Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Mamta Chetri 3 years, 2 months ago
- 0 answers
Posted by Md Fahim Ahmad 3 years, 2 months ago
- 0 answers
Posted by Mohan Venkata Sai Reddy Singarapu 3 years, 2 months ago
- 3 answers
Shailja Singh 3 years, 2 months ago
Aastik Verma 3 years, 2 months ago
Posted by Shibashish Sahoo 3 years, 2 months ago
- 0 answers
Posted by Shnaya Singla 3 years, 2 months ago
- 0 answers
Posted by Chahak Kukreja 11 2 years, 10 months ago
- 3 answers
Akshiti Ajay 3 years, 2 months ago
Posted by Aanya Wadhwa 3 years ago
- 1 answers
Preeti Dabral 3 years ago
Democracy enhances dignity and freedom of an individual by giving equal rights to its citizens.
Posted by Vaibhav Sharma 3 years, 2 months ago
- 0 answers
Posted by Rohan Sahu 3 years, 2 months ago
- 0 answers
Posted by Aradhya Purwar 3 years, 2 months ago
- 5 answers
Guriya Singh 3 years, 2 months ago
Posted by Ashok Mahadik 3 years, 2 months ago
- 1 answers
Amal Krishna 3 years, 2 months ago
Posted by Aradhya Purwar 3 years, 2 months ago
- 3 answers
Ishika Paswan 3 years, 1 month ago
Posted by Rajeswari V 3 years, 2 months ago
- 0 answers
Posted by Prakash Chakraborty 3 years, 2 months ago
- 0 answers
Posted by Masuma Begum 3 years, 2 months ago
- 0 answers
Posted by Gurjott Kaurr 3 years, 2 months ago
- 2 answers
Ruchika Kumari 3 years, 2 months ago
Posted by Mohit Nain 3 years, 2 months ago
- 1 answers
Avichal S 3 years ago
Posted by M W 3 years, 2 months ago
- 1 answers
Siya Nath 3 years, 2 months ago
Posted by Priyanshi Patel 3 years, 2 months ago
- 1 answers
Tanisha Chaudhary 3 years ago
Posted by Mayil Samy 3 years, 2 months ago
- 0 answers
Posted by Ritika Sharma 3 years, 2 months ago
- 1 answers
Posted by Devendra Kumar 3 years, 1 month ago
- 1 answers
Preeti Dabral 3 years, 1 month ago
Given: {tex}y = {\sin ^{ - 1}}\left( {\frac{{2x}}{{1 + {x^2}}}} \right){/tex}
To simplify the given Inverse Trigonometric function,we put, {tex}x = \tan \theta{/tex}
{tex}\Rightarrow y = {\sin ^{ - 1}}\left( {\frac{{2\tan \theta }}{{1 + {{\tan }^2}\theta }}} \right) = {\sin ^{ - 1}}\left( {\sin 2\theta } \right) = 2\theta{/tex}
{tex}\Rightarrow y = 2{\tan ^{ - 1}}x{/tex}
{tex}\Rightarrow \frac{{dy}}{{dx}} = 2.\frac{1}{{1 + {x^2}}} = \frac{2}{{1 + {x^2}}}{/tex}

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide