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Gaurav Seth 2 hours ago

Radius of circle = 50/2 = 25 cm

 

perpendicular distance = 24 cm

 

 

 

Therefore, By Pythagoras theorem:

 

Hypotenuse² = Base² + Perpendicular ²

 

25² = Base² + 24²

 

Base² = 625 - 576

 

Base² = 49

 

Base = 7

 

 

Chord = 2 × Base

 

Chord = 2 × 7

 

Answer: 14 cm

  • 1 answers

Devashish Kumar 18 hours ago

Formula for the probability of A and B (independent events): p(A and B) = p(A) * p(B). If the probability of one event doesn't affect the other, you have an independent event. All you do is multiply the probability of one by the probability of another.
  • 1 answers

Home Dias 1 day, 3 hours ago

What do u want exactly?
  • 5 answers

Niranjan R 1 day, 17 hours ago

0

Arpit Agnihotri 1 day, 18 hours ago

0

Arya Shinde 1 day, 18 hours ago

0

Shreya Rana 1 day, 18 hours ago

0

Aruba Shah❤ 1 day, 19 hours ago

0
  • 1 answers

Sakshi Sharma 1 day, 19 hours ago

Given data ko alag alag side likh ke eg- 2x-ab = 2z - ab
  • 3 answers

Devesh More 1 day, 3 hours ago

273

Kishan Kishan 1 day, 22 hours ago

X+1-x

Kishan Kishan 1 day, 22 hours ago

(13)21
  • 3 answers

Devesh More 1 day, 3 hours ago

Side and side

Yogita Ingle 1 day, 22 hours ago

SSS (Side-Side-Side)

If all the three sides of one triangle are equivalent to the corresponding three sides of the second triangle, then the two triangles are said to be congruent by SSS rule.

In the diagrams below, if AB = RPBC = PQ and CA = QR, then triangle ABC is congruent to triangle RPQ.

M K Tobaiy 1 day, 22 hours ago

If three sides of one triangle are equal to the three sides of another triangle,then the two triangle are congruent
  • 5 answers

Manthan Patel 22 hours ago

1

Tamana Yadav 1 day ago

B

Parth Awasthi 1 day, 20 hours ago

1

Shrutee Kumari 1 day, 21 hours ago

in ax^2+bx+c ; coefficient of x is b

Dhanush M 1 day, 22 hours ago

,a
  • 2 answers

Mithilesh Kumar 1 day, 23 hours ago

It is given that, ∠Q = 2∠PRQ. In ΔPQR, ∠PQR + ∠PRQ + ∠RPQ = 180° ⇒ 2∠PRQ + ∠PRQ + 90° = 180° ⇒ 3∠PRQ = 180° − 90° = 90° ⇒ ∠PRQ = 90°/30=30° … (1) ∴ ∠PQR = 2 × 30° = 60° … (2) Now, extending QP to S such that QP = PS, and joining RS. P /|\ / | \ / | \ / | \ / | \ / | \ / | \ / | \ / | 90° \ /______ |__________\ S Q R In ΔRPQ and ΔRPS: RP = RP (Common) ∠RPQ = ∠RPS = 90° PQ = PS (by construction) ∴ ΔRPQ ≅ ΔRPS (by SAS congruence rule) ⇒ RQ = RS and ∠PRQ = ∠PRS (CPCT) Now, ∠SRQ = ∠PRQ + ∠PRS = 2∠PRQ = 2 × 30° = 60° [from (1)] By CPCT, we obtain ∠PQR = ∠PSR ∴ ∠PSR = 60° [from (2)] Therefore, ΔQRS is an equilateral triangle. ⇒ QR = RS = SP = 10 cm ∴ SP = PQ = 10cm/2=5cm On applying Pythagoras theorem to ΔPQR, we obtain RP2 + PQ2 = QR2 ⇒ RP2 + (5 cm)2 = (10 cm)2 ⇒ RP2 + 25 cm2 = 100 cm2 ⇒ RP2 = 75 cm2 ⇒ RP =5√3cm ∴ Perimeter of ΔPQR = RP + PQ + QR =(5√3+5+10)cm = (5 × 1.73 + 15) cm = 23.65 cm Thus, the perimeter of ΔPQR is 23.65 cm. The correct answer is C.

Rohit Gautam 2 days ago

Nahi aata muje
  • 1 answers

Gaurav Seth 2 days, 1 hour ago

Given :

 

In a triangle ABC :

 

∠ A -  ∠ B = 33

 

∠ B  -  ∠ C = 18

 

We have find values of all angle :

 

We know sum of all interior angle of triangle is 180 .

 

∠ A + ∠ B + ∠ C = 180 .. ( ii )

 

We have :

 

∠ A -  ∠ B = 33

 

∠ B  -  ∠ C = 18

 

Rewrite as :

 

∠ A  = 33 + ∠ B

 

∠ C = ∠ B - 18

 

Now putting

 

33 + ∠ B + ∠ B + ∠ B - 18 = 180

 

3 ∠ B + 15 = 180

 

3 ∠ B = 165

 

∠ B = 55

 

Putting values of B in :

 

∠ A -  ∠ B = 33

 

∠ B  -  ∠ C = 18

 

∠ A = 88

 

∠ C = 37 .

 

Answer:

 

∠ A = 88

 

∠ B = 55

 

∠ C = 37 .

  • 1 answers

Gaurav Seth 2 days, 2 hours ago

Prime factorization is the decomposition of a composite number into a product of prime numbers.

Prime factorization of 72: 23 × 32

Prime factorization of 800: 25 × 52

Prime factorization of 18: 2 × 32

 

  • 1 answers

Gaurav Seth 2 days, 4 hours ago

Trapezium:

  1. Like other quadrilaterals, the sum of all the four angles of the trapezium is equal to 360°
  2. A trapezium has two parallel sides and two non-parallel sides
  3. The diagonals of regular trapezium bisect each other
  4. The length of the mid-segment is equal to half the sum of the parallel bases, in a trapezium
  5. Two pairs of adjacent angles of a trapezium formed between the parallel sides and one of the non-parallel side, add up to 180 degrees.

Rhombus:

  • All sides of the rhombus are equal.
  • The opposite sides of a rhombus are parallel.
  • Opposite angles of a rhombus are equal.
  • In a rhombus, diagonals bisect each other at right angles.
  • Diagonals bisect the angles of a rhombus.

 

Parallelogram:

  • The opposite sides are congruent.
  • The opposite angles are congruent.
  • The consecutive angles are supplementary.
  • If anyone of the angles is a right angle, then all the other angles will be the right angle.
  • The two diagonals bisect each other.
  • Each diagonal bisects the parallelogram into two congruent triangles.
  • 3 answers

Abhinandan Dubey 2 days, 4 hours ago

Some lessons are very difficult

Palak Pandey 2 days, 5 hours ago

Yeah average but I think in our textbook 3 chapters are too bouring and difficult also quadrilateral , parellogram and circle😂😂😂😂😂

Kanishka Chauhan 2 days, 5 hours ago

Average
  • 2 answers

Kishan Kishan 1 day, 22 hours ago

(13)21

Siddhi Karnani 2 days, 12 hours ago

3x(2x³+3x²) -2(2x³+3x²) (6x⁴+9x³) - (-4x³-6x²) 6x⁴+9x³+4x³+6x² 6x⁴+13x³+6x²
  • 0 answers

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