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Divyansh Chouhan 2 years, 7 months ago (14402282)

Njsheb
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Saksham Sharma 2 years, 7 months ago (14477169)

Hh
  • 1 answers

Abhay Mehta 2 years, 7 months ago (14498576)

Hello
  • 2 answers

Aditi Tiwari 2 years, 8 months ago (14441710)

√1 =1 hence modulus of (1-i/1+i)¹⁰⁰ is 1

Aditi Tiwari 2 years, 8 months ago (14441710)

(1-i/1+i)¹⁰⁰ Multiple with conjugate of denominator =(1-i*1-i/1+i*1-i)¹⁰⁰ =(1-i-i+i²/1-(i)²)¹⁰⁰ =(1-2i+(-1)/1-(-1))¹⁰⁰ =(-2i/2)¹⁰⁰ =(-i)¹⁰⁰ =(-i)⁴*²⁵+⁰ =(1)¹⁰⁰ =1 In complex form =1+0i |z|= √1²+0² |z|=√1
http://mycbseguide.com/examin8/
  • 2 answers

Shambhavi Singh 2 years, 7 months ago (14408304)

Where is the stroy?

Shivansh Anand 2 years, 8 months ago (13069221)

Gyd6
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Samiksha Rajendra Laddha 2 years, 7 months ago (9323254)

In the first line of the chapter there it is clearly written that The thought came to a {{certain}} king
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  • 4 answers

Sumit Kumar Roy 2 years, 8 months ago (13928158)

-2

Viraj Parmar 2 years, 8 months ago (12376602)

-30

‌Himani Syunary 2 years, 8 months ago (10472860)

I Don't know 😶😶😔

Sushil Giri 2 years, 8 months ago (14400099)

Hi
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Ambika Sharma 2 years, 8 months ago (14407172)

This will not be added because its under root is different.
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Muskan Jatav 2 years, 8 months ago (14425539)

What do you mean by federalism
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Suruchi Saumya 2 years, 8 months ago (14339233)

Square root
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