Ask questions which are clear, concise and easy to understand.

Ask QuestionPosted by Gopal Roy 8 hours ago

- 0 answers

ANSWER

Posted by A . 9 hours ago

- 1 answers

Posted by Priya Kumari 12 hours ago

- 1 answers

Posted by Prachi Sadhya 15 hours ago

- 1 answers

Yogita Ingle 15 hours ago

2x + 3y = 7

2ax + (a + b) y = 28

If two equations has infinite solutions, then,

a1 / a2 = b1 / b2 = c1 /c2

2 / 2a = 3 / a+b = -7 / -28

1/a = 3/a+b = 1/4

Now,

1/a = 1/4

a = 4

And

3/a+b = 1/4

12 = 4 + b

12 - 4 = b

b = 8

Thus,

a = 4

b = 8

So, b = 2a

Posted by Sandhya K 16 hours ago

- 1 answers

Yogita Ingle 15 hours ago

( 17 x 11 x 2 ) + ( 17 x 11 x 5 )

By taking ( 17 x 11 ) common ,

= ( 17 x 11 ) ( 2 + 5 )

= ( 17 x 11 ) ( 7 )

= 17 x 11 x 7.

If any number can be represented in the form of product of prime numbers then that number is composite number.

Hence , ( 17 x 11 x 2 ) + ( 17 x 11 x 5 ) is a composite number.

Posted by Urvashiverma Rajput 19 hours ago

- 2 answers

Shambhu Shind 9 hours ago

Prime factors of 378=2*3*3*3*7
Prime factors of 180=2*2*3*3*5
Prime factors of 420=2*2*3*5*7
So, hcf of 378,180,420 is 2*3=6
LCM of 348,180,420 is 2*2*3*3*3*5*7=3780

Gaurav Seth 18 hours ago

A n s w e r

Prime factors of 378 = 2 × 3 × 3 × 3 × 7

Prime factors of 180 = 2 × 2 × 3 × 3 × 5

Prime factors of 420 = 2 × 2 × 3 × 5 × 7

So, HCF of 378, 180 and 420 is 2 × 3 = 6

And LCM of 378, 180 and 420 is 2 × 2 × 3 × 3 × 3 × 5 × 7 = 3780

Posted by Randheer Singh 21 hours ago

- 0 answers

Posted by Mahantesh Kajagar 21 hours ago

- 0 answers

Posted by Veena Rankawat 21 hours ago

- 1 answers

Posted by Chandan Akharia 22 hours ago

- 0 answers

Posted by Abhishek Mandal 22 hours ago

- 1 answers

Posted by Charu D 1 day, 2 hours ago

- 1 answers

Gaurav Seth 23 hours ago

**1. Form the pair of linear equations in the following problems, and find their solutions graphically.**

**(i) 10 students of Class X took part in a Mathematics quiz. If the number of girls is 4 more than the number of boys, find the number of boys and girls who took part in the quiz.**

**(ii) 5 pencils and 7 pens together cost 50, whereas 7 pencils and 5 pens together cost 46. Find the cost of one pencil and that of one pen.**

**Solution:**

(i)Let there are x number of girls and y number of boys. As per the given question, the algebraic expression can be represented as follows.

x +y = 10

x– y = 4

Now, for x+y = 10 or x = 10−y, the solutions are;

For x – y = 4 or x = 4 + y, the solutions are;

The graphical representation is as follows;

Click on the given link to continue

Posted by Charu D 1 day, 2 hours ago

- 3 answers

Posted by Maitreyee Dawle 1 day, 12 hours ago

- 2 answers

Shubham Kumar 1 day, 12 hours ago

Here your answer goes
Step :-1
Take one equation from the two equations and represent it in the form of x and y by replacing
7x - 15y = 2----- > 1
x + 2y = 3------- > 2
Take equation 2
x = 3 - 2y ------>> 3
Step :- 2
Now , Substitute the value of x in equation 1
7 ( 3 - 2y ) - 15 = 2
21 - 14y - 15y = 2
21 - 29y = 2
-29y = 21 - 2
y =
29/19
Step :- 3
Put the obtained value of y in equation 3
x = 3 - 2yx=3−2y
x =
29/49
Hope you like this answer

Posted by Yogita Gamer 1 day, 13 hours ago

- 1 answers

Sourav Keshri 23 hours ago

Sin square 60°+2tan 45°- cos square 30°
(√ 3/4)square + 2x1-
(√ 3/4)square
3/4 + 2/1 -3/4 (+3/4 or -3/4 cut ho jayega)
+2/1 = (2 Ans)

Posted by Dev Raj 1 day, 15 hours ago

- 2 answers

Yogita Ingle 1 day, 13 hours ago

We know that the largest 5 digit number is 99999.

So here we can see that 99999 is not a perfect square as it leaves 143 as the remainder while finding it s square root.

So for finding 5 digit perfect square we will have to subtract 143 from 99999

=> 99999-143 = 99856

Hence 99856 is a perfect square whose square root is √99856 = 316.

Posted by Pranav Pranav 1 day, 15 hours ago

- 0 answers

Posted by Simran Gupta 1 day, 18 hours ago

- 2 answers

Posted by Tarak () 1 day, 20 hours ago

- 1 answers

Yogita Ingle 1 day, 12 hours ago

we know that if there is no solution then lines must be parallel and if lines are parallel than

≠ c_{1/}c_{2}

so,a_{1}/a_{2}=3/6= 1/2

b_{1}/b_{2}=1 / k

now

so k=2

Posted by Vaibhav Sharma 2 days, 9 hours ago

- 4 answers

Spoorti Shrinivas 19 hours ago

the square of the hypotenuse side is equal to the sum of squares of the other two sides is know as phythagoras theorem
Formula : Hypotenuse2 = Perpendicular2 + Base2
c2 = a2 + b2

Jobanjot Kaur 1 day, 21 hours ago

The square of two the hypotenuse is the sum of the other two sides is known as pythagoras theorem
FORMULA:
H2 =B2+P2
H Square =B Square +P Square

Shuvendu Kumar 1 day, 21 hours ago

The square of two the hypotenuse is the sum of other two sides is known as pythagoras therom

Harshali Vilhekar 2 days, 7 hours ago

The square of the hypotenuse is equal to the sum of squares of other two sides is known as Pythagoras theorem

Posted by Ajay Kartikay Bansal 2 days, 16 hours ago

- 1 answers

Gaurav Seth 2 days, 16 hours ago

In figure, a circle touches all the four sides of a quadrilateral ABCD_{/} whose sides AB = 6 cm, BC = 7 cm and CD = 4 cm. Find AD.

Since, length of two tangents drawn from an external point of circle are equal.

So, AP = AS

BP = BQ DR = DS

and RC = CQ

Adding all, we get

(AP + BP) + (DR + RC) = AS + BQ + DS + CQ

⇒ (AP + BP) + (DR + RC)

= (AS + DS) + (BQ + CQ)

⇒ AB + DC = AD + BC

⇒ 6 + 4 = AD + 7

⇒ 10 = AD + 7

AD = 10 – 7 = 3 cm

Hence, AD = 3 cm.

Posted by 😀😀😀.. 😊😊😊 2 days, 18 hours ago

- 3 answers

Posted by Yashraj Ahirwar 2 days, 22 hours ago

- 5 answers

Bhai Se Sikho Sikho 2 days, 17 hours ago

sin A = 3/4
P = 3
H= 4
B=?
H² = P² + B²
B²= 16 - 9
B = √7
Sec A = H/B
= 4/√7
4/√7 × √7/√7 = 4√7/7
So, Sec A = 4√7/7

Nisha😋🤣 Bharti 2 days, 18 hours ago

Sin A= 3/2=p/h
b²=h²-p²=
b²=4-9=-5
b=√-5
SecA=h/b=2/-√5

Posted by Gourahari Meher 2 days, 23 hours ago

- 3 answers

Yogita Ingle 2 days, 23 hours ago

6 = 2^{1} × 3^{1}

20 = 2^{2} × 5^{1}

LCM(6,20) = 2^{2} × 3^{1} × 5^{1}

LCM(6,20) = 60

Posted by Khushdeep Kaur 2 days, 18 hours ago

- 1 answers

Yogita Ingle 2 days, 23 hours ago

The common point of a tangent to a circle and the circle is called___

Point of contact

Posted by Ok Wahsi 3 days ago

- 2 answers

Posted by Ok Wahsi 3 days ago

- 2 answers

Maniya Jain 2 days, 19 hours ago

2x-y=2
2x-2=y ....(1)
x+3y=15 ....(2)
By substituting the value from 1 and 2 eq.
x+3(2x-2)=15
x+6x-6=15
7x-6=15
7x = 21
x= 21÷7
x=3
From 1 eq we can find out the value of y .....
2x-2=y
2(3)-2=y
6-2 =y
x=3 and y=4

Yogita Ingle 2 days, 23 hours ago

2x - y = 2

y = 2x - 2 ...(1)

x + 3y = 15 ...(2)

Substituting the value of y from (1) in (2), we get,

x + 6x - 6 = 15

7x = 21

x = 3

From (1),

y = 2 3 - 2 = 4

Create papers in minutes

Print with your name & Logo

Download as PDF

3 Lakhs+ Questions

Solutions Included

Based on CBSE Blueprint

Best fit for Schools & Tutors

- Work from home with us
- Create questions or review them from home

No software required, no contract to sign. Simply apply as teacher, take eligibility test and start working with us. Required desktop or laptop with internet connection