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When they heard of the Non-Cooperation Movement thousands of workers defied the authorities left the plantations and headed home. iii They believed that Gandhi Rai was coming and everyone would be given land in their own village. iv They however never reached their destination.
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Make is the answer. The subject is plural so it is followed by a plural verb form.
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Preeti Dabral 3 years ago
The boiling point of the solution is 273.41 k
GIVEN
Weight of urea = 6 grams
weight of Glucose = 9 grams.
Weight of water = 300 grams
TO FIND
The boiling point of the solution.
SoOLUTION
We can simply solve the given problem as follows-
To calculate the boiling point of the solution, we will apply the following formula -
∆Tₒ = Kb× b × i (eq 1)
Where,
∆Tₒ = boiling point elevation
Kb = ebullioscopic constant of the solvent ( kb = o.515 kg/mol)
b = molality of the solute
i = van't Hoff factor of solute ( since urea and glucose are non-ionic compounds, so, i= 1)
We know that,
Boiling point elevation is defined as :
ΔTₒ = T₁ - T ........(eq2)
where,
T₁ = boiling point of the solution
T = boiling point of the solvent (T = 273.15 k of water)
Now,
{tex}\begin{aligned} & \text { number of moles of urea }=\frac{\text { given weight of urea }}{\text { molar mass of urea }} \\ & = \\ & \frac{6}{60}=0.1 \text { moles } \\ & \text { number of moles of glucose }=\frac{\text { given weight of glucose }}{\text { molar mass of glucose }} \\ & =\frac{9}{180}=0.05 \text { moles } \\ & \text { Total moles of solute }=0.1+0.05=0.15 \text { moles } \\ & \text { molality of solute }(b)=\frac{\text { moles of solute }}{\text { mass of solvent in } \mathrm{kg}} \\ & b=\frac{0.15 \times 1000}{300} \\ & b=0.5 \mathrm{M} \end{aligned}{/tex}
putting the values in ( eq 1) we have
ΔTₒ = 0.512 × 0.5 × 1
ΔTₒ = 0.26 k
Now, putting the value of ΔTₒ in (eq 2)
ΔTₒ = T₁ - T
0.26 = T₁ - 273.15
T₁ = 273.15 + 0.26
T₁ = 273.41 k
Hence, The boiling point of the solution is 273.41 k
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Avi Garg 3 years, 2 months ago
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