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Yogita Ingle 6 hours ago
Mass spectrometry is an analytical method to find the molecular mass of a compound and indirectly helped to prove the identity of isotopes.
A mass spectrometer generates multiple ions from the sample being investigated, then separates them by their specific mass-to-charge ratio (m/z) and then records the relative abundance of each type of ion.
Posted by Sonali Kanwar Rathore 23 hours ago
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Yogita Ingle 7 hours ago
The first law has already given us a qualitative definition of force. Now we are interested in finding out its magnitude. According to Newton’s second law of motion, the net force experienced by a body is directly proportional to the rate of change of momentum of the body. It can be written as:
f ∝ dP/dt
⇒f ∝ (mv−mu)/t
⇒f∝m(v−u)/t
⇒f∝ma
⇒f=kma
Where k is the constant of proportionality and it comes out to be 1 when the values are taken in SI unit. Hence the final expression will be,
F = ma
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Yogita Ingle 23 hours ago
Motion:-A body is said be in a state of motion if it changes its position continuously with respect to its surroundings with the passage of time.
E.g A bus running on a road, a flying bird etc
Rest:- A body is said to be at rest if it does not changes its position continuously with respect to its surroundings with the passage of time.
Eg A book lying on a table.
Pranathi Markapuram 1 day ago
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Yogita Ingle 1 day, 6 hours ago
When an external force is applied to a rigid body there is a change in its length, volume (or) shape. When external forces are removed the body tends to regain its original shape and size. Such a property of a body by virtue of which a body tends to regain its original shape (or) size when external forces are removed is called elasticity.
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Yogita Ingle 3 days, 9 hours ago
Dimensional analysis for formula of frequency of oscillating liquid drop.
r= radius = [L].
d= p= density = [M ][L^-3]
S = Surface Tension = [M T^-2]
n = frequency = k* r^a * p^b * S^c.
So [T^-1] = [M^b+c] [L^a-3b] [T^-2c]
Equating powers: a = -3/2. b= -1/2. c=1/2.
Answer: n = k* sqrt(S/(p*r^3))
Or n = k* sqrt (S/m).
m = mass of the drop.
Posted by Swasti Ranjan 5 days, 4 hours ago
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Yogita Ingle 5 days ago
Joule is the unit for energy
Dimension Formula for Joule is [M¹L²T⁻²]
Let n1(joule)=n2(erg)
n1(M₁¹L₁²T₁⁻²]=n2[M₂¹L₂²T₂⁻²]
n2=n1(M₁¹L₁²T₁⁻²] /M₂¹L₂²T₂⁻²]
=n1x(M1/M2)¹x(L1/L2)²x(T1/T2)⁻²
=1x(1kg/gm)¹x(1m/1cm)²x(1s/1s)⁻²
=1x(1000g/gm)x(100cm/1cm)²x(1s/1s)⁻²
=10⁷
Therefore n1(joule)=n2(erg)
∴1 Joule=10⁷erg
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Y P Learning Solutions 4 days, 12 hours ago
According to Newton's Second Law: If a particle of mass {tex}m{/tex} has velocity {tex}v{/tex} at any moment {tex}t{/tex},
{tex}\vec{F}=\frac{d\vec{p}}{dt}{/tex}, where {tex}\vec{F}{/tex}is the force and {tex}\vec{p}=m\vec{v}{/tex} is the momentum.
Thus,
{tex}\vec{F} =\frac{d(m{\vec{v}})}{dt} =m\frac{d\vec{v}}{dt}+\vec{v}\frac{dm}{dt}{/tex}
For cases where mass changes with time, the above equation would be applicable.
Special Cases:
- If mass remains constant, as we see in most theories an numericals, {tex}\frac{dm}{dt}=0{/tex} hence, {tex}\vec{F}=m\frac{d\vec{v}}{dt}=m\vec{a}{/tex}, where {tex}\vec{a}{/tex} is the acceleration of the object.
- If the velocity remains constant but mass emerges out or gets added at a constant rate, as in cases of water coming out of hose pipe, or sands added at constant rate upon a moving belt; {tex}\vec{F}=\vec{v}\frac{dm}{dt}{/tex}.
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