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Preeti Dabral 2 years, 9 months ago
Let the digits of the required 3 - digit number at hundreds, tens and ones places be {tex}a - d, ~ a , ~ a + d{/tex} respectively
Then their sum = 15
i.e, {tex}a - d + a + a + d{/tex} = 15
{tex}\Rightarrow{/tex} {tex}3a{/tex} = 15
{tex}\Rightarrow{/tex} {tex}a{/tex} = 5
Required three digit number = {tex}100(a - d) + 10a + a + d{/tex}
= {tex}100a - 100d + 10a + a + d{/tex}
= {tex}111a - 99d{/tex}
Number obtained by reversing the digits = {tex}100(a + d) + 10a + a - d{/tex}
= {tex}100a + 100d + 10a + a - d{/tex}
= {tex}111a + 99d{/tex}
According to the question,
{tex}111a + 99d = 111a - 99d - 594{/tex}
{tex}\Rightarrow{/tex} {tex}594 = 111a - 99d - 111a - 99d{/tex}
{tex}\Rightarrow{/tex}{tex}594 = -198d{/tex}
{tex}\Rightarrow{/tex}{tex}\frac { - 594 } { 198 } = d{/tex}
{tex}d = -3{/tex}
The number is 111a - 99d
{tex}111 \times 5 - 99 \times - 3{/tex}= 852
555 + 297 = 852
Therefore, Number is 852.
Posted by Drishti Pal 2 years, 10 months ago
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Sejal Shakya 2 years, 10 months ago
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Sejal Shakya 2 years, 10 months ago
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Sejal Shakya 2 years, 10 months ago
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Ebright grew up north of Reading, Pennsylvania. He was the only child of his parents. His father died when he was in third grade. He excelled in school and enjoyed collecting rocks, fossils, and coins as a child.
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Tarun Kumar 2 years, 10 months ago
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Hitesh Chaudhary Solution 2 years, 10 months ago
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