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Ritumoni Borgohain 3 years, 5 months ago

Vapour pressure of water,P1​=23.8 m of hg The weight of water=850 g        The weight of Urea=50 g  The molecular weight of water(H_2O)=1×2+16=18 g mol−1 molecular weight of urea (NH2​CONH2​)=2N+4H+C+O=2×14+4×1+12+16=60 g mol−1 Use formula            number of moles=molar massmass​ number of moles of water   n1​=18850​=47.22 number of moles of urea   n2​=6050​=0.83 Now, we have to calculate the vapour pressure of water in the solution. we take vapour pressure as P1​.         Use the formula of Raoult's law       P10​P10​−P1​​=n1​+n2​n2​​ plug the values we get 23.823.8−P1​​=47.22+0.830.83​ 23.823.8−P1​​=0.0173 23.8−P1​=23.8×0.0173 P1​=23.4 m Hg Vapour Pressure of water in the given solution=23.4 mm of Hg Relative lowering=0.0173
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Swaraj Bodke 3 years, 5 months ago

Pata nahi

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126
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All the processes which together keep the living organisms alive and perform task to maintain the body are called life processes

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Life process is the basic functions performed by organism to maintain their life in earth

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The process which are essential to sustain our life are called life process

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Life process is the basic functions performed by organism to maintain their life.
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pagal

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पक्षी को अनाज , जंगल और बहती हुई नदी से प्यार था

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