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Anamika Bajpai 2 days, 16 hours ago

Answer plz
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Piyush ❤️ 2 days, 13 hours ago

But kasa solve krka send kru

Khushi Sharma 2 days, 19 hours ago

Pls anybody answer🙏
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Himanshu Chauhan 2 days, 2 hours ago

Given √3 + √5 To prove: √3 + √5 is an irrational number. Let us assume that√3 + √5 is a rational number. So it can be written in the form a/b √3 + √5 = a/b Here a and b are coprime numbers and b ≠ 0 Solving √3 + √5 = a/b On squaring both sides we get, (√3 + √5)² = (a/b)² √3² + √5² + 2(√5)(√3) = a²/b² 3 + 5 + 2√15 = a²/b² 8 + 2√15 = a²/b² 2√15 = a²/b² – 8 √15 = (a²- 8b²)/2b a, b are integers then (a²-8b²)/2b is a rational number. Then √15 is also a rational number. But this contradicts the fact that √15 is an irrational number. Our assumption is incorrect √3 + √5 is an irrational number. Hence, proved.

Rupesh Rounak 2 days, 22 hours ago

yuik
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Rose Preet 3 days, 14 hours ago

3x²+5x+2 3x²+3x+2x+2 3x(x+1) +2(x+1) (X+1)(3x+2) X+1is equal to 0 Then x is equal to -1 Here we can say that alpha is equal to -1 Similarly, If we take 3x +2 Beta is equal to x is eqal to -2/3 1/alpha+ 1/beta 1/-1 +1/-2/3 Is eqal to -5/3
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Hiral Thakur 5 days, 21 hours ago

Cos
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