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Yogita Ingle 3 hours ago
GIVEN
54th term
a + 53 d
132 more than a54
a + 53d + 132
Therefore, this is your an (last term)
AP 3 15 27 39,...
first term 'a' = 3
Common difference 'd' = 15 - 3 = 12
an = a + 53d + 132
FORMULA
an = a + (n - 1)d
a + 53d + 132 = a + (n - 1)d
Subsitute the values of a and d
3 + 53x12 + 132 = 3 + ( n - 1) x 12
3 + 53x12 + 132 - 3 = 12( n - 1)
636 + 132 = 12( n - 1)
768 = 12( n - 1)
768 / 12 = n - 1
64 = n - 1
64 + 1 = n
n = 65
Therefore, the required term is 65th.
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Yogita Ingle 3 hours ago
fundamental theorem of arithmetic:
Every composite number can be expressed as a product of powers of primes, and this factorization is unique, apart from the order in which the prime factors occur
96= 2^5*3
360=2^3*3^2*5
lcm(96,360)=product of the greatest power of each prime factors, in the numbers
=2^5*3^2*5
=1440
Read more on Brainly.in - https://brainly.in/question/1144348#readmore
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</a> Hope it'll help u...n ignore my handwriting 😂😂
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(-3,2) - II quadrant
(3,2) - I quadrant
(2,0) - x -axis
(0,2) - y- axis
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