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Posted by Manish Saini 6 hours ago

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Posted by Helena Rose 21 hours ago

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Yogita Ingle 6 hours ago

Mass spectrometry is an analytical method to find the molecular mass of a compound and indirectly helped to prove the identity of isotopes.

A mass spectrometer generates multiple ions from the sample being investigated, then separates them by their specific mass-to-charge ratio (m/z) and then records the relative abundance of each type of ion.

Posted by Sonali Kanwar Rathore 23 hours ago

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Yogita Ingle 7 hours ago

The first law has already given us a qualitative definition of force. Now we are interested in finding out its magnitude. According to Newton’s second law of motion, the net force experienced by a body is directly proportional to the rate of change of momentum of the body. It can be written as:

f ∝ dP/dt

⇒f ∝ (mv−mu)/t

⇒f∝m(v−u)/t

⇒f∝ma

⇒f=kma

Where k is the constant of proportionality and it comes out to be 1 when the values are taken in SI unit. Hence the final expression will be,

F = ma

Posted by Kritika Joshi 1 day ago

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Posted by Nazir Ahmed 1 day, 1 hour ago

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Yogita Ingle 23 hours ago

**Motion:**-A body is said be in a state of motion if it changes its position continuously with respect to its surroundings with the passage of time.

E.g A bus running on a road, a flying bird etc

**Rest:-** A body is said to be at rest if it does not changes its position continuously with respect to its surroundings with the passage of time.

Eg A book lying on a table.

Pranathi Markapuram 1 day ago

Object at rest in the sense it doesn't change it's position with respect to it's surroundings whereas object in motion changes it's position with respect to it's surroundings.

Posted by Anushka Negi 1 day, 7 hours ago

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Yogita Ingle 1 day, 6 hours ago

When an external force is applied to a rigid body there is a change in its length, volume (or) shape. When external forces are removed the body tends to regain its original shape and size. Such a property of a body by virtue of which a body tends to regain its original shape (or) size when external forces are removed is called elasticity.

Posted by Sanjay Kumar 2 days ago

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Pk . 1 day, 13 hours ago

TAN alpha= (B TAN theta)/(A+B COS theta) Here gives u direction of resultant and theta here is angle btw two vectors

Posted by Harshdeep Singh Sidhu 2 days, 3 hours ago

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Yogita Ingle 3 days, 9 hours ago

Dimensional analysis for formula of frequency of oscillating liquid drop.

r= radius = [L].

d= p= density = [M ][L^-3]

S = Surface Tension = [M T^-2]

n = frequency = k* r^a * p^b * S^c.

So [T^-1] = [M^b+c] [L^a-3b] [T^-2c]

Equating powers: a = -3/2. b= -1/2. c=1/2.

Answer: n = k* sqrt(S/(p*r^3))

Or n = k* sqrt (S/m).

m = mass of the drop.

Posted by Swasti Ranjan 5 days, 4 hours ago

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Yogita Ingle 5 days ago

Joule is the unit for energy

Dimension Formula for Joule is [M¹L²T⁻²]

Let n1(joule)=n2(erg)

n1(M₁¹L₁²T₁⁻²]=n2[M₂¹L₂²T₂⁻²]

n2=n1(M₁¹L₁²T₁⁻²] /M₂¹L₂²T₂⁻²]

=n1x(M1/M2)¹x(L1/L2)²x(T1/T2)⁻²

=1x(1kg/gm)¹x(1m/1cm)²x(1s/1s)⁻²

=1x(1000g/gm)x(100cm/1cm)²x(1s/1s)⁻²

=10⁷

Therefore n1(joule)=n2(erg)

∴1 Joule=10⁷erg

Posted by Apurva Gupta 5 days, 7 hours ago

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Posted by Gurleen Kaur 5 days, 8 hours ago

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Y P Learning Solutions 4 days, 12 hours ago

According to Newton's Second Law: If a particle of mass {tex}m{/tex} has velocity {tex}v{/tex} at any moment {tex}t{/tex},

{tex}\vec{F}=\frac{d\vec{p}}{dt}{/tex}, where {tex}\vec{F}{/tex}is the force and {tex}\vec{p}=m\vec{v}{/tex} is the momentum.

Thus,

{tex}\vec{F} =\frac{d(m{\vec{v}})}{dt} =m\frac{d\vec{v}}{dt}+\vec{v}\frac{dm}{dt}{/tex}

For cases where mass changes with time, the above equation would be applicable.

*Special Cases:*

- If mass remains constant, as we see in most theories an numericals, {tex}\frac{dm}{dt}=0{/tex} hence, {tex}\vec{F}=m\frac{d\vec{v}}{dt}=m\vec{a}{/tex}, where {tex}\vec{a}{/tex} is the acceleration of the object.
- If the velocity remains constant but mass emerges out or gets added at a constant rate, as in cases of water coming out of hose pipe, or sands added at constant rate upon a moving belt; {tex}\vec{F}=\vec{v}\frac{dm}{dt}{/tex}.

Posted by Tushar Goswami 5 days, 11 hours ago

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Atul Kumar 3 days, 10 hours ago

Are you able to give me answers of my Q. Then tell me I'll give you 50 Q.including both types

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Posted by Aanchal Mittal 1 week ago

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Posted by Simarpreet Bhoi 1 week ago

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Ayush Pandey 1 week ago

Dude abhi class 11 ke starting me calculus samajh me nhi aaye to bhi uske basic formulae yaad kar lo because pure 11th me iska use karna padega aur ise badhia se padhna hai class 12 me.
I am ur senior.
Its just an advice

Posted by Rishabh Patidar 1 week, 1 day ago

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Posted by Anita Kumari 1 week, 1 day ago

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Posted by Ansh Sharma 1 week, 1 day ago

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Ansh Sharma 1 week, 1 day ago

V = velocity
E= coefficient of elasticity = MLraise to the power -1 T raise to the power -2
P= density
V= LT raise to the power -1
√ E/P = LT raise to the power -1
Hence the LHS and RHS are same and hence it is correct

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