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Sia 🤖 2 weeks, 1 day ago

The sum of arithmetic progression whose first term is a and the common difference is d can be calculated using one of the following formulas: **S _{n} = n/2 (2a+(n−1)d) and S_{n} = n/2 (a_{1}+a_{n})**. The sum of AP of n natural numbers is n(n+1)/2.

Posted by Kartik Jaat 2 weeks, 1 day ago

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Sia 🤖 2 weeks, 1 day ago

x^{2} + 6x + 9 = 0.

Put x = -3 in the equation

{tex}\Rightarrow{/tex}{tex}(-3)^2 + 6(-3) + 9{/tex}

{tex}\Rightarrow{/tex} {tex}9 - 18 + 9 =0{/tex}

Hence, it is a solution of the given equation.

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