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How to study 8 hrs a day

Posted by Aman Sharma 4 years, 2 months ago

CBSE > Class 11 > Physical Education

0 answers

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Mention any three major drainage system of Himalayas system ?

Posted by Thupuvezo Swuro 4 years, 2 months ago

CBSE > Class 11 > Geography

3 answers

Sia ? 4 years, 2 months ago

The Himalayan drainage system includes the Ganga, the Indus and the Brahmaputra river basins. The peninsular plateau is drained by Narmada, Tapi, the Mahanadi, the Godavari, the Krishna and the Kaveri.

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Preeti Sarwan Kumar 4 years, 1 month ago

Ganga drainage system, brahmaputra drainage system and Indus river system

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Kamlesh Mishra 4 years, 2 months ago

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पोशाक कब में िीचे झुकिे िे रोकती ै ? क िब म निम्ि श्रेणी के दुख को देखकर झुकिा चा ते ैं ख िब म निम्ि श्रेणी िे कुछ चा ते ैं ग दोिों ि ी घ इिमें िे कोई ि ीिं

Posted by Adyasa Mahapatra 4 years, 2 months ago

CBSE > Class 09 > हिंदी ब

0 answers

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Near lower part of the mountain is called___

Posted by A. S. Jeevithan Saravanan 4 years, 2 months ago

CBSE > Class 05 > English

1 answers

A. S. Jeevithan Saravanan 4 years, 2 months ago

Foothills

1Thank You

ANSWER

These two

Posted by Himamshi Mehra 4 years, 2 months ago

CBSE > Class 06 > Sanskrit

3 answers

Haridasan Sankaran 4 years, 2 months ago

These two in sanskrit is in the textbook(Page No. 3)

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Nidhi Verma 4 years, 2 months ago

Hello can you explain me chapter number 9 Karta Karak sambhog

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Sia ? 4 years, 2 months ago

What is the question?

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What do you mean by free fall ?

Posted by Ganesh P 4 years, 2 months ago

CBSE > Class 09 > Science

3 answers

Ganesh P 4 years, 2 months ago

When an object fall from high.there should act only one type of force that is gravitation force of earth.except gravitation force of earth no other force should have applied on the object

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Ganesh P 4 years, 2 months ago

It is the object falling towards earth under the influence of attraction force of earth or gravity.

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Ganesh P 4 years, 2 months ago

Gravity of the earth attracts every object towards its center. When an object is dropped from a certain height,it begins to fall towards earth's surface under the influence of gravitational force.such a motion of object is called free fall

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On 1st April, 2014, Veeru Ltd. purchased a machinery for Rs. 2,50,000 and spent rs. 50,000 on its installation. On 1st July, 2016 1/3rd of machinery purchased on 1st April, 2014 was sold for Rs. 15,000 and a new machinery at the cost of Rs. 2,00,000 was purchased on the same date. The company has adopted the method of providing depreciation @ 15% p.a. on straight line method. Show the machinery account, provision for depreciation account and machinery disposal account for three years ended on 31st March, 2015 to 31st March, 2017.

Posted by Sejal Kotasthane 4 years, 2 months ago

CBSE > Class 11 > Accountancy

1 answers

Sia ? 4 years, 2 months ago

MACHINERY ACCOUNT

Dr.					Cr.
Date	Particulars	Amount ₹	Date	Particulars	Amount ₹
2014 April 1	To Bank A/c	2,50,000
April 1	To Bank A/c (Installation Exp.)	50,000	2015 Mar. 31	By Balance c/d	3,00,000
		3,00,000			3,00,000
2015 April 1	To Balance b/d	3,00,000	2016 Mar. 31	By Balance c/d	3,00,000
		3,00,000			3,00,000
2016 April 1	To Balance b/d	3,00,000	2016 July 1	By Machinery Disposal A/c	1,00,000
2016 July 1	To Bank A/c	2,00,000	2017 Mar. 31	By Balance c/d	4,00,000
		5,00,000			5,00,000

PROVISION FOR DEPRECIATION ACCOUNT

Dr.					Cr.
Date	Particulars	Amount ₹	Date	Particulars	Amount ₹
2015 Mar 31	To Balance c/d	45,000	2015 Mar. 31	By Depreciation A/c	45,000
		45,000			45,000
2016 Mar. 31	To Bank c/d	90,000	2015 April 1	By Balance b/d	45,000
			2016 Mar. 31	By Depreciation A/c	45,000
		90,000			90,000
2016 July 1	To Machinery Disposal A/c	33,750	2016 April 1	By Balance b/d	90,000
2017 Mar. 31	To Balance c/d	1,12,500	July 1	By Depreciation A/c	3,750
			Mar. 31	By Depreciation A/c	52,500
		1,46,250			1,46,250

MACHINERY DISPOSAL ACCOUNT

Dr.					Cr.
Date	Particulars	Amount ₹	Date	Particulars	Amount ₹
2016 July 1	To Machinery A/c	1,00,000	2016 July 1	By Provision for Depreciation A/c	33,750
			July 1	By Bank A/c	15,000
			July 1	By Statement of Profit & Loss (Loss on sale)	51,250
		1,00,000			1,00,000

Working Notes:

(1)	Calculation of loss on sale of machinery:	₹
	Original Cost of {tex}\frac{1}{3}{/tex}rd machinery as on 1st April, 2014	1,00,000
	Less : Depreciation @ 15% p.a. for 2 years 3 months on original cost method	33,750
	Book Value as on 1st July, 2016	66.250
	Less: Sale proceeds	15.000
	Loss on sale	51.250
(2)	Depreciation on unsold machinery for the year 2016-17 :
	On old machinery of ₹2,00,000 for 1 year	30.000
	On new machinery of ₹2,00,000 for 9 months	22.500
		52.500

Depreciation is charged @ 10% each year on origial value of asset each year i.e., same amount of depreciation charged each year.If some expenses are incur while purchasing asset the it is capitalised in value of asset.

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Can any one please tell me the answer ? The zeros of the quadratic polynomial x square+99x+127

Posted by Aditi Singhania 4 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Yuvraj Agarwal 4 years, 2 months ago

By direct formula -b/a = -9 / 1

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Anwesha Paul 4 years, 2 months ago

-1.3 and -97.7

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Newspaper are official records

Posted by Vallabha B. M. 4 years, 2 months ago

CBSE > Class 08 > Social Science

1 answers

Jesse Trina ? 4 years, 2 months ago

True

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All class 10th maths formula

Posted by Ashmit Patel 4 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Rakshit Singh 4 years, 2 months ago

Book mei dekh le

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Sumit Yadav 4 years, 2 months ago

Polynomials Formulas ( x + y ) 2 = x 2 + y 2 + 2 x y ( x − y ) 2 = x 2 + y 2 − 2 x y ( x + y ) ( x − y ) = x 2 − y 2 ( x + y ) ( x + z ) = x 2 + x ( y + z ) + y z ( x + y ) ( x − z ) = x 2 + x ( y − z ) − y z x 2 + y 2 = ( x + y ) 2 − 2 x y ( x + y ) 3 = x 3 + y 3 + 3 x y ( x + y ) ( x − y ) 3 = x 3 − y 3 − 3 x y ( x − y ) ( x + y + z ) 2 = x 2 + y 2 + z 2 + 2 x y + 2 y z + 2 z x ( x − y − z ) 2 = x 2 + y 2 + z 2 − 2 x y + 2 y z − 2 z x x 3 + y 3 = ( x + y ) ( x 2 − x y + y 2 ) x 3 − y 3 = ( x − y ) ( x 2 + x y + y 2 ) x 4 − y 4 = ( x 2 ) 2 − ( y 2 ) 2 = ( x 2 + y 2 ) ( x 2 − y 2 ) = ( x 2 + y 2 ) ( x + y ) ( x − y ) ( x + y + z ) 2 = x 2 + y 2 + z 2 + 2 x y + 2 y z + 2 z x ( x + y − z ) 2 = x 2 + y 2 + z 2 + 2 x y − 2 y z − 2 z x ( x − y + z ) 2 = x 2 + y 2 + z 2 − 2 x y − 2 y z + 2 z x ( x − y − z ) 2 = x 2 + y 2 + z 2 − 2 x y + 2 y z − 2 z x x 3 + y 3 + z 3 − 3 x y z = [ ( x + y + z ) ( x 2 + y 2 + z 2 − x y − y z − z x ) ] 2. Arithmetic Progression Formulas nth Term of an Arithmetic Progression a n = a + ( n − 1 ) × d Sum of 1st n Terms of an Arithmetic Progression S n = n 2 [ 2 a + ( n − 1 ) d ] 3. Coordinate Geometry Formulas Distance Formula A B = √ ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2 Section Formula ( m x 2 + n x 1 m + n , m y 2 + n y 1 m + n ) Mid-point Formula ( x 1 + x 2 2 , y 1 + y 2 2 ) Area of Triangle ar ( Δ A B C ) = 1 2 × ⎡ ⎢ ⎣ x 1 ( y 2 − y 3 ) + x 2 ( y 3 − y 1 ) + x 3 ( y 1 − y 2 ) ⎤ ⎥ ⎦ 4. Trigonometry Formulas Trigonometric Identities sin 2 A + cos 2 A = 1 tan 2 A + 1 = sec 2 A cot 2 A + 1 = c o s e c 2 A Relations between Trigonometric Identities tan A = sin A cos A cot A = cos A sin A c o s e c A = 1 sin A sec A = 1 cos A Trigonometric Ratios of Complementary Angles sin ( 90 ∘ − A ) = cos A cos ( 90 ∘ − A ) = sin A tan ( 90 ∘ − A ) = cot A cot ( 90 ∘ − A ) = tan A sec ( 90 ∘ − A ) = c o s e c A c o s e c ( 90 ∘ − A ) = sec A Values of Trigonometric Ratios of 0° and 90° ∠ A 0 ∘ 30 ∘ 45 ∘ 60 ∘ 90 ∘ sin A 0 1 2 1 √ 2 √ 3 2 1 cos A 1 √ 3 2 1 √ 2 1 2 0 tan A 0 1 √ 3 1 √ 3 Not Defined sec A 1 2 √ 3 √ 2 2 Not Defined cosec A Not Defined 2 √ 2 2 √ 3 1 cot A Not Defined √ 3 1 1 √ 3 0 5. Circles Formulas Area of circle π r 2 Diameter of circle 2 r Circumference of circle 2 π r Sector angle of circle θ = ( 180 × l ) ( π r ) Area of the sector = ( θ 2 ) × r 2 Area of the circular ring = π × ( R 2 − r 2 ) θ = Angle between two radii R = Radius of outer circle r = Radius of inner circle 6. Statistics Formulas Mean a m = a 1 + a 2 + a 3 + a 4 4 = n ∑ 0 a n Median M e d i a n = l + ( n 2 − c f f ) h Mode M o = l + ( f 1 − f 0 2 f 1 − f 0 − f 2 ) h 7. Quadratic Equations Formulas Quadratic Equations a x 2 + b x + c = 0 where a ≠ 0 Quadratic Polynomial P ( x ) = a x 2 + b x + c where a ≠ 0 Zeroes of the Polynomial P ( x ) The Roots of the Quadratic Equations are zeroes One Real Root b 2 − 4 a c = 0 Two Distinct Real Roots b 2 − 4 a c > 0 No Real Roots b 2 − 4 a c < 0 8. Triangles Formulas Six elements of triangle Three sides and three angles Angle sum property of triangle Sum of three angles: ∠ A + ∠ B + ∠ C = 180 ∘ Right angled triangle Adjacent Side Opposite Side Hypotenuse Pythagoras Theorem H 2 = A S 2 + O S 2 H = Hypotenuse A S = Adjacent Side O S = Opposite Side Equilateral Triangles All sides are equal Isosceles Triangle Two sides are equal Congruent Triangles Their corresponding parts are equal SSS Congruence of two triangles Three corresponding sides are equal SAS Congruence of two triangles Two corresponding sides and an angle are equal ASA Congruence of two triangles Two corresponding angles and a side are equal 9. Surface Area and Volume Formulas Cuboid Volume of Cuboid (LSA) l × b × h Lateral Surface Area of Cuboid (LSA) 2 h ( l + b ) Total Surface Area of Cuboid (TSA) 2 ( l b + b h + h l ) Cube Volume of Cube x 3 Lateral Surface Area of Cube (LSA) 4 x 2 Total Surface Area of Cube (TSA) 6 x 2 Sphere Volume of Sphere 4 3 × π r 3 Lateral Surface Area of Sphere (LSA) 4 π r 2 Total Surface Area of Sphere (TSA) 4 π r 2 Right Circular Cylinder Volume of Right Circular Cylinder π r 2 h Lateral Surface Area of Right Circular Cylinder (LSA) 2 × ( π r h ) Total Surface Area of Right Circular Cylinder (TSA) 2 π r × ( r + h ) Right Pyramid Volume of Right Pyramid 1 3 × [ Area of the Base ] × h Lateral Surface Area of Right Pyramid (LSA) 1 2 × p × L Total Surface Area of Right Pyramid (TSA) LSA + [ Area of the Base ] Right Circular Cone Volume of Right Circular Cone 1 3 × ( π r 2 h ) Lateral Surface Area of Right Circular Cone (LSA) π r l Total Surface Area of Right Circular Cone (TSA) π r × ( r + L ) Hemisphere Volume of Hemisphere 2 3 × ( π r 3 ) Lateral Surface Area of Hemisphere (LSA) 2 π r 2 Total Surface Area of Hemisphere (TSA) 3 π r 2 Prism Volume of Prism B × h Lateral Surface Area of Prism (LSA) p × h Total Surface Area of Prism (TSA) π × r × ( r + L ) l = Length, h = Height, b = Breadth r = Radius of Sphere L = Slant Height

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If 2 sin2 B -cos2B=2,then B is

Posted by Dichen Sherpa 4 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Tanya Singh 4 years, 2 months ago

90° or 180°

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Ashmit Patel 4 years, 2 months ago

Pta nhi

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Does the notes provided in this app cover full chapter??

Posted by Pawandeep Kaur 4 years, 2 months ago

CBSE > Class 10 > Science

4 answers

Priya . 4 years, 2 months ago

Yes

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Rakshit Singh 4 years, 2 months ago

Yes

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Priya . 4 years, 2 months ago

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Mamta Devi 4 years, 2 months ago

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The perimeter of a sector of a circle with central angle 90° is 25cm. The area of the minor segment of the circle is

Posted by Rimi Das 4 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Sumit Yadav 4 years, 2 months ago

Let r be the radius of the circle and θ be the angle. Now, Perimeter of the sector=(2r+2πrθ360) =2r+2×227×r×90360=(2r+11r7)=25r7 Also, 25r7=25⇒r=(25×725)⇒r=7 cm Area of the minor segment=(πr2θ360−12r)2sin θ cm2 =∣∣(227×7×7×90360)−(12×7×7×sin 90°)∣∣ cm2=(772−492) cm2=282 cm2=14 cm2

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Ex 9.2 QS no 16

Posted by Anish Kumar 4 years, 2 months ago

CBSE > Class 11 > Mathematics

0 answers

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Write a short python code segment that prints the longest word in a list

Posted by Ankit Patel 4 years, 2 months ago

CBSE > Class 12 > Computer Science

1 answers

Deepak Jain 4 years, 1 month ago

Long=len(L[0]) Longest=L[0] for i in L: if len(i)>Long: Long=len(i) Longest=i print(Longest)

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Main English ka first chapter acche se samajh nahi Pa rahi hai

Posted by Shree Shreya 4 years, 2 months ago

CBSE > Class 05 > English

1 answers

Tanishka Sharma 4 years, 2 months ago

English first chapter ice cream man this chapter was very easy

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Who was the first person to meet Modiji?

Posted by Chandrashekar Murgad 4 years, 2 months ago

CBSE > Class 05 > General Knowledge

5 answers

Khushi _03 4 years, 1 month ago

His mother

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Shivani.S.Malagan 6Th 'B' 4 years, 1 month ago

His mother

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Jaya Pandey 4 years, 2 months ago

His mother

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Jiyan Menat 4 years, 2 months ago

Shri Narendra bhai Modi

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Angel Gautam 4 years, 2 months ago

Biggest country

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Different types of vegetation and the climatic condition

Posted by Sampada Awajigol 4 years, 2 months ago

CBSE > Class 07 > Social Science

1 answers

Sia ? 4 years, 2 months ago

Tropical Evergreen rainforests
Deciduous or Monsoon type of forests
The Thorn Forests and Scrubs
Montane Forests
Mangrove Forests

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IDENTIFY X AND Y IN THE FOLLOWING REACTION Ca(OH)2 (aq) + X(g) cacl2(s) + y + 2NH3

Posted by Pawan Padihar 4 years, 2 months ago

CBSE > Class 10 > Science

1 answers

Palak Arora 4 years, 2 months ago

X= Nh4Cl and Y=H20. So the equation becomes- Ca(OH)2 + NH4Cl =h20+ 2NH3+ cacl2.

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What is formal and informal letter

Posted by Vipul Jaisal 4 years, 2 months ago

CBSE > Class 09 > English Lang & Lit. (184)

3 answers

Rishma Bhuyan 4 years, 2 months ago

The main difference between formal and informal letters professionally address someone, and informal letters address someone in a personal way. Other differences include: Formal letter follow a specific format, while informal letter can follow any format

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Radhika Tayal 4 years, 2 months ago

Letter written to school , office ,any government office fot any official work it is called formal letter Letter written to you family members ,relatives or friends then it is informal letter

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Ramesh Kaushik 4 years, 2 months ago

Formal

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How I make project file on topic animal and plant cell ??

Posted by Sayli Mane 4 years, 2 months ago

CBSE > Class 09 > Science