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  • 1 answers

Mayank Saarthak 2 years, 6 months ago

Cos²Q
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Anjan Karthi 2 years, 6 months ago

When no of electrons in the valence shell is less than 4, then, these electrons have a tendency to be lost from the atom so that the atom can attain the nearest (penultimate shell) octet. When no of electrons is greater than 4, there is a tendency that the atoms gain electrons in their neighborhood to attain nearest (valence shell) octet. But, when no of valence electrons is equal to 4, gaining 4 electrons is a matter outside the control of the nucleus and losing 4 electrons causes huge energy loss to the molecule, disturbing it's thermodynamic stability. So, here electrons are just shared, and not completely transferred as in the previous cases.
  • 2 answers

Varsha 🥰😘 2 years, 6 months ago

ap

Kushal Shah 2 years, 6 months ago

.
  • 1 answers

Bharat Malik 2 years, 6 months ago

Ctrl+ a
  • 1 answers

Alisha Margoob 2 years, 6 months ago

Learn half and again half and again half you can do this process you remember the answer
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  • 3 answers

K. Adwita Iyengar 2 years, 4 months ago

55

Riya. Shilimkar 2 years, 5 months ago

Hu

Shaik Firdous 2 years, 6 months ago

55
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Satyam Tiwari 2 years, 6 months ago

A solution that contains maximum amount of solute can be dissolved under a conditions at which the solution exists
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Bhargava Bharath 2 years, 6 months ago

The product of the zeros of a quadratic equation is equal to the constant term divided by the coefficient of the squared term. So, for the quadratic equation 3kx² - 7x + 11, the product of the zeros would be: x * (1/x) = 1 Now, we can use the sum of the zeros of a quadratic equation, which is equal to the negative coefficient of the linear term divided by the coefficient of the squared term. So, for our equation: x + (1/x) = -(-7) / 3k x + (1/x) = 7 / 3k Now, we have two equations: x * (1/x) = 1 x + (1/x) = 7 / 3k Let's simplify the first equation: x * (1/x) = 1 1 = 1 Now, for the second equation, let's solve for x + (1/x): x + (1/x) = 7 / 3k Since we know that x * (1/x) = 1, we can multiply both sides of the second equation by x: x * (x + (1/x)) = x * (7 / 3k) This simplifies to: x² + 1 = 7x / 3k Now, let's find the common denominator on the right side: x² + 1 = (7x * x) / (3k * x) x² + 1 = (7x²) / (3kx) Now, let's bring all terms to one side of the equation: x² + 1 - (7x²) / (3kx) = 0 To solve this quadratic equation for x, we need to find the common denominator: (3kx * x² + 3kx - 7x²) / (3kx) = 0 Now, we need to find the LCD (Least Common Denominator) of the terms in the numerator: LCD = 3kx Now, let's multiply both sides of the equation by the LCD to get rid of the fraction: 3kx * (3kx * x² + 3kx - 7x²) / (3kx) = 0 * (3kx) This simplifies to: 3kx * (3kx * x² + 3kx - 7x²) = 0 Expanding the expression: 9k²x³ + 3k²x² - 21kx³ = 0 Combine the x³ terms: (9k² - 21k) * x³ + 3k²x² = 0 For this equation to be true for all x, the coefficients of x³ and x² must be zero: 9k² - 21k = 0 (Coefficient of x³) 3k² = 0 (Coefficient of x²) Solving the second equation: 3k² = 0 k² = 0 k = 0 Now, for the first equation: 9k² - 21k = 0 9(0)² - 21(0) = 0 0 - 0 = 0 Since both equations are true when k = 0, the value of k that satisfies the conditions is k = 0.
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Smyan Doshi 2 years, 6 months ago

For growth and development of our body
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  • 2 answers

Jonty Banjara 2 years, 6 months ago

Kya hua

Jonty Banjara 2 years, 6 months ago

Jonty
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Anushka Singh 2 years, 3 months ago

In society 4 points of significance of reproductive health are as follows: -Reproductive health is vital in the prevention and control of sexually transmitted diseases such as AIDS, HIV, etc. -Population control and unwanted pregnancies can be avoided. -Awareness about pre and post maternal care and proper medications. -Better *** education spreading awareness about contraception, misconceptions, etc.
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Hari Patel 2 years, 6 months ago

LAN
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  • 1 answers

Md Mudassir 2 years, 6 months ago

AEo/(d-t+t/k)
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Prachi Chaudhary 2 years, 5 months ago

Naepoleon sahinta ke naam se jaana jaata hai

Abhijeet Kumar 2 years, 6 months ago

Napoleon
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Aarav Gupta 2 years, 6 months ago

967.015
  • 2 answers

Gaurav Singh 2 years, 6 months ago

a²+b² = (a+b)² - 2ab. 61 =(11)² - 2ab. 61=121-2ab. ab =30. a³+b³ =(a+b) (a²+b²+ab). = 11 + (61 + 30) = 11 x 181 = 1991

Akshayaasree Akshayaasree 2 years, 6 months ago

2x2x2x=

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