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  • 2 answers

Maneesh R.K 1 week ago

Ex 5/7

Maneesh R.K 1 week ago

Give the sum
  • 2 answers

Mahi Sharma 4 days ago

On simple form It is a data which is used to represent coordinates or one or more than one number to determine the position of the points

Mahi Sharma 4 days ago

In geometry, a coordinate system is a system that uses one or more numbers, or coordinates, to uniquely determine the position of the points or other geometric elements on a manifold such as Euclidean space.
  • 2 answers

Rahul Gurjar 1 week ago

25+12+17÷2=27 =√27(27-25)(27-17)(27-12) =√27(2)(10)(15) =√9×3×2×5×2×5×3 =3×3×2×5 =90 Altitude to the longest side 90=½×12 90×2÷12=h 180÷12=h 15=h

Md Abdal 1 week ago

Longest altitude always forms from the shortest side
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Maneesh R.K 1 week ago

2.111 2.112 2.113 2.114 2.115 2.116 2.117 2.118 2.119 2.120 2.121 2.122 2.123 2.124 2.125 2.126 2.150

Sachin Negi 1 week, 1 day ago

2.1/1× 17/17 and 2.2/1×17/17
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Harjot Singh 1 week ago

The data we collect ourself

Sachin Negi 1 week, 1 day ago

Primary data also called internal data
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  • 2 answers

Himanshi Goyal 2 days, 22 hours ago

Chapter 1 Chapter 3 Chapter 6 Chapter 7 Chapter 12 Chapter 14

Kanchan Gadwal 1 week, 2 days ago

Chapter 1 , 3, 4,6,7,12,14
  • 1 answers

Laya Varshini.P ... 1 week, 2 days ago

1
  • 3 answers

Himanshi Goyal 2 days, 22 hours ago

12.5

Laya Varshini.P ... 1 week, 1 day ago

12.5

Anak Yadav 1 week, 2 days ago

Answer is 12.5
  • 3 answers

Ayush Sahu 1 week, 2 days ago

sare padh l9

Huda Khan 1 week, 2 days ago

7 bhi bht important h

Sujeet Roy 1 week, 3 days ago

1 , 3 , 4 , 6 , 7 , 12 , 14 syllabus he aur 1 , 6 , 12 , 3 padhke jha
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Vanshika Agarwal 1 week, 3 days ago

Either the question will be ABCD is a rhombus and p, q ,r and s are the mid-points of the sides AB,BC, CD and DA respectively . Show that the quadrilateral PQRS is a rectangle. Either it will be ABCD is a rectangle and p, q ,r and s are the mid-points of the sides AB,BC, CD and DA respectively . Show that the quadrilateral PQRS is a rhombus.

Vanshika Agarwal 1 week, 3 days ago

Ur question is wrong
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Mahi Sharma 4 days ago

In figure 6.31 if AB is parallel to CD,Angle APQ = 50° and angle PRD=127° Find x and y

Vanshika Agarwal 1 week, 3 days ago

NCERT BOOK?

Shreyansh Singh 1 week ago

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Sia 🤖 1 week, 3 days ago

Please write full question. 

  • 2 answers

Vanshika Agarwal 1 week, 3 days ago

Plz complete your question

Sia 🤖 1 week, 3 days ago

Complete your question.

  • 4 answers

Vandana Yashu 1 week, 2 days ago

Given:AC=BD----1 AB bisects angle A Therefore angle BAC =angle BAD----2 In ∆ABC and ∆ABD AC=AB(by equation 1) Angle BAC=angle BAD (by equation 2) AB=AB (common) Therefore by SAS axiom ∆ABC~∆ABD By CPCT BC=BD

Vandana Yashu 1 week, 2 days ago

AC =BD and AB bisects angle A .Show that ∆ ACB ~∆ABD ,what can you say about BC and BD?

Vanshika Agarwal 1 week, 3 days ago

Reason- How a triangle can be ABCD?

Vanshika Agarwal 1 week, 3 days ago

Ur question is wrong
  • 4 answers

Shubham Kumar 1 week, 2 days ago

2√2

Vanshika Agarwal 1 week, 3 days ago

Answer-3

Utkarsh Agarwal 1 week, 5 days ago

x² = 2 then x ³ =2√2 EXPLANATION : Let the no.'x' be √2 Now when you put the value of X in the first eq. you will get √2 *2 =2 Now put this value of X in the second eq. you will get √2*√2*√2 = 2√2

Bhagya Singla 1 week, 5 days ago

2x=2 x=2/2 x=1 Then, 3x Put (x=1) 3(1)= 3
  • 1 answers

Lucky Singh 1 week, 6 days ago

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.
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  • Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
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Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.
  • 3 answers

Laya Varshini.P ... 1 week, 1 day ago

0.41

Aditya Pal 1 week, 6 days ago

O

Jeetesh Prasad 1 week, 6 days ago

√2+1
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  • 1 answers

Sia 🤖 1 week, 6 days ago

Given: A square ABCD.

To Prove : (i) AC = BD and (ii) Diagonals bisect each other at right angles.
Proof :

  1. In {tex}\triangle{/tex}ADB and {tex}\triangle{/tex}BCA, we have
    AD = BC ...[As sides of a square are equal]
    {tex}\angle{/tex}BAD = {tex}\angle{/tex}ABC ...[All interior angles are of 90o]
    AB = BA ...[Common]
    {tex}\triangle{/tex}ADB {tex}\cong{/tex} {tex}\triangle{/tex}BCA ...[By SAS rule]
    AC = BD ...[c.p.c.t.]
  2. Now in {tex}\triangle{/tex}AOB and {tex}\triangle{/tex}COD, we have
    AB = CD ...[Sides of a square]
    {tex}\angle{/tex}AOB = {tex}\angle{/tex}COD ...[Vertically opp. angles]
    {tex}\angle{/tex}OBA = {tex}\angle{/tex}ODC ...[Alternate interior angles are equal]
    {tex}\triangle{/tex}AOB {tex}\cong{/tex} {tex}\triangle{/tex}COD ...[By ASA rule]
    OA = OC and OB = OD ...[c.p.c.t.] ...(1)
    Now consider {tex}\triangle{/tex}s AOD and COD.
    AD = CD ...[Sides of square]
    OA = OC ...[As proved above]
    OD = OD ...[Common]
    {tex}\triangle{/tex}AOD {tex}\cong{/tex} {tex}\triangle{/tex}COD ...[By SSS rule]
    {tex}\angle{/tex}AOD = {tex}\angle{/tex}COD ...[c.p.c.t.]
    But {tex}\angle{/tex}AOD + {tex}\angle{/tex}COD = 180° ...[linear pair]
    or {tex}\angle{/tex}AOD + {tex}\angle{/tex}AOD = 180° ...[As {tex}\angle{/tex}AOD = {tex}\angle{/tex}COD]
    or 2{tex}\angle{/tex}AOD = 180° {tex}\therefore{/tex} {tex}\angle{/tex}AOD = 90° ...(2)
    From equation (1) and (2) it is clear that diagonals of a square bisect each other at right angles.

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