Ask questions which are clear, concise and easy to understand.

• 1 answers

Jatin Kushwaha 17 hours ago

If two distances are equal and the points are not collinear then points form a isosceles triangle. To prove that it is also right triangle , use the converse of Pythagoras Check that is square of longest sides equal to sum of square of two shorter side. H^2=P^2+B^2
• 1 answers

Sumit Yadav 18 hours ago

No solution
• 0 answers
• 1 answers

Sumit Yadav 18 hours ago

A(-1,0)B(3,1)C(2,2)D(x, y) ABCD is a diagonal apply mid point method AC and BD and 4th vertex (-2,1)
• 1 answers

Sumit Yadav 18 hours ago

the y axis divides the line joining the points (-2, -3) and (3, 7) be k : 1. point of intersection line to y axis to be (0, y). Apply section formula and answer 2:3
• 3 answers

The Mystery 22 hours ago

Learn more:
$$\sf \color{aqua}{Trigonometry\: Table}\\ \blue{\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|} \sf \red{\angle A} & \red{\sf{0}^{ \circ} }&\red{ \sf{30}^{ \circ} }& \red{\sf{45}^{ \circ} }& \red{\sf{60}^{ \circ}} &\red{ \sf{90}^{ \circ}} \\ \hline \\ \rm \red{sin A} & \green{0} & \green{\dfrac{1}{2}}& \green{\dfrac{1}{ \sqrt{2} }} &\green{ \dfrac{ \sqrt{3}}{2} }&\green{1} \\ \hline \\ \rm \red{cos \: A} & \green{1} &\green{ \dfrac{ \sqrt{3} }{2}}&\green{ \dfrac{1}{ \sqrt{2} }} & \green{\dfrac{1}{2}} &\green{0} \\ \hline \\\rm \red{tan A}& \green{0} &\green{ \dfrac{1}{ \sqrt{3} }}&\green{1} & \green{\sqrt{3}} & \rm \green{\infty} \\ \hline \\ \rm \red{cosec A }& \rm \green{\infty} & \green{2}& \green{\sqrt{2} }&\green{ \dfrac{2}{ \sqrt{3} }}&\green{1} \\ \hline\\ \rm \red{sec A} & \green{1 }&\green{ \dfrac{2}{ \sqrt{3} }}& \green{\sqrt{2}} & \green{2} & \rm \green{\infty} \\ \hline \\ \rm \red{cot A }& \rm \green{\infty} & \green{\sqrt{3}}& \green{1} & \green{\dfrac{1}{ \sqrt{3} }} & \green{0}\end{array}}}}$$

The Mystery 22 hours ago

$$sinA = x$$
$$secA=y$$
$$\sf \bf :\longmapsto \dfrac{1}{cosA} = y$$
$$\sf \bf :\longmapsto \dfrac{sinA}{cosA} = xy$$
$$\sf \bf :\longmapsto tanA =xy$$
Learn more:

$$\sf \color{aqua}{Trigonometry\: Table}\\ \blue{\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|} \sf {\angle A} & \{\sf{0}^{ \circ} }&\red{ \sf{30}^{ \circ} }& \{\sf{45}^{ \circ} }& \red{\sf{60}^{ \circ}} &{ \sf{90}^{ \circ}} \\ \hline \\ \rm {sin A} & \green{0} & {\dfrac{1}{2}}& {\dfrac{1}{ \sqrt{2} }} &{ \dfrac{ \sqrt{3}}{2} }&{1} \\ \hline \\ \rm {cos \: A} & {1} &{ \dfrac{ \sqrt{3} }{2}}&{ \dfrac{1}{ \sqrt{2} }} & {\dfrac{1}{2}} &{0} \\ \hline \\\rm {tan A}& {0} &{ \dfrac{1}{ \sqrt{3} }}&{1} & {\sqrt{3}} & \rm {\infty} \\ \hline \\ \rm {cosec A }& \rm {\infty} & {2}& {\sqrt{2} }&{ \dfrac{2}{ \sqrt{3} }}&{1} \\ \hline\\ \rm {sec A} & {1 }&{ \dfrac{2}{ \sqrt{3} }}& {\sqrt{2}} & {2} & \rm {\infty} \\ \hline \\ \rm {cot A }& \rm {\infty} & {\sqrt{3}}& {1} & {\dfrac{1}{ \sqrt{3} }} &{0}\end{array}}}}$$

Prajan Elango 23 hours ago

Tan A = SinA/Cos A Sec A = 1/Cos A So TanA = SinA * Sec A = x*y = xy
• 4 answers

🤟Royal Thakur🤟 1 day, 17 hours ago

😳😳Wow bro 🙌🙌🙌🙌🙌🙌

The Mystery 1 day, 17 hours ago

Edited table :

$$\sf \color{aqua}{Trigonometry\: Table}\\ \blue{\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|} \sf \red{\angle A} & \red{\sf{0}^{ \circ} }&\red{ \sf{30}^{ \circ} }& \red{\sf{45}^{ \circ} }& \red{\sf{60}^{ \circ}} &\red{ \sf{90}^{ \circ}} \\ \hline \\ \rm \red{sin A} & \green{0} & \green{\dfrac{1}{2}}& \green{\dfrac{1}{ \sqrt{2} }} &\green{ \dfrac{ \sqrt{3}}{2} }&\green{1} \\ \hline \\ \rm \red{cos \: A} & \green{1} &\green{ \dfrac{ \sqrt{3} }{2}}&\green{ \dfrac{1}{ \sqrt{2} }} & \green{\dfrac{1}{2}} &\green{0} \\ \hline \\\rm \red{tan A}& \green{0} &\green{ \dfrac{1}{ \sqrt{3} }}&\green{1} & \green{\sqrt{3}} & \rm \green{\infty} \\ \hline \\ \rm \red{cosec A }& \rm \green{\infty} & \green{2}& \green{\sqrt{2} }&\green{ \dfrac{2}{ \sqrt{3} }}&\green{1} \\ \hline\\ \rm \red{sec A} & \green{1 }&\green{ \dfrac{2}{ \sqrt{3} }}& \green{\sqrt{2}} & \green{2} & \rm \green{\infty} \\ \hline \\ \rm \red{cot A }& \rm \green{\infty} & \green{\sqrt{3}}& \green{1} & \green{\dfrac{1}{ \sqrt{3} }} & \green{0}\end{array}}}}$$

The Mystery 1 day, 17 hours ago

$$\sf \bf :longmapsto xcosA = 8$$
$$\sf \bf :longmapsto cosA=\dfrac{8}{x}$$
Taking second equation,
$$\sf \bf :longmapsto 15cosecA = 8secA$$
$$\sf \bf :longmapsto 15\dfrac{1}{sinA} = 8\dfrac{1}{cosA}$$
$$\sf \bf :longmapsto tanA = \dfrac{15}{8}$$

Thus, you can see using a triangle that sides are respectively, 15k, 8k, 17k
$$\sf \bf :longmapsto cosA = \dfrac{8}{17}$$
Hence , x = 17

More information:

$$\sf \color{aqua}{Trigonometry\: Table}\\ \blue{\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|} \sf \red{\angle A} & \red{\sf{0}^{ \circ} }&\red{ \sf{30}^{ \circ} }& \red{\sf{45}^{ \circ} }& \red{\sf{60}^{ \circ}} &\red{ \sf{90}^{ \circ}} \\ \hline \\ \rm \red{sin A} & \green{0} & \green{\dfrac{1}{2}}& \green{\dfrac{1}{ \sqrt{2} }} &\green{ \dfrac{ \sqrt{3}}{2} }&\green{1} \\ \hline \\ \rm \red{cos \: A} & \green{1} &\green{ \dfrac{ \sqrt{3} }{2}}&\green{ \dfrac{1}{ \sqrt{2} }} & \green{\dfrac{1}{2}} &\green{0} \\ \hline \\\rm \red{tan A}& \green{0} &\green{ \dfrac{1}{ \sqrt{3} }}&\green{1} & \green{\sqrt{3}} & \rm \green{\infty} \\ \hline \\ \rm \red{cosec A }& \rm \green{\infty} & \green{2}& \green{\sqrt{2} }&\green{ \dfrac{2}{ \sqrt{3} }}&\green{1} \\ \hline\\ \rm \red{sec A} & \green{1 }&\green{ \dfrac{2}{ \sqrt{3} }}& \green{\sqrt{2}} & \green{2} & \rm \green{\infty} \\ \hline \\ \rm \red{cot A }& \rm \green{\infty} & \green{\sqrt{3}}& \green{1} & \green{\dfrac{1}{ \sqrt{3} }} & \green{0}\end{array}}}}$$

The Mystery 1 day, 17 hours ago

17
• 3 answers

The Mystery 1 day, 2 hours ago

How 6 aren't 5? And total are 50 not 54

Its Nav Sandhu ✌✌ 1 day, 6 hours ago

6 to 50 there were 6 perfect square and total no. 54 so P (E) :- 6/54 = 3/27 = 1/9 answer

The Mystery 1 day, 16 hours ago

Perfect square number from 1 to 50 are only 5 (as 7²=49)
$$\sf \bf :\longmapsto P = \dfrac{5}{50} = \dfrac{1}{10}$$
• 0 answers
• 1 answers

Kunal Chauhan 1 day, 23 hours ago

Hi
• 2 answers

Bhavya Maheshwari 1 day, 21 hours ago

Tan theta = 3/4 then P=3k B=4k H=5k ( Pythagoras) Cos² - sin² = (4/5)² - (3/5)² = 16/25 - 9/25 = 7/25

Reena Ahirwar 2 days, 5 hours ago

Therefore we can say that when tan theta =34,cos 2 theta -sin 2 theta =725
• 3 answers

Sakshi Kumari 2 days, 4 hours ago

45×2 = 90

X-O Harsh 2 days, 16 hours ago

(45)^2=90

Aastha Lilhore 2 days, 17 hours ago

45*2 = 90
• 2 answers

Its Nav Sandhu ✌✌ 1 day, 20 hours ago

D. 2520 Its a comman and very important ques so never forget him

Prateek Aggarwal 2 days, 16 hours ago

D 2520
• 1 answers

Monarch Pathak¹³ 2 days, 18 hours ago

By using Euclid's division lemma (a=bq+r) Where A=225. B=135 Step 1 225=135×1+90 Step 2 A=135. B=90 135=90×1+45 Step 3 A=90. B=45 90=45×2+0 So our HCF of (135 and 225) is 45 Hence proved
• 2 answers

Subodh Kumar 3 days, 17 hours ago

Hi

Rohan Kandulna 3 days, 19 hours ago

Questions no 1
• 1 answers

Rohan Kandulna 3 days, 19 hours ago

Experience 7.1
• 0 answers
• 0 answers
• 2 answers

Abbhiijit Samanta 4 days, 16 hours ago

x^2-x-12
You can make any polynomial using these terms only by substituting values
• 1 answers

Deep Kevadiya 4 days, 1 hour ago

5©®0®€\$
• 4 answers

Ragini Kumari 5 days, 6 hours ago

The zeroes of the polynomial are the values of X which satisfy the equation Y= F(X)
Zeroes of the polynomial are to be determined by how many times the line touches the x-axes .

Jeba Hussain 5 days, 19 hours ago

The zeros of polynomial are the values of x which satisfy the equation y = f(x)

Dhairya Sobti 5 days, 19 hours ago

Zeroes of the polynomial are those who can make a polynomial value zero
• 2 answers

Abbhiijit Samanta 4 days, 16 hours ago

1

Dhairya Sobti 5 days, 18 hours ago

These values are deleted ☺️☺️☺️
• 3 answers

Sameer Hsngrh 4 days, 16 hours ago

Hlo

Garvit Vats 5 days, 19 hours ago

3/4

Dhairya Sobti 5 days, 19 hours ago

Cos theta = 4/5 = B/H Therefore, Tan theta = P/B= 3/4 .
• 1 answers

Harsh Gopal 6 days, 17 hours ago

Theta / 360⁰ × pi × r^2
• 1 answers

Riya Kumari 5 days, 23 hours ago

x = -4 and y = -3
• 0 answers
• 5 answers

Prince Kumar Sah 6 days, 21 hours ago

√49 = √7×7 = 7

Ashish Majhi 6 days, 23 hours ago

7

Rahaf Rehas 1 week ago

7*7 = 49 So the √49 is 7

Naman Gupta 1 week, 1 day ago

7

Akashi Gupta 1 week, 1 day ago

√49 = 7
• 1 answers
Triangle means a shape made up of three side or three straight line In triangle their are two types:- 1.sides. 2.angle SIDES:-. ANGLE:- ¹.equilateral ¹.acute ².isosceles ².obtuse ³.scalen. ³.right Similarities property:- RHS AAS SAS SSS A triangle are said to be similar when their sides are proportional and opposite angle are equal .
• 1 answers

Akashi Gupta 1 week ago

Triangle
• 1 answers

Deepti Mittal 6 days, 4 hours ago

(6,3)

## myCBSEguide

Trusted by 1 Crore+ Students

#### CBSE Test Generator

Create papers in minutes

Print with your name & Logo

Download as PDF

3 Lakhs+ Questions

Solutions Included

Based on CBSE Blueprint

Best fit for Schools & Tutors

#### Work from Home

• Work from home with us
• Create questions or review them from home

No software required, no contract to sign. Simply apply as teacher, take eligibility test and start working with us. Required desktop or laptop with internet connection