Ask questions which are clear, concise and easy to understand.

Ask QuestionPosted by Saniya Gouri 1 week ago

- 0 answers

ANSWER

Posted by Nerajaa A.V 1 week ago

- 2 answers

Posted by Nerajaa A.V 1 week ago

- 0 answers

Posted by Nerajaa A.V 1 week ago

- 0 answers

Posted by Nerajaa A.V 1 week ago

- 0 answers

Posted by Nerajaa A.V 1 week ago

- 1 answers

Posted by Divyansh Kumar 1 week, 1 day ago

- 2 answers

Khushi Kulshrestha 1 week ago

Means 8 square is 64 and 6 square is 36 add both . 100 will come take the square root of it , the ans is 10

Khushi Kulshrestha 1 week, 1 day ago

U can use a trick here.which is that take the square root of squares of radii.

Posted by Arshdeep Kataria 1 week, 1 day ago

- 2 answers

Kaviya Sudhan 1 week, 1 day ago

Hence any integer is of one of the form 2q, 2q+1. Hence n(n+1) = 2((2q+1)(q+1)), which is even. Hence n(n+1) is always even. Hence the product of two consecutive integers is always divisible by 2.

Posted by The -Bandits 1 week ago

- 1 answers

Sia 🤖 1 week ago

1.A cut out of a geometrical figure such as a triangle is made and placed on a rectangular sheet of paper marked with X and Y-axis.

2.The co-ordinates of the vertices of the triangle and its centroid are noted.

3.The triangular cut out is displaced(along x-axis, along y-axis or along any other direction.)

4.The new co-ordinates of the vertices and the centroid are noted again.

5.The procedure is repeated, this time by rotating the triangle as well as displacing it. The new co-ordinate of vertices and centroid are noted again. Displacement and rotation of a geometrical figure.

6.Using the distance formula, distance between the vertices of the triangle are obtained for the triangle in original position and in various displaced and noted positions.

7.Using the new coordinates of the vertices and the centroids, students will obtain the ratio in which the centroid divides the medians for various displaced and rotated positions of the triangles.

Posted by Dev Singh 1 week, 1 day ago

- 1 answers

Posted by Arsh Deep Kaur 1 week, 1 day ago

- 1 answers

Posted by Gurubasavaraj Angadi 1 week, 1 day ago

- 0 answers

Posted by Sameer Sharma 1 week, 2 days ago

- 1 answers

Divyanshi Saxena 1 week, 2 days ago

Let α,β be the other zeros of the given polynomial x 3 +ax 2 +bx +c
Sum of the zeros =
coefficient of x
3
−coefficient of x
2
⇒−1+α+β=
1
−a
=−a
⇒α+β=−a+1 (i)
Again,
(−1)α+αβ+(−1)β=
coefficient of x
3
−coefficient of x
⇒−α+αβ−β=
1
b
=αβ=b+α+β
α+β=−a+1 , from (i))
=b−a+1

Posted by Towfic Islam 1 week, 2 days ago

- 2 answers

Posted by Prashanth .N 1 week, 2 days ago

- 1 answers

Posted by Dhanraj Pandey 1 week, 2 days ago

- 1 answers

Sumit Yadav 1 week, 2 days ago

p(x) = 16x2 - 25
= 4x2 - 52
= ( 4x - 5 ) ( 4x + 5 )
4x - 5 = 0
4x = 5
x = 5 / 4
or alpha = 5 / 4
4x + 5 = 0
4x = -5
x = -5 / 4
or beta = -5/ 4
!st relation,
ax2 + bx +c
a = 16 , b = 0 and c = -25
alpha + beta = - b / a
LHS = RHS
5 / 4+ - 5 / 4 = - 0 / 16
0 = 0
L.H.S = R.H.S
2nd relationship
Alpha x beta = c / a
LHS = RHS
5 / 4 x - 5/ 4 = - 25 / 16
-25 / 16
L.H.S = R.H.S

Posted by Sankar Sss 1 week, 3 days ago

- 1 answers

Sumit Yadav 1 week, 2 days ago

(v) (cos A – sin A + 1) / (cos A + sin A – 1) = cosec A + cot A using the identity cosec2A = 1 + cot2A
Solving LHS
Multiplying numerator and denominator by (cot A – 1 + cosec A)
= (cot2A + 1 + cosec2A – 2*cot A – 2*cosec A + 2*cot A*cosec A) / (cot2A – (1 + cosec2A – 2*cosec A))
= (2*cosec2A – 2*cot A – 2*cosec A + 2*cot A*cosec A) / (cot2A – 1 – cosec2A + 2*cosec A)
= (2* cosec A *(cosec A + cot A) – 2*(cosec A + cot A)) / (cot2A – 1 – cosec2A + 2*cosec A)
= ((cosec A + cot A) * (2*cosec A – 2 )) / (2*cosec A – 2)
= cosec A + cot A = RHS
Hence Proved

Posted by Kanchan Kumawat 1 week, 3 days ago

- 2 answers

Chahak Nashine 1 week, 3 days ago

Q1 (i) similar
(ii) similar
(iii) equilateral
Q2 (i) 2 equilateral triangles of length 2&4 cms.
2 squares of length 1&2
cms.
(ii) trapezium & square
Triangle & rectriangle.
Q3 They are not similar as their corresponding sides are proportional i.e 1:2 but their corresponding angles are not equal.

Posted by Aryan Pradhan 1 week, 3 days ago

- 0 answers

Posted by Manish Kumar 1 week, 3 days ago

- 1 answers

Sia 🤖 1 week, 3 days ago

Let the given number when divided by 143 give q as quotient and 31 as remainder. Then, number = 143q + 31 { 13×11q+13×2+5)=13×(11q+2)+5

So , the same number when divided by 13 gives 5 as remiander.

Posted by Sumit Kumar 1 week, 4 days ago

- 1 answers

Posted by Æshìsh Kùmàr 1 week, 4 days ago

- 1 answers

Kunal Yadav 1 week, 3 days ago

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. **If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section.** Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

**Few rules to keep homework help section safe, clean and informative. **

Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

- Don't post personal information, mobile numbers and other details.
- Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
- Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
- Ask specific question which are clear and concise.

Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

Posted by Shobhit Baghel 1 week, 4 days ago

- 3 answers

Create papers in minutes

Print with your name & Logo

Download as PDF

3 Lakhs+ Questions

Solutions Included

Based on CBSE Blueprint

Best fit for Schools & Tutors

- Work from home with us
- Create questions or review them from home

No software required, no contract to sign. Simply apply as teacher, take eligibility test and start working with us. Required desktop or laptop with internet connection