrac{1}{ \sqrt{3} }} & \green{0}\end{array}}}}[/tex]

The Mystery 20 hours ago

$$sinA = x$$
$$secA=y$$
$$\sf \bf :\longmapsto \dfrac{1}{cosA} = y$$
$$\sf \bf :\longmapsto \dfrac{sinA}{cosA} = xy$$
$$\sf \bf :\longmapsto tanA =xy$$
Learn more:

$$\sf \color{aqua}{Trigonometry\: Table}\\ \blue{\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|} \sf {\angle A} & \{\sf{0}^{ \circ} }&\red{ \sf{30}^{ \circ} }& \{\sf{45}^{ \circ} }& \red{\sf{60}^{ \circ}} &{ \sf{90}^{ \circ}} \\ \hline \\ \rm {sin A} & \green{0} & {\dfrac{1}{2}}& {\dfrac{1}{ \sqrt{2} }} &{ \dfrac{ \sqrt{3}}{2} }&{1} \\ \hline \\ \rm {cos \: A} & {1} &{ \dfrac{ \sqrt{3} }{2}}&{ \dfrac{1}{ \sqrt{2} }} & {\dfrac{1}{2}} &{0} \\ \hline \\\rm {tan A}& {0} &{ \dfrac{1}{ \sqrt{3} }}&{1} & {\sqrt{3}} & \rm {\infty} \\ \hline \\ \rm {cosec A }& \rm {\infty} & {2}& {\sqrt{2} }&{ \dfrac{2}{ \sqrt{3} }}&{1} \\ \hline\\ \rm {sec A} & {1 }&{ \dfrac{2}{ \sqrt{3} }}& {\sqrt{2}} & {2} & \rm {\infty} \\ \hline \\ \rm {cot A }& \rm {\infty} & {\sqrt{3}}& {1} & {\dfrac{1}{ \sqrt{3} }} &{0}\end{array}}}}$$

Prajan Elango 21 hours ago

Tan A = SinA/Cos A Sec A = 1/Cos A So TanA = SinA * Sec A = x*y = xy
  • 1 answers

Prince Sharma 22 hours ago

Paper easy hoga ya hard

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

CBSE Test Generator

Create papers in minutes

Print with your name & Logo

Download as PDF

3 Lakhs+ Questions

Solutions Included

Based on CBSE Blueprint

Best fit for Schools & Tutors

Work from Home

  • Work from home with us
  • Create questions or review them from home

No software required, no contract to sign. Simply apply as teacher, take eligibility test and start working with us. Required desktop or laptop with internet connection