Rājasthānī painting, the style of miniature painting that developed mainly in the independent Hindu states of Rājasthān in western India in the 16th–19th century. It evolved from Western Indian manuscript illustrations, though Mughal influence became evident in the later years of its development.

Yes, I agree that ‘Lost Spring’ explains the grinding poverty and traditions that condemn thousands of people to a life of abject poverty. 'Lost Spring' is a good narration of grinding poverty and traditions to which thousands of people have succumbed over decades. The story revolves around the pitiable condition of poor children who have been forced to live in slums and work hard in dirty conditions. The story is divided into two parts. The first part tells the writer's impression about the life of poor ragpickers who have migrated from Bangladesh but now have settled in the Seemapuri, on periphery of Delhi. These people are devoid of education, food and the basic amenities. So garbage is gold to them as ragpicking is their only means of survival.

The second part narrates the miserable life of the bangle makers in the town of Firozabad. The stark reality of these families is that in spite of back-breaking hard work that they put in, they cannot have two square meals a day. Besides, they are victims of exploitation by those above them and also suffer the consequences of blind belief in traditions. They cannot dare to dream to lead a better life.

Solution is given below:

{tex}\begin{aligned} & n(A \cup B)=n(A)+n(B)-n(A \cap B) \\ & n(B)=42-20+4=26 \\ & n(A-B)=n(A)-n(A \cap B)=20-4=16 \\ & n(B-A)=n(B)-n(A \cap B)=26-4=22 \end{aligned}{/tex}

1. 1 mole of C₂H₆ contains 2 moles of carbon atoms
   {tex}\therefore{/tex} 3 moles of C₂H₆ will C-atoms = 2 {tex}\times{/tex} 3  =  6 moles
2. 1 mole of C₂H₆ contains 6 moles of hydrogen atoms
   {tex}\therefore{/tex} 3 moles of C₂H₆ will contain H-atoms = 3 {tex}\times{/tex} 6  =   18 moles
3. 1 mole of C₂H₆ contains Avogadro's no., i.e. 6.02 {tex}\times{/tex} 10²³ molecules  of ethane
   {tex}\therefore{/tex} 3 moles of C₂H₆ will contain ethane molecules = 3 {tex}\times{/tex} 6.02 {tex}\times{/tex} 10²³ =  18.06 {tex}\times{/tex}10²³

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The word "transience feet" reflects the mortality of human life. Unlike the sea that undergoes little change over a span of hundred years, humans disappear from the face of earth within short periods of time. Hence, in these lines the feet are described as "transient feet" to represent human mortality.

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Bodhisattva Padmapani is a painting from cave no. 1 at Ajanta in central India late 5th century, likely 477. 1) This extraordinary mural painting survives from early medieval India, preserved in the interior of the rock-cut Buddhist monastery of Ajanta.

In this painting, a wild beast (bison) is shown raging and attacking a man. He has overpowered him as he has now surrendered and is lying on the ground.

Reasonable accuracy: The mathematical conclusion must be accurate based on the purpose of the investigation, its nature, size and available resources.

Protective Equipment : From helmets to cleats, new technology in sports equipment has revolutionized the way that manufacturers keep athletes safe from injury. Helmet manufacturers have produced helmets with technologically advanced materials to produce safe and more comfortable helmets.

Problems faced by Small Scale Industries
The following are the problems faced by Small Scale Industries:

1. Poor capacity utilization
   In many of the Small Scale Industries, the capacity utilization is not even 50% of the installed capacity. Nearly half of the machinery remains idle. Capital is unnecessarily locked up and idle machinery also occupies space and needs to be serviced resulting in increased costs.
2. Incompetent management
   Many Small Scale Industries are run in an incompetent manner by poorly qualified entrepreneurs without much skill or experience. Very little thought has gone into matters such as demand, production level and techniques, financial availability, plant location, future prospects etc. 
3. Inadequate Finance
   Many Small Scale Industries face the problem of scarcity of funds. They are not able to access the domestic capital market to raise resources. They are also not able to tap foreign markets by issuing ADR’s (American Depository Receipts) GDR’s (Global Depository Receipts) etc because of their small capital base. Banks and financial institutions require various procedures and formalities to be completed. Even after a long delay, the funds allocated are inadequate.
   Bank credit to the small scale sector as a percentage of total credit has been declining. It fell from 16% in 1999 to 12.5% in 2002. Small Scale Industries are not able to get funds immediately for their needs. They have to depend on private money lenders who charge high interest. Finance, as a whole, both long and short term, accounts for as large as 43% of the sector’s sickness.
4. Raw material shortages
   Raw materials are not available at the required quantity and quality.Scarcity of raw materials results in idle capacity, low production, inability to meet demand and loss of customers.
5. Lack of marketing support
   Small Scale Industries lack market knowledge with regard to competitors, consumer preferences, market trends. Since their production volume is small and cannot meet demand for large quantities their market is very restricted. Now with the process of liberalization and globalization they are facing competition from local industries as well as foreign competitors who sell better quality products at lower prices. For e.g. heavily subsidized but better quality imports from China has made most of the Indian SSI units producing toys, electronic goods, machine tools, chemicals, locks and paper etc., unviable.
6. Problem of working capital
   Many Small Scale Industries face the problem of inadequate working capital. Due to lack of market knowledge their production exceeds demand, and capital gets locked in unsold stock. They do not have enough funds to meet operational expenses and run the business.

The range of movements of joints is called flexibility.

Speed of a transverse wave on a stretched string. The wave velocity through a medium depends on its inertial and elastic properties. So the transverse wave through a stretched string is determined by two factors:

1. Tension T in the string is a measure in the string. Without tension no can propagate in the string. of elasticity disturbance Dimensions of T = [Force] = [MLT ²]
2. Mass per unit length or linear mass density m of the string so that the string can store kinetic energy.
   Dimensions of  {tex}m=\frac{[\text { Mass }]}{[\text { Length }]}=\left[\mathrm{ML}^{-1}\right]{/tex}
   Now, dimensions of ratio {tex}\frac{T}{m}=\frac{\left[\mathrm{MLT}^{-2}\right]}{\left[\mathrm{ML}^{-1}\right]}=\left[\mathrm{L}^{2} \mathrm{~T}^{-2}\right]{/tex}
   As the speed v has the dimensions [LT^-1] so we can express v in terms of T and m as {tex}v=C \sqrt{\frac{T}{m}}{/tex}
   From detailed mathematical analysis! or from experiments, the dimensionless constant C = 1. Hence the speed of transverse waves on a stretched string is given by
   {tex}v=\sqrt{\frac{T}{m}}{/tex}

Simple harmonic motion is an oscillatory motion in which the particle's acceleration and force are directly proportional to its displacement from the mean location at each point. It is a special case of oscillatory motion.

Gravitational waves stretch and squeeze the fabric of space and time on very minuscule scales; visually exaggerating these effects reveals how Earth is squeezed and stretched. Gravitational waves are generated when massive objects, such as pairs of black holes, accelerate through space and time.

Bernoulli's principle states that an increase in the speed of a fluid occurs simultaneously with a decrease in static pressure or a decrease in the fluid's potential energy.
To prove Bernoulli's theorem, consider a fluid of negligible viscosity moving with laminar flow. as shown in Figure.
Let the velocity, pressure and area of the fluid cloumn be p₁, v₁ and A₁ at Q and p₂, v₂ and A₂ at R. Let the  volume bounded by Q and R move to S and T where QS = L₁, and RT = L₂

If the fluid is incompressible:
The work done by the pressure difference per unit volume = gain in kinetic energy per unit volume + gain in potential energy per unit volume. Now:
A₁L₁ = A₂L₂
Work done is given by:
W = F {tex}\times{/tex} d = p {tex}\times{/tex} volume
{tex}\Rightarrow{/tex} W_net = p₁ - p₂
{tex}\Rightarrow{/tex} K.E = {tex}\frac{1}{2}{/tex}mv² = {tex}\frac{1}{2}{/tex}V {tex}\rho{/tex}v² = {tex}\frac{1}{2}{/tex}{tex}\rho{/tex}v² ({tex}\because{/tex} V = 1)
{tex}\Rightarrow{/tex} K.E_gained = {tex}\frac{1}{2} \rho\left(v_{2}^{2}-v_{1}^{2}\right){/tex}
P₁ + {tex}\frac{1}{2} \rho v_{1}^{2}{/tex} + {tex}\rho{/tex}gh₁ = P₂ + {tex}\frac{1}{2} \rho v_{2}^{2}{/tex} + {tex}\rho{/tex}gh₂
{tex}\therefore{/tex} P + {tex}\frac{1}{2} \rho v^{2}{/tex} + {tex}\rho{/tex}gh = const.
For a horizontal tube
{tex}\because{/tex} h₁ = h₂
{tex}\therefore{/tex} P + {tex}\frac{1}{2} \rho v^{2}{/tex} = const.
Therefore, this proves Bernoulli's theorem. Here we can see that if there is an increase in velocity there must be a decrease in pressure and vice versa.