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Ask QuestionPosted by Aaradhana Kumar an hour ago

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Posted by Vaishnavi Belapurkar 3 hours ago

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Posted by Ankit Kumar 4 hours ago

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Gaurav Seth 3 hours ago

Speed upstream= (x - y) km/h

Speed downstream= (x + y) km/h

_{}

On subtracting, we get,

_{}

_{On solving, we get,}

_{}

_{}Speed of boat in still water = 8 km/h

And, Speed of stream = 3 km/h

Posted by Jaya Shree Meenakshi 4 hours ago

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Yogita Ingle 3 hours ago

Euclid division lemma:-

a=bq+r

First find the HCF of 693 and 567,

693=567(1)+126

567=126(4)+63

126=63(2)+0

HCF of 693 and 567 is 63.

Now find the HCF of 63 and 441,

441=63(7)+0

The HCF of 63 and 441 is 63.

Therefore, the HCF of 441,567 and 693 is 63.

Posted by Ankita Chhabra 4 hours ago

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Posted by Anitha Joseph 5 hours ago

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Gaurav Seth 4 hours ago

Q: Use Euclid's division lemma to show that the cube of any positive integer is of the form 9m,9m+1 or 9m+8

Let *x *be any positive integer. Then, it is of the form 3*q *or, 3*q *+ 1 or, 3*q *+ 2.

So, we have the following cases :

**Case I : **When *x *= 3*q*.

then, *x*^{3} = (3*q*)^{3} = 27*q*^{3} = 9 (3*q*^{3}) = 9*m*, where *m *= 3*q*^{3}.

**Case II : **When *x *= 3*q *+ 1

then, *x*^{3} = (3*q *+ 1)^{3}

= 27*q*^{3} + 27*q*^{2} + 9*q *+ 1

= 9 *q *(3*q*^{2} + 3*q *+ 1) + 1

= 9*m *+ 1, where *m *= *q *(3*q*^{2} + 3*q *+ 1)

**Case III. **When *x *= 3*q *+ 2

then, *x*^{3} = (3*q *+ 2)^{3}

= 27 *q*^{3} + 54*q*^{2} + 36*q *+ 8

= 9*q *(3*q*^{2} + 6*q *+ 4) + 8

= 9 *m *+ 8, where *m *= *q *(3*q*^{2} + 6*q *+ 4)

Hence, *x*^{3 }is either of the form 9 *m *or 9 *m *+ 1 or, 9 *m *+ 8.

Posted by Jo Hosakke Kar Lo 😁😁🤣🤣✌️ 7 hours ago

- 1 answers

Gaurav Seth 6 hours ago

**Answer:**

**Step-by-step explanation:**

we have **to find the 5 irrational number which are lying between 4 and 5 in radical form**

**Irrational numbers** are those real numbers that cannot be written as a simple fraction. **These are non-terminating and non-repeating.**

**All the above five numbers are non-terminating and non-repeating.**

Posted by Jo Hosakke Kar Lo 😁😁🤣🤣✌️ 7 hours ago

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Gaurav Seth 6 hours ago

Total pens=1001

Total pencils=910

we need to find maximum no.of students among whom 1001 pens and 910 pencils can be distributed in such a way that each students get same no.of pens and pencils.

Then we need to find HCF of 1001 and 910

Prime factorization of,

1001=7×11×13

910=2×5×7×13

HCF=product of commom prime factor of least power

HCF=7×13=91

Here HCF of 1001 and 910 is 91.

Hence among 91 students 1001 pens and 910 pencils can be distributed such that each student get same no.of pens and pencils.

Posted by Høñéy Khäñ 8 hours ago

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Posted by Krishan Kadian Kadian 11 hours ago

- 2 answers

Yogita Ingle 11 hours ago

2x^{2} -5x + 3

= 2x^{2} - 2x -3 x + 3

= 2x(x - 1) - 3 ( x - 1)

= (x -1) (2x - 3)

Posted by Yogesh Meena 12 hours ago

- 1 answers

Gaurav Seth 12 hours ago

Question : Find the series if an=9−5n

Given

an=9−5n

a1=9−5=4

a2=9−10=−1

a3=9−15=−6

∴ The series is 4,−1,−6,−11....

Posted by Rani Jijo 12 hours ago

- 2 answers

Gaurav Seth 12 hours ago

**Let’s assume the two numbers be x and y. And also assume that x is greater than or equal to y. **

**So as per the question, we can write the sum of the two numbers as **

x + y = 1000 ……….. (i)

Again it’s given that, the difference between the squares of the two numbers, thus writing it

x^{2} – y^{2} = 256000

⇒ (x + y) (x – y) = 256000

⇒ 1000(x - y) = 256000

⇒ x – y = 256000/1000

⇒ x – y = 256 ………….. (ii)

**By solving (i) and (ii), we can find the two numbers **

**On adding the equations (i) and (ii), we get; **

(x + y) + (x - y) = 1000 + 256

⇒ x + y + x – y =1256

⇒ 2x = 1256

⇒ x = 1256/ 2

⇒ x = 628

**Now, putting the value of x in equation (i), we get **

628 + y =1000

⇒ y = 1000 – 628

⇒ y = 372

**Hence, the two required numbers are 628 and 372.**

Posted by Apurv Sharma 12 hours ago

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Posted by Usha Motwani 15 hours ago

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Arpita Singh 3 hours ago

All the counting numbers are called natural number. It os denoted by 'N'
Examples-1,2,3,4,.....

Ramesh Yadav 13 hours ago

Counting number are called natural number . These numbers are denoi by N=(1.2.3....)

Posted by Pankaj Choudhary 17 hours ago

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Posted by R_C_Y_@ 💔💔 19 hours ago

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Posted by R_C_Y_@ 💔💔 19 hours ago

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Attitude Girl 👑 18 hours ago

Oh sry sis.....I thought u r in 10th nd in that way I talked with u....but I will again tell u the same thing not to use this app for chatting coz this site has been made for studies disscussions.....Nd I am not greedy at all but ya I am somewhat aggressive so in that way I talked with u because I used to use this app for freshing my mind but because of u people I was not because now Gm,gn,hello,hi these types of msg r more in this app STUDY APP but it shuld hv more question but no...there r very less u know less bhi nhi 2or3...because of which I am fed up....So mera anger aap logo pr uttar gya.....ND U TOLD U R BIGGER THAN ME SO I RESPECT ELDERS VERY SRY IF U FELT BAD BEACUSE OF ME BUT plzz dont type these types of msgs......HOPE U UNDERSTOOD🤗

Posted by Sanjana Singh 1 day, 2 hours ago

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Gagandeep Singh 1 day, 4 hours ago

Pls tell the question
Actually i am not having Rs Aggarwal

Posted by Cute Sakshi 1 day, 6 hours ago

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Posted by Heer Shah 1 day, 7 hours ago

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Yogita Ingle 1 day, 6 hours ago

A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared. The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable. One absolute rule is that the first constant "a" cannot be a zero.

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Aditya Raj an hour ago

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