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  • 2 answers

Satwik Banerjee 18 hours ago

The second equation please

Tejas Bramhe 20 hours ago

Plz type the whole question
  • 0 answers
  • 1 answers

Preeti Dabral 20 hours ago

Let p be any positive integer and b = 3. Applying division Lemma with p and b =3 ,

we have
p = 3q + r, where 0 {tex}\leq{/tex} r < 3 and q is some integer

So r=0,1,2

If r=0 , p=3q

If r=1, p=3q+1

If r=2, p=3q+2

Therefore any positive integer  is of form 3q,3q+1,3q+2 for some integer q.

  • 3 answers

Shanvi Sneh 1 day, 5 hours ago

Answer will be 0.

T Lalitha Rani Saraswathi 1 day, 14 hours ago

Sorry it's 1

T Lalitha Rani Saraswathi 1 day, 14 hours ago

2
  • 1 answers

Himanshi Gautam 1 day, 1 hour ago

4-5√3= a/b -5√3= a/b-4 √3=4/5-a/b RHS is not equal to LHS HENCE IT IS AN IRRATIONAL NUMBER.
  • 0 answers
  • 1 answers

Preeti Dabral 1 day, 23 hours ago

Suppose the numerator of the fraction be x 

Denominator of the fraction be y 
{tex}\therefore{/tex} the fraction is {tex}\frac{x}{y}{/tex}
According to the question,

 The sum of the numerator and denominator of the fraction is 12.
{tex}\Rightarrow x + y = 12{/tex}
{tex}\Rightarrow{/tex} {tex}x + y - 12 = 0{/tex}
If the denominator is increased by 3, the fraction becomes {tex}\frac{1}{2}{/tex}.
{tex}\Rightarrow \frac{x}{{y + 3}} = \frac{1}{2}{/tex}
{tex}\Rightarrow{/tex} {tex}2x = (y + 3){/tex}
{tex}\Rightarrow{/tex} {tex}2x - y - 3 = 0{/tex}
So, we have two equations
{tex}x + y - 12 = 0{/tex}
{tex}2x - y - 3 = 0{/tex}
Here x and y are unknowns.
We have to solve the above equations for x and y.
By using cross-multiplication, 
{tex}\Rightarrow \frac{x}{{(1) \times ( - 3) - ( - 1) \times - 12}}{/tex} {tex} = \frac{{ - y}}{{1 \times ( - 3) - 2 \times - 12}}{/tex} {tex}= \frac{1}{{1 \times ( - 1) - 2 \times (1)}}{/tex}
{tex}\Rightarrow \frac{x}{{ - 3 - 12}}{/tex} {tex}= \frac{{ - y}}{{ - 3 + 24}} = \frac{1}{{ - 1 - 2}}{/tex}
{tex}\Rightarrow \frac{x}{{ - 15}} = \frac{{ - y}}{{21}} = \frac{1}{{ - 3}}{/tex}
{tex}\Rightarrow \frac{x}{{15}} = \frac{y}{{21}} = \frac{1}{3}{/tex}
{tex}\Rightarrow x = \frac{{15}}{3},\;y = \frac{{21}}{3}{/tex}
{tex}\Rightarrow{/tex} {tex}x = 5, y = 7{/tex}
The fraction is {tex}\frac{5}{7}{/tex}

  • 1 answers

Preeti Dabral 1 day, 23 hours ago

Given : 

To Find :  solve it by cross multiplication method

Solution:

Cross multiplication method

Equations : 

Comparing the given equations

So, x = 4 and y = 1

  • 3 answers

Preeti Dabral 1 day, 23 hours ago

<header>

Consider quadratic polynomial
P(x) = 2x2 – 16x + 30.
Now, 2x2 – 16x + 30 = (2x – 6) (x – 3)
= 2 (x – 3) (x – 5)
The zeros of P(x) are 3 and 5.
Sum of the zeros = 3 + 5 = 8 = −(−16)2 = -[coefficient of xcoefficient of x2]

Product of the zeros = 3 × 5 = 15 = 302 = [constant term coefficient of x2]
So if ax2 + bx + c, a ≠ 0 is a quadratic polynomial and α, β are two zeros of polynomial then
α+β=−ba
αβ=ca
In general, it can be proved that if α, β, γ are the zeros of a cubic polynomial ax3 + bx2 + cx + d, then
α+β+γ=−ba
αβ+βγ+γα=ca
αβγ=−da
Note:  ba, ca and da  are meaningful because a ≠ 0.

</header>

Armaan Armaan 1 day, 22 hours ago

Like in 3x^2 + 5 In this 3 is a coefficient

Armaan Armaan 1 day, 22 hours ago

Zeroes are number like a and b. Coefficient are numbers side the x and y. 😉
  • 1 answers

Aditya Raghuwanshi 1 day, 3 hours ago

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  • 3 answers

Armaan Armaan 1 day, 22 hours ago

19/30,20/30,21/30,22/30,23/30

Vinayak Rathod Vishal 2 days, 4 hours ago

Find the 6th term from the end of the A. P 17,14 , 11...-40

Akarshit Sharma 2 days, 15 hours ago

3/5=0.6 4/5=0.8 So numbers between between 0.6 and 0.8 are 0.65 , 0.70 , 0.71 , 0.75 , 0.61
  • 1 answers

Tejas Bramhe 20 hours ago

They can not be added
  • 3 answers

Bishnu Gond 2 days, 5 hours ago

X coordinate 0 and y coordinate 3

Sarita Panda 2 days, 6 hours ago

(5,-2), (6,-3), (0,3), (3,0) and infinitely many more.

Vipin Patel 2 days, 16 hours ago

2,1
4-1
  • 1 answers

Armaan Armaan 1 day, 22 hours ago

3
  • 5 answers

Armaan Armaan 1 day, 22 hours ago

79

Aditya Raghuwanshi 1 day, 3 hours ago

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.
  • Don't post personal information, mobile numbers and other details.
  • Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
  • Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
  • Ask specific question which are clear and concise.

Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

Vipin Patel 2 days, 16 hours ago

79

Miswah Anwar 2 days, 17 hours ago

79

Sanjay Yadav 2 days, 18 hours ago

79
  • 2 answers

Tejas Bramhe 20 hours ago

It cannot be solved by factorisation method

Armaan Armaan 1 day, 22 hours ago

5/2,7/2

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