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Vrinda Goyal 3 months, 3 weeks ago

Find the zeros of the polynomial p(x)=(x-3)²-(x+3)²
  • 4 answers

Govardhan C Chinthi 3 months, 4 weeks ago

a4-b4

Saransh Banwal 3 months, 4 weeks ago

4ab

Niharika Kakodiya 3 months, 4 weeks ago

(a+b)²(a-b)² ->(a²+2ab+b²)(a²-2ab+b²) a⁴-2a³b+a²b²+2a³b-4a²b²+2ab³+a²b²-2ab³+b⁴ a⁴+b⁴+2a²b²-4a²b² a⁴+b⁴-2a²b²

Avinash Kumar 3 months, 4 weeks ago

Hii
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Niharika Kakodiya 3 months, 4 weeks ago

If x = 0 , y = k 5x-3y=0 -> 5*0-3k=0 0-3k=0 -3k=0 K=0/-3 K=0

Akshita Goel 3 months, 4 weeks ago

5x-3y=0 5x0 - 3xk = 0 0 -3k = 0 So -3k = 0 k= 0/3 k=0
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Ranjana Dixit 4 months ago

Factories by taking common 3a^+9ab
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Roshan Kumar 4 months ago

4x²+8x+3 =4x²+(6x+2x)+3 =2(2x+3)+1(2x+3) =(2x+3)(2+1)
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Anindita Anin 4 months ago

This will be solved using middle term split. 8x²+28x+14x+49 =(8x²+28x)+(14x+49) =4x(2x+7)+7(2x+7) =(2x+7)(4x+7) Therefore (2x+7)(4x+7) is the answer. Hope this helps! 🙂
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Satyam Kumar 4 months ago

(3x+1) (4+1)

Satyam Kumar 4 months ago

(3x+1) (4+1)
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Mohd Aunn 4 months ago

Let the x X=0.001 bar X=0.001001001..................eq 1 x=1.001001001............eq2 By sub eq 1&2 10x-x=0.001......-1.001001........ 9x=1 x=1/9

Abishek R.A 4 months ago

x³-y³

Aditya Upadhyay 4 months ago

1/1000
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