CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Have you read the question carefully?? 7.2 , qs 3) is having two parts 1) distance between two girls and is that Rashmi wanted to locate a flag exactly half between them That's gives the ans 5th line 22.5m

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Sin A + Cosa=

Posted by Manish Pathak 3 days, 14 hours ago

CBSE > Class 10 > Mathematics

1 answers

Harsh Malik 1 day, 20 hours ago

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3±6

Posted by Deepti Singh 3 days, 15 hours ago

CBSE > Class 10 > Mathematics

3 answers

Rahul Pal 3 days, 8 hours ago

3+6=9, 3-6=-3

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P.Dheeraj Kanna 3 days, 12 hours ago

3+6=9 , 6+3=9 , 3-6=-3 , 6-3=3

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Gaming 2.0 3 days, 15 hours ago

3+6=9 , 3-6= -3

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2. A ladder, leaning against a wall, makes an angle of 60⁰ with the horizontal. If the foot of the ladder is 9.5m away from the wall. The length of the ladder is ..

Posted by Absh Upadhyay 3 days, 21 hours ago

CBSE > Class 10 > Mathematics

2 answers

Shivam Gupta 3 days, 10 hours ago

Cos 60° = 1/2 Base = 9.5 1/2= base/ hypotenuse 1/2=9.5/ hypotenuse 9.5 multiply by 1/2 Length of ladder=19

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Absh Upadhyay 3 days, 21 hours ago

10m

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tree breaks due to storm and the broken part bends so that the top of the tree touches the ground making an angle 30 degree with it. The distance between the foot of the tree to the point where the top touches the ground is 8m. Find the height of the tree.

Posted by Amshu S 3 days, 22 hours ago

CBSE > Class 10 > Mathematics

1 answers

Sidak Vasu 3 days, 14 hours ago

16/root3m+8/root3=24/root3 =8root3

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. A guard, stationed at the top of a 240 m tower, observed an unidentified boat coming towards it. A clinometer or inclinometer is an instrument used for measuring angles or slopes(tilt). The guard used the clinometer to measure the angle of depression of the boat coming towards the lighthouse and found it to be 30°. (Lighthouse of Mumbai Harbour. Picture credits - Times of India Travel) Make a labelled figure on the basis of the given information and calculate the distance of the boat from the foot of the observation tower. 2 After 10 minutes, the guard observed that the boat was approaching the tower and its distance from tower is reduced by 240(root 3 - 1) m. He immediately raised the alarm. What was the new angle of depression of the boat from the top of the observation tower

Posted by Swati Dahiya 4 days, 1 hour ago

CBSE > Class 10 > Mathematics

1 answers

Kavana Tn 10 hours ago

i)let x be the distance travelled by boat Angle of depression =30 degree Tan 30°=240/x 1/root 3=240/x x=240 root 3 Therefore distance travelled by boat is 240 root 3 m. ii) now angle of depression let be theta Distance of boat is reduced by 240(root3-1)m Let new distance travelled by boat be y Difference in distance is given Earlier distance - new distance =difference i.e 240root3 - y = 240(root 3-1) We get y=240 Tan theta =opp/adjacent Tan theta=240 i.e height of tower/ 240 i.e distance travelled Tan theta=1 Tan theta = Tan 45° Therefore theta=45° Hence the new angle of depression is 45 degree https://photos.app.goo.gl/3dosPnoJ2sT1j8AF8 ( corresponding figure u can check here👆🏻)

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Make a labelled figure on the basis of the given information and calculate the distance of the boat from the foot of the observation tower. 2 After 10 minutes, the guard observed that the boat was approaching the tower and its distance from tower is reduced by 240( - 1) m. He immediately raised the alarm. What was the new angle of depression of the boat from the top of the observation tower?

Posted by Swati Dahiya 4 days, 1 hour ago

CBSE > Class 10 > Mathematics

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Two water taps together fill a tank in 17 hours. The tap with longer diameter takes 2 hours less than the tap with smaller one to fill the tank separately. Find the time in which each tap can fill the tank separately.

Posted by Manthan Srivastava 4 days, 13 hours ago

CBSE > Class 10 > Mathematics

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Two tangent TP and TQ are drawn to a circle with centre O from an external point T at P and Q. Prove that ∠PTQ=40, then find ∠OPQ

Posted by Samarth Prachande 4 days, 21 hours ago

CBSE > Class 10 > Mathematics

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Two tangent TP and TQ are drawn to a circle with centre O from an external point T at P and Q. Prove that ∠PTQ=40 ∠OPQ

Posted by Samarth Prachande 4 days, 21 hours ago

CBSE > Class 10 > Mathematics

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tan²A+cot²A+2=secA+cosec²A

Posted by Henil Patel 5 days, 21 hours ago

CBSE > Class 10 > Mathematics

1 answers

Arun😉 Saini 5 days, 3 hours ago

bhai term 2 me trigonometry nahi aa rahi ....

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A metric progression

Posted by Priyanshu Kumar Kumar Sagar 6 days, 1 hour ago

CBSE > Class 10 > Mathematics

1 answers

Dolly Rajput 4 days, 13 hours ago

Arithmetic progression

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Exercise 5.4 solution

Posted by Priyanshu Kumar Kumar Sagar 6 days, 1 hour ago

CBSE > Class 10 > Mathematics

1 answers

Mohit Gemini Mohit Gemini 4 days, 13 hours ago

Search from Google bro

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In the given figure, BO and CO are bisector of /B and /C respectively . If /A = 50 , then /BOC=?

Posted by Sachin Singh 6 days, 10 hours ago

CBSE > Class 10 > Mathematics

1 answers

Isha Kumari Alisha 5 days, 15 hours ago

BOC=115

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In the given figure O is the centre of the circle of radius 5 cm. T is a point such that OT = 13 cm and OT intersect the circle at E. If AB is the tangent to the circle at E , find the length of AB.

Posted by N C 6 days, 14 hours ago

CBSE > Class 10 > Mathematics

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Budding

Posted by Prachi 2005 1 week, 1 day ago

CBSE > Class 10 > Mathematics

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Tamanna Sharma 1 week ago

A small part of body of parent organism grow out as a bud which became new organism.example hydra

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12 solid spheres of same size are made by melting a solid metallic cylinder of base radius 1cm and height 1/3 of 48cm. Find the radius of each sphere

Posted by Anmolpreet Kaur 1 week, 1 day ago

CBSE > Class 10 > Mathematics

1 answers

Aditi Patel 6 days, 21 hours ago

R= 1

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4x2-2(a2+b2)x+a2b2=0

Posted by Gssydu Ogkvkg 1 week, 1 day ago

CBSE > Class 10 > Mathematics

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2 cubes each of volume 64cm^3 are joined end to end . Find the surface area of the resulting cuboid

Posted by Rimjhim Rai 1 week, 3 days ago

CBSE > Class 10 > Mathematics

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Find the roots of equations x²-3x-10=0

Posted by 44Uday Shinde10E 1 week, 3 days ago

CBSE > Class 10 > Mathematics

2 answers

Chhavi Soni 1 week ago

-2 and 5

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Jeet Dutta 1 week, 3 days ago

x² - 3x - 10 = 0 => x² - (5 - 2)x - 10 = 0 => x² - 5x + 2x - 10 = 0 => x(x - 5) + 2(x - 5) = 0 => (x - 5)(x + 2) = 0 x - 5 = 0 or x + 2 = 0 => x = 5 or => x = - 2 Roots are 5, - 2

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Two chords AB and CD of lengths 5 cm and 11 cm respectively of a circle are parallel to each other and are on opposite sides of its centre. If the distance between AB and CD is 6 cm, find the radius of the circle.

Posted by Lakshay Verma 1 week, 5 days ago

CBSE > Class 10 > Mathematics

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Ex 4.2 Q1

Posted by Vinay Sawlecha 1 week, 6 days ago

CBSE > Class 10 > Mathematics

2 answers

Rahul Yadav Rahul Yadav 1 week, 5 days ago

Factorisation

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Rahul Yadav Rahul Yadav 1 week, 5 days ago

x=-5,2

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Marks obtained out of 50 by 100 to student in physics test are given in the frequency table below Marks : 15 20 22 24 25 30 33 38 45 Frequency :5 8 11 20 23 18 13 3 1 Find the mean

Posted by Vivek Rana 2 weeks ago

CBSE > Class 10 > Mathematics

1 answers

Khushi...🤗🤗 Sharma...❤❤ 1 week, 6 days ago

Answer:- Marks (x) Frequency (f) fx 155 75 208 160 2211 242 2420 480 2523575 3018 540 3313 429 283 84 45145 Σf=5+8+11+20+23+18+13+3+1 =102 Σfx=75+160+242+480+575+540+429+84+45 =2630Average mark(xˉ)=ΣfΣfx=1022630=25.78

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derive the formula for the sum of first n terms of ap,whose first term is a and the common difference is d.

Posted by Tanuja Chavan 2 weeks, 1 day ago

CBSE > Class 10 > Mathematics

2 answers

Sia 🤖 2 weeks, 1 day ago

The sum of arithmetic progression whose first term is a and the common difference is d can be calculated using one of the following formulas: S_n = n/2 (2a+(n−1)d) and S_n = n/2 (a₁+a_n). The sum of AP of n natural numbers is n(n+1)/2.

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Kishan Kishan Nm 1 week, 5 days ago

999

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Show that x = -3 is the solution of the equation x2 +6x +9 = 0.

Posted by Kartik Jaat 2 weeks, 1 day ago

CBSE > Class 10 > Mathematics

1 answers

Sia 🤖 2 weeks, 1 day ago

x² + 6x + 9 = 0.

Put x = -3 in the equation
{tex}\Rightarrow{/tex}{tex}(-3)^2 + 6(-3) + 9{/tex}
{tex}\Rightarrow{/tex} {tex}9 - 18 + 9 =0{/tex}
Hence, it is a solution of the given equation.

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what is culminative frequency?

Posted by Avnish Gawande 2 weeks, 4 days ago

CBSE > Class 10 > Mathematics