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Rutvik Vankar 1 day, 12 hours ago

18.3

Aashna Meena 4 days, 13 hours ago

Wave is continues form of energy

Nazia Kazmi 6 days, 20 hours ago

Can I ask some maths problem

Avishka - 1 week, 5 days ago

power is the defined as the the rate of work done.its unit is watt.

Avishka - 1 week, 5 days ago

resistance in parallel=1/3 resistance in series=3 equivalent resistance=10/3

Chandresh Tomar 2 weeks, 3 days ago

Hyy

Jeetlal Yadav 2 weeks, 5 days ago

The ratio of lateral stress to the longitudinal stress
First calculate the arithmetic mean of readings, Xmean = X1 + X2 + X3 + X4 + X5 =(2.63+2.56+2.42+2.71+2.80)/5 = 2.62s The absolute error can be calculated as, For first reading, ΔX1=(2.63−2.62) ΔX1=0.01s For second reading, ΔX2=(2.56−2.62) ΔX2=0.06s For third reading, ΔX3=(2.42−2.62) ΔX3=0.20s For forth reading, ΔX4=(2.71−2.62) ΔX4=0.09s For fifth reading, ΔX5=(2.80−2.62) ΔX5=0.18s Calculate the arithmetic mean of absolute errors, ΔXmean=(ΔX1+ΔX2+ΔX3+ΔX4+ΔX5)/5 ΔXmean=(0.01+0.06+0.20+0.09+0.18)/5 ΔXmean=0.54/5 ΔXmean=0.11s Calculate the relative error, RE=ΔXmean/Xmean RE=0.11/2.62 RE=0.04s Calculate the percentage error, PE=(ΔXmean/Xmean)×100 PE=(0.11/2.62)×100 PE=4%

Avishka - 1 week, 5 days ago

i joule=10^7erg

Shubh Lakshna Pandey 3 weeks, 5 days ago

10^8 erg

Tika Ram 1 month ago

10^8

Saroj Kant 1 month ago

1H

Anshika Saini 1 month ago

Kya hota hai

Aashna Meena 4 days, 13 hours ago

Lamda and meter

Anshika Saini 1 month ago

Ohm

Ritesh Kumar 1 month ago

Omm

Barsha Kumbhakar 1 month, 1 week ago

Nanometre (nm) : 1nm=10−9m (iii) Angs→rm(Å):1Å=10-10m
Can you give me the notes of ch 1 physics

Avishka - 1 week, 5 days ago

1N=10^5dyne 5 N=5*10^5 dyne

Tika Ram 1 month ago

50^5

Naman Gupta 1 month, 2 weeks ago

We know that Newton is in MKS while Dyne is in CGS N2 = N1 U1/ U2 N1 5 N2 x U1 Mks U2 Cgs Putting it 5* kg m sec-2/ g Cm sec-2 (Sec cut) N2= 5* kg/g* m/Cm 5 *1000g/g *100cm/cm 5*1000*100 500000 5*10power5

Shinjini Ghosh 1 month, 2 weeks ago

I think reading ncert for now is enough

Chahat Kumar 1 month, 2 weeks ago ## myCBSEguide

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