CBSE > Class 12 > Physics | CBSE Board | Homework Help

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Posted by Kriti Singh 3 weeks, 1 day ago

CBSE > Class 12 > Physics

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Pollaride

Posted by Tarannum Ahmad 3 weeks, 3 days ago

CBSE > Class 12 > Physics

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Don't post personal information, mobile numbers and other details.
Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
Ask specific question which are clear and concise.

Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

Posted by Shivam Chaudhary 3 weeks, 3 days ago

CBSE > Class 12 > Physics

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Relation between Xm and Xr

Posted by Suraj Singh Meena Meena 3 weeks, 3 days ago

CBSE > Class 12 > Physics

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How many interference fringes will be seen if the size of each slit is 1/5 the separation of between two slits

Posted by Rekha Sharma 3 weeks, 6 days ago

CBSE > Class 12 > Physics

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IC=ID

Posted by Mohit Tanwar 4 weeks, 1 day ago

CBSE > Class 12 > Physics

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Biot's savarts law formula

Posted by Goutam Chouhan 1 month ago

CBSE > Class 12 > Physics

3 answers

Priyanshu Singh 2 weeks, 3 days ago

Munot upon 4pis idl sintetaupon r square

1Thank You

Manish Yadav 3 weeks, 2 days ago

Idlsintheta by r square

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Krish Agrawal 1 month ago

dB = (μ₀ / 4π) * (Idl × r) / r³

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(a) If one of two identical slits producing interference in Young's experiment is covered with glass, so that the light intensity passing through it is reduced to 50 %, find the ratio of the maximum and minimum intensity of the fringe in the interference pattern. (b) What king of fringes do you expect to observe if white light is used instead of monochromatic light?

Posted by Ekta Singla 1 month ago

CBSE > Class 12 > Physics

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What are the 2 postulates of Rutherford atomic module

Posted by Suraj Negi 1 month, 1 week ago

CBSE > Class 12 > Physics

1 answers

Krish Agrawal 1 month ago

Ernest Rutherford's atomic model, also known as the Rutherford model, was proposed in the early 20th century. It is primarily based on two key postulates: 1. **The Nucleus**: Rutherford postulated that an atom consists of a tiny, dense, and positively charged core at its center, known as the nucleus. This nucleus contains most of the atom's mass and is where the positively charged protons are located. Electrons orbit around the nucleus. 2. **Electron Orbits**: Rutherford proposed that electrons orbit the nucleus in well-defined, circular or elliptical paths. These orbits are sometimes referred to as electron shells or energy levels. Electrons in different shells have different energy levels, and they can jump from one energy level to another by absorbing or emitting energy in the form of electromagnetic radiation. Rutherford's model was groundbreaking because it replaced the earlier Thomson model, which depicted atoms as a "plum pudding" with electrons distributed throughout a positively charged sphere. Rutherford's experiments, most notably the famous gold foil experiment, provided evidence for the existence of the atomic nucleus and laid the foundation for our modern understanding of atomic structure. However, Rutherford's model had limitations and was eventually refined by Niels Bohr and others to account for the quantization of energy levels in electrons and the behavior of atoms in more detail.

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A transformer has 500 primary turns and 10 secondary turns. If the secondary has resistive load of 15 Ω, the currents in the primary and secondary

Posted by Gangana Pandey 1 month, 1 week ago

CBSE > Class 12 > Physics

1 answers

Krish Agrawal 1 month ago

To calculate the currents in the primary and secondary of a transformer, you can use the transformer equation, which relates the primary and secondary voltages and currents. The equation is: (Vp / Vs) = (Np / Ns) Where: - Vp is the primary voltage. - Vs is the secondary voltage. - Np is the number of turns in the primary coil. - Ns is the number of turns in the secondary coil. In your case, you have: - Np = 500 - Ns = 10 Now, let's calculate the primary voltage (Vp) and the secondary voltage (Vs). The primary voltage (Vp) is typically the voltage applied to the primary coil. To find it, you would need more information, such as the source voltage. Assuming you have the primary voltage (Vp), you can use the equation to find the secondary voltage (Vs): (Vp / Vs) = (Np / Ns) Vs = Vp * (Ns / Np) Now, we need to calculate the currents in the primary and secondary. Use Ohm's Law: I = V / R Where: - I is the current. - V is the voltage. - R is the resistance. For the secondary: - Vs is the voltage (which you've found). - The resistive load is 15 Ω. Isolate the secondary current (Is) and calculate it: Is = Vs / Rs Is = Vs / 15 Ω For the primary current (Ip), you can use the transformer equation again: (Vp / Vs) = (Np / Ns) Ip = Is * (Ns / Np) Substitute the values you have to calculate Ip. Please note that to get precise values, you would need the primary voltage (Vp). Without that information, you won't be able to calculate the exact currents in the primary and secondary coils.

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R1 in a lens is positive or negative?

Posted by Tushar Dulloo 1 month, 2 weeks ago

CBSE > Class 12 > Physics

1 answers

Krish Agrawal 1 month ago

The sign conventions for the radii of curvature (R1 and R2) for lenses are as follows: 1. **Convex Lens (Diverging Lens)**: - R1 (the radius of curvature of the first surface) is considered positive if the center of curvature is on the same side as the incident light (opposite to the direction of incoming light). - R2 (the radius of curvature of the second surface) is considered negative. 2. **Concave Lens (Converging Lens)**: - R1 (the radius of curvature of the first surface) is considered negative. - R2 (the radius of curvature of the second surface) is considered positive if the center of curvature is on the same side as the incident light (opposite to the direction of incoming light). These conventions are used in lens formula and mirror formula calculations to determine the sign of focal lengths and object distances.

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Question 1: A lens has a refractive index of 1.5 and a radius of curvature of 15 cm for one surface and 20 cm for the other surface. Calculate the difference in curvature between the two surfaces using the lens maker's formula Question 2: A concave lens with a refractive index of 1.4 is required to have a focal length of -12 cm. Determine the radil of curvature for the two lens surfaces using the lens maker's formula. Question 3: A biconvex lens with a refractive index of 1.6 has a known focal length of 25 cm. Calculate the difference in radii of curvature for its two surfaces using the lens maker's formula. Question 4 (Easy): A plano-concave lens has a refractive index of 1.2. The radius of curvature of the curved surface is 18 cm, and the flat side has a radius of curvature of infinity, Calculate the focal length of the lens using the lens maker's formula. Question 5 (Easy): A converging lens has a refractive index of 1.6. The radius of curvature of one surface is 12 om, and the radius of curvature of the other surface is 15 cm. Calculate the focal length of the lens using the lens maker's formula.

Posted by Tushar Dulloo 1 month, 2 weeks ago

CBSE > Class 12 > Physics

1 answers

Krish Agrawal 1 month ago

To answer each of your questions, we can use the lens maker's formula, which is given by: \[ \frac{1}{f} = (n - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right) \] Where: - \( f \) is the focal length of the lens. - \( n \) is the refractive index of the material. - \( R_1 \) is the radius of curvature of the first surface. - \( R_2 \) is the radius of curvature of the second surface. Let's solve each of your questions: **Question 1:** Given \( n = 1.5 \), \( R_1 = 15 \, \text{cm} \), and \( R_2 = 20 \, \text{cm} \), we need to calculate the difference in curvature between the two surfaces. Using the lens maker's formula, we can calculate the focal length, and then the difference in curvature. 1. Calculate \( \frac{1}{f} \) using the formula with the given values. 2. Once you find \( \frac{1}{f} \), calculate the focal length \( f \) by taking the reciprocal. **Question 2:** Given \( n = 1.4 \) and \( f = -12 \, \text{cm} \), we need to determine the radii of curvature for the two lens surfaces. Using the lens maker's formula, you can calculate \( R_1 \) and \( R_2 \). 1. Rearrange the lens maker's formula to solve for either \( R_1 \) or \( R_2 \). 2. Plug in the known values and solve for \( R_1 \) and \( R_2 \). **Question 3:** Given \( n = 1.6 \) and \( f = 25 \, \text{cm} \), we need to calculate the difference in radii of curvature for its two surfaces. Again, use the lens maker's formula to calculate \( R_1 \) and \( R_2 \). **Question 4:** Given \( n = 1.2 \), \( R_1 = 18 \, \text{cm} \), and \( R_2 = \infty \) for a flat side, calculate the focal length using the lens maker's formula. **Question 5:** Given \( n = 1.6 \), \( R_1 = 12 \, \text{cm} \), and \( R_2 = 15 \, \text{cm} \), calculate the focal length using the lens maker's formula. For each question, perform the calculations as described above, and you will have the answers you need. If you have any specific values to calculate or encounter any issues, feel free to ask for further assistance.

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The equation of progressive wave is y=0.01sin(100t-x)

Posted by Patcharu Sandeep 1 month, 3 weeks ago

CBSE > Class 12 > Physics

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What do you mean by magnetic confinement?

Posted by Gaurav Choudhary 1 month, 3 weeks ago

CBSE > Class 12 > Physics

0 answers

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कंसीडर थे फॉलोइंग रिएक्शन 1 h2 + 1h3 गिव्स तो he4 और + न + के कैलकुलेट द एनर्जी रिलीज इफ द मास्स ऑफ़ 1h2 इस 2.014102u और 1s 3 इस 3.0160949u मास ऑफ़ न्यूट्रॉन इस 1.008665 यू मास ऑफ़ 2 है 4 इस 4.00

Posted by Anshika Saxena 2 months ago

CBSE > Class 12 > Physics

0 answers

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Explain how OH group attached to a carbon in the Benzene ring activate the benzene towards electrophilic reaction

Posted by Haleema Khatoon 1 month, 3 weeks ago

CBSE > Class 12 > Physics

0 answers

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Tan inverse(25/12) ki value

Posted by Sunil Prajapat 2 months ago

CBSE > Class 12 > Physics

2 answers

Ankit Singh 1 month, 2 weeks ago

64° approx

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Gaurav Prabhakar 2 months ago

Pta nahi

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1m in cm

Posted by Yuvraj Singh 2 months ago

CBSE > Class 12 > Physics

4 answers

Krish Agrawal 1 month ago

100cm

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Rahul Chauhan 1 month, 2 weeks ago

100 cm

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Faizan Raja 1 month, 3 weeks ago

1M=100cm

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Sunil Prajapat 2 months ago

100 cm

4Thank You

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Power of combination of two concave lens derivation and formula

Posted by Soni Kushwaha 2 months ago

CBSE > Class 12 > Physics

2 answers

Krish Agrawal 1 month ago

The power of a combination of two concave lenses can be determined using the lens formula and the power formula for lenses. When lenses are in contact (i.e., their curved surfaces are facing each other), the formula to calculate their combined power is: \[ P_{\text{total}} = P_1 + P_2 \] Where: - \( P_{\text{total}} \) is the total power of the combination of lenses. - \( P_1 \) is the power of the first lens. - \( P_2 \) is the power of the second lens. The power \( P \) of a lens is given by: \[ P = \frac{1}{f} \] Where: - \( P \) is the power of the lens. - \( f \) is the focal length of the lens. If you have two concave lenses with focal lengths \( f_1 \) and \( f_2 \), you can calculate their individual powers as \( P_1 = \frac{1}{f_1} \) and \( P_2 = \frac{1}{f_2} \), respectively. Then, you can find the total power by adding these individual powers. So, to calculate the total power of a combination of two concave lenses, simply add their individual powers using the formula \( P_{\text{total}} = P_1 + P_2 \). This is applicable when the lenses are in contact. If they are separated by a distance, you would need to consider the separation between the lenses when calculating their combined power.

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Rahul Chauhan 1 month, 2 weeks ago

1/f1+1/f2=1/F

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