$$\int\limits _{0}^{x} F dx \\ \int\limits _{0}^{x} kxdx \\ k \int\limits _{0}^{x}xdx \\ k \displaystyle [\dfrac{x^2}{2}]^x _0 \\ k \displaystyle [\dfrac{x^2}{2} - \dfrac{0}{2}] \\ \dfrac{kx^2}{2} $$

to convert acetic acid to ethane Lets convert this acetic acid to ammonium acetate then from that we can convert it to Acetamide and form that it can be converted to acetonitrile.Now from acetonitrile it can easily converted to any X-CH3 where X is a halogen and from that X-CH3 it can be converted to ethane by wurtz reaction beacuase ethane has even number of carbon atom. 1.CH3COOH→CH3COONH4 2. CH3CONH4→CH3CONH2 3. CH3CONH2→CH3CN 4. CH3CN+KBr→CH3Br 5. CH3Br+2Na+BrCH3→CH3-CH3+2NaBr Here in Reaction 1) NH3 is added with heat. 2)P2O5 is added with heat. 3)P2O5 is added with heat 4)its an nucleophilic substitution reaction. 5)its called wurtz reaction.

Virat Kohli

Virat kohli

Virat Kohli

As of 1 May 2020, India is ranked third in Tests, second in ODIs and third in T20 Is by the ICC. Virat Kohli is the current captain of the team across all formats, while the head coach is Ravi Shastri.

Augmented assignment is the combination, in a single statement, of a binary operation and an assignment statement. ...

e.g. a += 1 means a is assigned a+1. They are useful because they reduce the length of the code and make it look cleaner.

Work=F.d=(3i+4j-6k).(6i-2j-k) = (3×6)+(4×-2)+(-6×-1) = 18+(-8)+6= 16J Power=work÷time =16÷2 =8 watt

Among  molecule the energy required to break the first N-H bond and other N-H bond is not same" is true.

The reason for this is -

• Dissociation energy for the bond of  that is of N-H and  species gets decreased in its value.

• This means that the breaking of first N-H bond of ammonia molecule during dissociation requires more energy or the highest energy among all the further dissociation.

Assume a perfect sphere-shaped planet of radius R and mass M. Now, if a body of mass m is projected from a point A on the surface of the planet. An image is given below for better representation:

sIn the diagram, a line from the center of the planet i.e. O is drawn till A (OA) and extended further away from the surface. In that extended line, two more points are taken as P and Q at a distance of x and dx respectively from the center O.

Now, let the minimum velocity required from the body to escape the planet b

ve

Thus, Kinetic Energy will be

At point P, the body will be at a distance x from the planet’s center and the force of gravity between the object and the planet will be:

To take the body from P to Q i.e. against the gravitational attraction, the work done will be->

Now, the work done against the gravitational attraction to take the body from the planet’s surface to infinity can be easily calculated by integrating the equation for work done within the limits x=R to x=∞.

Thus,

By integrating it further, the following is obtained:

Thus, the work done will be:

Now, to escape from the surface of the planet, the kinetic energy of the body has to be equal to the work done against the gravity going from the surface to infinity. So,

K.E. = W

Putting the value for K.E. and Work, the following equation is obtained:

From this equation, the escape velocity can be easily formulated which is:

Putting the value of g = GM, the value of escape velocity becomes:

From this equation, it can be said that the escape velocity depends on the radius of the planet and the mass of the planet only and not on the mass of the body.

Escape Velocity of Earth:

From the above equation, the escape velocity for any planet can be easily calculated if the mass and radius of that planet are given. For earth, the values of g and R are:

g = 9.8 m

R = 63,781,00 m

So, the escape velocity will be:

ve=2×9.8×63,781,00−−−−−−−−−−−−−−−−√

Escape Velocity of Earth= 11.2 km/s.

Hlo

Using pythagoras theorem, resultant displacement is 5 metres due north - east.

5 metres

 

The inner core, the outer core, mantle and crust are the four layers of earth

The Inner Core

It is the centre and the hottest layer of the Earth. The inner core is solid and made up of iron and nickel with temperature up to 5,500^oC. Due to its immense <a href="https://byjus.com/physics/heat-energy/" rel="noopener" target="_blank">heat energy</a>, the inner core is more like the engine room of the Earth.

The Outer Core

The outer core of the Earth is similar to a very hot ball of metals, whose temperature is around 4000 ^oF to 9000⁰F. It is so hot that the metals inside are all in the liquid state. The outer core is located around 1800 miles under the crust and approximately 1400 miles thick. It is composed of metals such as iron and nickel. The outer core surrounds the inner core.

The inner core has pressures and temperatures so high that the metals are squeezed together and not able to move like a liquid, but are forced to vibrate instead of solid.

Mantle

Mantle is the widest section of the Earth. Its thickness is approximately 2,900 km. The mantle is mainly made up of semi-molten rock known as magma. The rock is hard in the upper part of the mantle, but lower down the rock is softer and begins to melt.

The mantle is located directly under the Sima. The mantle consists of very hot and dense rock. This layer of rock flows like asphalt under heavy weight. This flow is because of the greatest temperature differences from the bottom to the top of the mantle. The reason behind the plates of the Earth move is the movement of the mantle. Its temperature varies between 1600 oF at the upper part to 4000 oF near the bottom.

Crust

The crust is the outer layer where we live. The thickness is around 0-60 km. It’s a solid rock layer divided into two types:

1. Continental crust covers the land and,
2. Oceanic crust covers water

The crust is the most widely studied and understood. Mantle is hotter and capable of flowing. The outer and inner core are much hotter with great pressures that you can be squeezed into a ball smaller than a marble if you are able to go in the center of the Earth.

Where are the options?

Domain=all real numbers Range=all non positive real numbers

Enthalpy of vaporization is the amount of energy that must be supplied to the liquid in order to change the liquid into a gas. Enthalpy is also regarded as boiling temperature of the liquid. 

Acetone does not have hydrogen bond, and thus intermolecular forces are comparatively weaker which makes it boil/evaporates fast, thus reducing the molar enthalpy of vaporization. Also, Acetone does not polar O-H bond contributing to low enthalpy. 

Water has non-polar region and also has strong hydrogen bond. Water has highly polar O-H bond which makes water boil at relatively higher temperature than Acetone thus has enthalpy greater than that of Acetone. 
 

Principle of Subrogation

Subrogation means one party stands in for another. As per this principle, After the insured, i.e. the individual has been compensated for the incurred loss to him on the subject matter that was insured, the rights of the ownership of that property goes to the insurer, i.e. the company.

Subrogation gives the right to the insurance company to claim the amount of loss from the third-party responsible for the same.

Example – If Mr A gets injured in a road accident, due to reckless driving of a third party, the company with which Mr A took the accidental insurance will compensate the loss occurred to Mr A and will also sue the third party to recover the money paid as claim. 

Ranga did not want to get married at an early age. He wanted to find the right girl. She should be mature enough to understand his love talk. Secondly, he wished to marry a girl he admired. He was against marrying quite young girls who had no manners or were not careful of their face or figure.

Three themes present in "Thank You, Ma'am" are Forgiveness and Empathy, the Power of Love and Trust, and Christian Charity. While she prepares the meal, Mrs. Jones leaves her purse on the other side of the screen where she cooks. Roger worries that she may not trust him, so he moves where he hopes she can see him.

Gud eve dono ko??

DELETED PORTION MATHEMATICS - 041 CLASS XI UNIT/ CHAPTER SYLLABUS REDUCED Unit- I: Sets and Functions 1.Sets Difference of sets. Complement of a set. Properties of Complement 2.Relations & Functions (up to RXRXR ). Sum, Difference, product and quotients of functions 3. Trigonometric Functions General Solutions of trigonometric equations of the type siny=sina, cosy=cosa and tany= tana. Unit II: Algebra 1.Principle of Mathematical Induction Delete full chapter 2.Complex Numbers and Quadratic Equations Polar representation of complex numbers. Square root of a complex number. 3.Linear Inequalities Nil 4. Permutations and Combinations Derivationof formulae for nPrandnCr 5.Binomial theorem Delete full Chapter 6. Sequence and Series Formulae for the following special sums ∑ ?,∑k2,∑ ?3 . Unit III: Coordinate geometry 1.Straight Lines Shifting of origin. Equation of family of lines passing through the point of intersection of two lines. 2 Conic sections a point, a straight line and a pair of intersecting lines as a degenerated case of a conic section. 3.Introduction to Three-dimensional Geometry Nil Unit-IV : Calculus 1.Limits and Derivatives Nil Unit-V : Mathematical Reasoning 1.Mathematical Reasoning Delete full chapter Unit-VI: Statistics and Probability 1. Statistics Analysis of frequency distributions with equal means but different variances. 2. Probability Axiomatic (set theoretic) probability, connections with other theories of earlier classes

Let the three numbers be a,ar, ar2, where r is the common ratio. ⇒a+ar+ar2=28 and a3r3=512 ⇒ar=8⇒a+ar2=20 ⇒8r2−20r+8=0 ⇒r=2,r=21​ If r=2,a=4 Therefore, the three numbers are 4,8,16

The three numbers in GP are 4 , 8 , 16.

• Let the three numbers in GP be a/r , a , ar.
• Now the product of three numbers is given as 512.

a/r × a × ar = 512

a³ = 512

a = 8

• Now sum of the three numbers is given as 28.

a/r + a + ar = 28

8/r + 8 + 8r = 28

8 + 8r² = 20r

8r² - 20r + 8 =0

8r² - 16r - 4r + 8 =0

8r(r-2) - 4(r-2) = 0

(r-2)(8r-4) = 0

• Therefore, r = 2 or r=1/2
• Now , the  three numbers are 4,8,16.

Dimensional Formulas for Physical Quantities Physical quantityUnitDimensional formulaAcceleration or acceleration due to gravity ms–2 ,LT–2,Angle (arc/radius)rad,MoLoTo ,Angular displacementrad,MoloToAngular frequency (angular displacement/time)rads–1T–1Angular impulse (torque x time)NmsML2T–1Angular momentum (Iω)kgm2s–1ML2T–1Angular velocity (angle/time)rads–1T–1Area (length x breadth)m2L2Boltzmann’s constantJK–1ML2T–2θ–1Bulk modulus (\Delta P.\frac{V}{\Delta V}ΔP.ΔVV​.)Nm–2, PaM1L–1T–2Calorific valueJkg–1L2T–2Coefficient of linear or areal or volume expansionoC–1 or K–1θ–1Coefficient of surface tension (force/length)Nm–1 or Jm–2MT–2Coefficient of thermal conductivityWm–1K–1MLT–3θ–1Coefficient of viscosity (F =\eta A\frac{dv}{dx}ηAdxdv​)poiseML–1T–1Compressibility (1/bulk modulus)Pa–1, m2N–2M–1LT2Density (mass / volume)kgm–3ML–3Displacement, wavelength, focal lengthmLElectric capacitance (charge/potential)CV–1, faradM–1L–2T4I2Electric conductance (1/resistance)Ohm–1 or mho or siemenM–1L–2T3I2Electric conductivity (1/resistivity)siemen/metre or Sm–1M–1L–3T3I2Electric charge or quantity of electric charge (current x time)coulombITElectric currentampereIElectric dipole moment (charge x distance)CmLTIElectric field strength or Intensity of electric field (force/charge)NC–1, Vm–1MLT–3I–1Electric resistance (\frac{potential\text{ difference}}{current}currentpotential difference​)ohmML2T–3I–2Emf (or) electric potential (work/charge)voltML2T–3I–1Energy (capacity to do work)jouleML2T–2Energy density (\frac{energy}{volume}volumeenergy​)Jm–3ML–1T–2Entropy (\Delta S=\Delta Q/TΔS=ΔQ/T)Jθ–1ML2T–2θ–1Force (mass x acceleration)newton (N)MLT–2Force constant or spring constant (force/extension)Nm–1MT–2Frequency (1/period)HzT–1Gravitational potential (work/mass)Jkg–1L2T–2Heat (energy)J or calorieML2T–2Illumination (Illuminance)lux (lumen/metre2)MT–3Impulse (force x time)Ns or kgms–1MLT–1Inductance (L) (energy =\frac{1}{2}L{{I}^{2}}21​LI2) or coefficient of self-induction henry (H)ML2T–2I–2Intensity of gravitational field (F/m)Nkg–1L1T–2Intensity of magnetization (I)Am–1L–1IJoule’s constant or mechanical equivalent of heatJcal–1MoLoToLatent heat (Q = mL)Jkg–1MoL2T–2Linear density (mass per unit length)kgm–1ML–1Luminous fluxlumen or (Js–1)ML2T–3Magnetic dipole momentAm2L2IMagnetic flux (magnetic induction x area)weber (Wb)ML2T–2I–1Magnetic induction (F = Bil)NI–1m–1 or TMT–2I–1Magnetic pole strength (unit: ampere–meter)AmLIModulus of elasticity (stress/strain)Nm–2, PaML–1T–2Moment of inertia (mass x radius2)kgm2ML2Momentum (mass x velocity)kgms–1MLT–1Permeability of free space (\mu_o = \frac{4\pi Fd^{2}}{m_1m_2}μo​=m1​m2​4πFd2​)Hm–1 or NA–2MLT–2I–2Permittivity of free space ({{\varepsilon }_{o}}=\frac{{{Q}_{1}}{{Q}_{2}}}{4\pi F{{d}^{2}}}εo​=4πFd2Q1​Q2​​.)Fm–1 or C2N–1m–2M–1L–3T4I2Planck’s constant (energy/frequency)JsML2T–1Poisson’s ratio (lateral strain/longitudinal strain)––MoLoToPower (work/time)Js–1 or watt (W)ML2T–3Pressure (for

ammonium cyanate

Urea

No question bank is right to read you have to just see your headings carefully. And just remind about your previous learning about that topic. It is one of the best way to review before examination. I hope if you will do it, you will get better result.

No , just take a look to all topic , and read the topic you didn't prepared yet. And yes, don't forget to rewind each and Every formula ,,
☻☻To bas padhai karte rahe, All the very best ☻☻