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Yogita Ingle 8 hours ago
{tex}\begin{array}{l}\;4\surd3+3\surd48-\;\frac52\surd\frac43\\=\;4\sqrt3\;+\;3\sqrt{16\times3}\;-\frac52\sqrt{\frac{4\times3}{3\times3}}\\=4\sqrt3\;+12\sqrt3\;\;-\;\frac{5\times2}{2\times3}\;\sqrt3\\=4\sqrt3\;+12\sqrt3\;\;-\;\frac53\;\sqrt3\\\end{array}{/tex}
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Yogita Ingle 7 hours ago
{tex}\frac{ \sqrt{2} - 1}{ \sqrt{2} + 1} = a + b \sqrt{2} \\ \frac{ \sqrt{2} - 1 }{ \sqrt{2} + 1} \times \frac{ \sqrt{2 } - 1}{ \sqrt{2 } - 1} = a + b \sqrt{2} \\ \frac{ {( \sqrt{2} - 1) }^{2} }{2 - 1} = a + b \sqrt{2} \\ 2 + 1 - 2 \sqrt{2} = a + b \sqrt{2} \\ 3 - 2 \sqrt{2} = a + b \sqrt{2} \\ a = 3 \: and \: b = - 2{/tex}
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Amisha Pandey 23 hours ago
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