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Preeti Dabral 2 years, 9 months ago
= 8^2/3 -√9×10^0=(1/144)^-1/2
= (2^3)^2/3 - √3^2 x 1 + (1/12^2)-1/2
= 2^3 - 3 + (12^2)^1/2
= 4-3+12
= 13
Posted by Sai Shivram Sahoo 2 years, 10 months ago
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Posted by Ritesh Rajput 2 years, 9 months ago
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Preeti Dabral 2 years, 9 months ago
Control Structures can be considered as the building blocks of computer programs. They are commands that enable a program to “take decisions”, following one path or another. A program is usually not limited to a linear sequence of instructions since during its process it may bifurcate, repeat code or bypass sections.
Posted by Prakriti Acharya 2 years, 10 months ago
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Nirvan Chawla 2 years, 10 months ago
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Preeti Dabral 2 years, 9 months ago
In most displays and digital images, resolution is expressed as PPI, which refers to the number of pixels that can be displayed over one inch of the screen or display. A high PPI means there are more pixels in every inch, which results in a higher resolution and a crisper image.
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Mfj6Chj Jvnvfmmh 2 years, 10 months ago
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Vaishh Hh 2 years, 10 months ago
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Posted by Shyam Kumar 2 years, 10 months ago
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Preeti Dabral 2 years, 9 months ago
Given Principal = ₹ 200000
Rate = 12% Compounded annually
Interest after 1year (I1) ={tex}\frac{200000 \times 12 \times 1}{100}{/tex}
= 2000 {tex}\times{/tex} 12
= ₹ 24000
The interest accrued is subject to income tax at 25% at the end of each year.
So, Income tax on 24000 = 25% of 24000
= {tex}\frac{25}{100} \times {/tex} 24000 = ₹6000
Principal after 1year & after income tax.
= 200000 + 24000 - 6000
= ₹218000
Interest after 2nd year (I2) {tex}=\frac{218000 \times 12 \times 1}{100}{/tex}
= ₹ 2180 {tex}\times{/tex} 12 = ₹ 26160
{tex}=\frac{25}{100} \times {/tex} 26160
= ₹6540
Amount after 2 year and after income tax
= 218000 + 26160 - 6540
= ₹ 237620
Posted by Priya Kumari 2 years, 10 months ago
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Shamsul Qamar 2 years, 3 months ago
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Monu Dahiya 2 years, 10 months ago
1Thank You