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Trupti Toke 20 hours ago

One

Pushprajsinh Rathod 5 days, 5 hours ago

1

Sia 🤖 1 week ago

Means 8 square is 64 and 6 square is 36 add both . 100 will come take the square root of it , the ans is 10

Khushi Kulshrestha 1 week, 1 day ago

U can use a trick here.which is that take the square root of squares of radii.

Sia 🤖 1 week ago

{tex}\frac{17}{90}{/tex}

Arshdeep Kataria 6 days, 12 hours ago

Thankyou

Kaviya Sudhan 1 week, 1 day ago

Hence any integer is of one of the form 2q, 2q+1. Hence n(n+1) = 2((2q+1)(q+1)), which is even. Hence n(n+1) is always even. Hence the product of two consecutive integers is always divisible by 2.

Advaith Krishna 1 week, 1 day ago

A)√2x2-3√3x+√6

Sia 🤖 1 week ago

1.A cut out of a geometrical figure such as a triangle is made and placed on a rectangular sheet of paper marked with X and Y-axis.

2.The co-ordinates of the vertices of the triangle and its centroid are noted.

3.The triangular cut out is displaced(along x-axis, along y-axis or along any other direction.)

4.The new co-ordinates of the vertices and the centroid are noted again.

5.The procedure is repeated, this time by rotating the triangle as well as displacing it. The new co-ordinate of vertices and centroid are noted again. Displacement and rotation of a geometrical figure.

6.Using the distance formula, distance between the vertices of the triangle are obtained for the triangle in original position and in various displaced and noted positions.

7.Using the new coordinates of the vertices and the centroids, students will obtain the ratio in which the centroid divides the medians for various displaced and rotated positions of the triangles.

Rajat Roshan 1 week, 1 day ago

2:1

Vansh Kumawat 1 week, 1 day ago

x=4 , y=3 by substitution method

Vallabha B. M. 1 week, 2 days ago

Linear equation formulas

Divyanshi Saxena 1 week, 2 days ago

Let α,β be the other zeros of the given polynomial x 3 +ax 2 +bx +c Sum of the zeros = coefficient of x 3 −coefficient of x 2 ​ ⇒−1+α+β= 1 −a ​ =−a ⇒α+β=−a+1 (i) Again, (−1)α+αβ+(−1)β= coefficient of x 3 −coefficient of x ​ ⇒−α+αβ−β= 1 b ​ =αβ=b+α+β α+β=−a+1 , from (i)) =b−a+1

Shayam Sahani 6 days, 15 hours ago

Nitesh Meena 1 week, 2 days ago

Bhio

Prashanth .N 1 week, 2 days ago

2 I think

Sumit Yadav 1 week, 2 days ago

p(x) = 16x2 - 25 = 4x2 - 52 = ( 4x - 5 ) ( 4x + 5 ) 4x - 5 = 0 4x = 5 x = 5 / 4 or alpha = 5 / 4 4x + 5 = 0 4x = -5 x = -5 / 4 or beta = -5/ 4 !st relation, ax2 + bx +c a = 16 , b = 0 and c = -25 alpha + beta = - b / a LHS = RHS 5 / 4+ - 5 / 4 = - 0 / 16 0 = 0 L.H.S = R.H.S 2nd relationship Alpha x beta = c / a LHS = RHS 5 / 4 x - 5/ 4 = - 25 / 16 -25 / 16 L.H.S = R.H.S

Sumit Yadav 1 week, 2 days ago

(v) (cos A – sin A + 1) / (cos A + sin A – 1) = cosec A + cot A using the identity cosec2A = 1 + cot2A Solving LHS Multiplying numerator and denominator by (cot A – 1 + cosec A) = (cot2A + 1 + cosec2A – 2*cot A – 2*cosec A + 2*cot A*cosec A) / (cot2A – (1 + cosec2A – 2*cosec A)) = (2*cosec2A – 2*cot A – 2*cosec A + 2*cot A*cosec A) / (cot2A – 1 – cosec2A + 2*cosec A)  = (2* cosec A *(cosec A + cot A) – 2*(cosec A + cot A)) / (cot2A – 1 – cosec2A + 2*cosec A) = ((cosec A + cot A) * (2*cosec A – 2 )) / (2*cosec A – 2)  = cosec A + cot A = RHS Hence Proved

Khushi Kulshrestha 1 week, 3 days ago

Chahak Nashine 1 week, 3 days ago

Q1 (i) similar (ii) similar (iii) equilateral Q2 (i) 2 equilateral triangles of length 2&4 cms. 2 squares of length 1&2 cms. (ii) trapezium & square Triangle & rectriangle. Q3 They are not similar as their corresponding sides are proportional i.e 1:2 but their corresponding angles are not equal.

Agrim Mishra 1 week, 3 days ago

Lin

Sia 🤖 1 week, 3 days ago

Let the given number when divided by 143 give q as quotient and 31 as remainder. Then, number = 143q + 31 { 13×11q+13×2+5)=13×(11q+2)+5
So , the same number when divided by 13 gives 5 as remiander.

Prerak Soni 1 week, 4 days ago

5x-4y+8=0 7x+6y-9=0

Sunita Ramesh 1 week, 4 days ago

10

Rohan Kumar Thakur 1 week, 4 days ago

SecA -1+SecA+1=SecA+SecA=2SecA

Kunal Yadav 1 week, 3 days ago

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C.J.Ramiya Krishna 1 week, 4 days ago

Consistent

Kunal Yadav 1 week, 4 days ago

consistent

Mishty Panchal 1 week, 4 days ago

Consistent ## myCBSEguide

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