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Ask QuestionPosted by Manish Jevaliya 4 minutes ago

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Posted by Harpreet Kaur an hour ago

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Posted by Shubham Chopra 2 hours ago

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Posted by Aditya Kumar 3 hours ago

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Posted by Panu Sahu 3 hours ago

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Gaurav Seth 2 hours ago

Radius of circle = 50/2 = 25 cm

perpendicular distance = 24 cm

Therefore, By Pythagoras theorem:

Hypotenuse² = Base² + Perpendicular ²

25² = Base² + 24²

Base² = 625 - 576

Base² = 49

Base = 7

Chord = 2 × Base

Chord = 2 × 7

Posted by Jashanpreet Singh 3 hours ago

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Posted by Sujal Tushir 5 hours ago

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Posted by Mangaiha Zongaihawma 16 hours ago

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Posted by Pragati Kesarwani 17 hours ago

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Posted by Manya Manjunatha 19 hours ago

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Devashish Kumar 18 hours ago

Formula for the probability of A and B (independent events): p(A and B) = p(A) * p(B). If the probability of one event doesn't affect the other, you have an independent event. All you do is multiply the probability of one by the probability of another.

Posted by Manthan Patel 22 hours ago

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Posted by Aliya Irshad 1 day, 19 hours ago

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Posted by Arun Jii 1 day, 19 hours ago

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Posted by Aryan Raheja 1 day, 21 hours ago

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Sakshi Sharma 1 day, 19 hours ago

Given data ko alag alag side likh ke eg-
2x-ab = 2z - ab

Posted by Kishan Kishan 1 day, 22 hours ago

- 3 answers

Posted by Dhanush M 1 day, 22 hours ago

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Yogita Ingle 1 day, 22 hours ago

If all the three sides of one triangle are equivalent to the corresponding three sides of the second triangle, then the two triangles are said to be congruent by SSS rule.

In the diagrams below, if *AB* = *RP*, *BC* = *PQ *and* CA = QR, *then triangle *ABC* is congruent to triangle *RPQ*.

M K Tobaiy 1 day, 22 hours ago

If three sides of one triangle are equal to the three sides of another triangle,then the two triangle are congruent

Posted by Simran Rani 1 day, 23 hours ago

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Posted by Bhumi Kumari 2 days ago

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Posted by Mithilesh Kumar 1 day, 23 hours ago

- 2 answers

Mithilesh Kumar 1 day, 23 hours ago

It is given that, ∠Q = 2∠PRQ.
In ΔPQR, ∠PQR + ∠PRQ + ∠RPQ = 180°
⇒ 2∠PRQ + ∠PRQ + 90° = 180°
⇒ 3∠PRQ = 180° − 90° = 90°
⇒ ∠PRQ = 90°/30=30° … (1)
∴ ∠PQR = 2 × 30° = 60° … (2)
Now, extending QP to S such that QP = PS, and joining RS.
P
/|\
/ | \
/ | \
/ | \
/ | \
/ | \
/ | \
/ | \
/ | 90° \
/______ |__________\
S Q R
In ΔRPQ and ΔRPS:
RP = RP (Common)
∠RPQ = ∠RPS = 90°
PQ = PS (by construction)
∴ ΔRPQ ≅ ΔRPS (by SAS congruence rule)
⇒ RQ = RS and ∠PRQ = ∠PRS (CPCT)
Now, ∠SRQ = ∠PRQ + ∠PRS = 2∠PRQ = 2 × 30° = 60° [from (1)]
By CPCT, we obtain
∠PQR = ∠PSR
∴ ∠PSR = 60° [from (2)]
Therefore, ΔQRS is an equilateral triangle.
⇒ QR = RS = SP = 10 cm
∴ SP = PQ = 10cm/2=5cm
On applying Pythagoras theorem to ΔPQR, we obtain
RP2 + PQ2 = QR2
⇒ RP2 + (5 cm)2 = (10 cm)2
⇒ RP2 + 25 cm2 = 100 cm2
⇒ RP2 = 75 cm2
⇒ RP =5√3cm
∴ Perimeter of ΔPQR = RP + PQ + QR
=(5√3+5+10)cm
= (5 × 1.73 + 15) cm
= 23.65 cm
Thus, the perimeter of ΔPQR is 23.65 cm.
The correct answer is C.

Posted by Varsha Kanwae 2 days, 1 hour ago

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Posted by K.Solaiyappan K.Solaiyappan 2 days, 1 hour ago

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Gaurav Seth 2 days, 1 hour ago

Given :

In a triangle ABC :

∠ A - ∠ B = 33

∠ B - ∠ C = 18

We have find values of all angle :

We know sum of all interior angle of triangle is 180 .

∠ A + ∠ B + ∠ C = 180 .. ( ii )

We have :

∠ A - ∠ B = 33

∠ B - ∠ C = 18

Rewrite as :

∠ A = 33 + ∠ B

∠ C = ∠ B - 18

Now putting

33 + ∠ B + ∠ B + ∠ B - 18 = 180

3 ∠ B + 15 = 180

3 ∠ B = 165

∠ B = 55

Putting values of B in :

∠ A - ∠ B = 33

∠ B - ∠ C = 18

∠ A = 88

∠ C = 37 .

∠ A = 88

∠ B = 55

∠ C = 37 .

Posted by Anshika Kumari 2 days, 4 hours ago

- 1 answers

Gaurav Seth 2 days, 2 hours ago

Prime factorization is the decomposition of a composite number into a product of prime numbers.

Prime factorization of 72: 2^{3} × 3^{2}

Prime factorization of 800: 2^{5} × 5^{2}

Prime factorization of 18: 2 × 3^{2}

Posted by My Cbse Guide 😊😊 2 days, 5 hours ago

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Gaurav Seth 2 days, 4 hours ago

Trapezium:

- Like other quadrilaterals, the sum of all the four angles of the trapezium is equal to 360°
- A trapezium has two parallel sides and two non-parallel sides
- The diagonals of regular trapezium bisect each other
- The length of the mid-segment is equal to half the sum of the parallel bases, in a trapezium
- Two pairs of adjacent angles of a trapezium formed between the parallel sides and one of the non-parallel side, add up to 180 degrees.

Rhombus:

- All sides of the rhombus are equal.
- The opposite sides of a rhombus are parallel.
- Opposite angles of a rhombus are equal.
- In a rhombus, diagonals bisect each other at right angles.
- Diagonals bisect the angles of a rhombus.

Parallelogram:

- The opposite sides are congruent.
- The opposite angles are congruent.
- The consecutive angles are supplementary.
- If anyone of the angles is a right angle, then all the other angles will be the right angle.
- The two diagonals bisect each other.
- Each diagonal bisects the parallelogram into two congruent triangles.

Posted by Shruti Pradhan 2 days, 5 hours ago

- 3 answers

Palak Pandey 2 days, 5 hours ago

Yeah average but I think in our textbook 3 chapters are too bouring and difficult also quadrilateral , parellogram and circle😂😂😂😂😂

Posted by Purbanhi Mitra 2 days, 12 hours ago

- 2 answers

Siddhi Karnani 2 days, 12 hours ago

3x(2x³+3x²) -2(2x³+3x²)
(6x⁴+9x³) - (-4x³-6x²)
6x⁴+9x³+4x³+6x²
6x⁴+13x³+6x²

Posted by Sarah Sana 2 days, 16 hours ago

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Posted by Suresh Chand 2 days, 18 hours ago

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Posted by Krrish Prasad 2 days, 18 hours ago

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