Posted by Swapna Shri 6 hours ago
Truly speaking p block is a vast chapter , full of reactions and different compounds. But if we arrange the things in a proper way , it's the easiest chapter ever. What I did was group the things together . I took large white sheets and arranged all the electronic configurations, chemical properties, physical properties, oxoacids , allotropes of Group 15 to 18 groupwise. On another sheets I noted down the chemical properties and reactions of different elements of each group like- Sulphur dioxide, Phosphine etc… This arrangement made the chapter easier for me .
Posted by Jashan . 1 day ago
Posted by Jashan . 1 day ago
Posted by Digvijaysingh 2717 2 days ago
|(i) Tetra phosphorus decoxide (P4O10)||Molecular|
|(ii) Ammonium phosphate (NH4)3PO4||Ionic|
|(iii) SiC||Network (covalent)|
|(vii) Graphite||Network (covalent)|
|(xi) Si||Network (covalent)|
Posted by Pooja Dhariwal 2 days, 2 hours ago
Posted by Preeti Yadav 2 days, 5 hours ago
Fluorine is more electronegative than chlorine, therefore, it can attract a shared pair of electron more easily and strongly than chlorine.
Thus, it can easily accept the pair of electrons and undergoes reduction. Thus it is a strong oxidizing agent than chlorine.
Posted by Harmoni Chauhan 2 days, 7 hours ago
In ionic compounds, electricity is conducted by ions. In solid state, ions are held together by strong electrostatic forces and are not free to move about within the solid. Hence, in molten state or in solution form, the ions are free to move and can conduct electricity.
Posted by Lil Bun 2 days, 19 hours ago
Posted by Kritika Parashar 3 days, 1 hour ago
Posted by Vishal Kumar 3 days, 4 hours ago
The reaction is
Here k = 2.5 × 10-4 M s-1
The order of the reaction is zero i.e.,
Rate = k [Reactant]o
Rate = 2.5 × 10-4 × 1 = 2.5 10-4 mol L-1 S-1
The rate of formation of N2 = 2.5 10-4 mol L-1 S-1
Therefore, rate of formation of H2 = 7.5 × 10-4 mol L-1 S-1
Posted by Avula Mastan 3 days, 5 hours ago
Volume of H2SO4 (V1) = 30 ml)
Diluted volume of H2SO4 (V2) = 500 ml
Number of moles present in 1000 mL of 0.5 M H2SO4 = 0.5 mol
Initial molarity M1= 0.5 M
We have to find M2 (molarity of 500 ml solution)
M2V2 = M1V1
M2 × 500 = 0.5 × 30
M2 = 15/ 500 = 0.03 M
Posted by Yaar 😍 3 days, 23 hours ago
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Posted by Sunaina Nazar 6 days, 17 hours ago
Posted by Shruti Duddi 1 week ago
Adsorption is always exothermic. This statement can be explained in two ways.
(i) Adsorption leads to a decrease in the residual forces on the surface of the adsorbent. This causes a decrease in the surface energy of the adsorbent. Therefore, adsorption is always exothermic.
(ii) ΔH of adsorption is always negative. When a gas is adsorbed on a solid surface, its movement is restricted leading to a decrease in the entropy of the gas i.e., ΔS is negative. Now for a process to be spontaneous, ΔG should be negative.
ΔG = ΔH - TΔS
Since ΔS is negative, ΔH has to be negative to make ΔG negative. Hence, adsorption is always exothermic.
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