Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Abhinav Srivastava 3 years ago
- 2 answers
Hooda 23578 3 years ago
Posted by Rahul Singh 3 years ago
- 3 answers
Rama Debbarma 3 years ago
Few rules to keep homework help section safe, clean and informative.
- Don't post personal information, mobile numbers and other details.
- Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
- Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
- Ask specific question which are clear and concise.
Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.
Posted by Ritika Gupta 3 years ago
- 1 answers
Krish Agarwal 3 years ago
Few rules to keep homework help section safe, clean and informative.
- Don't post personal information, mobile numbers and other details.
- Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
- Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
- Ask specific question which are clear and concise.
Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.
Posted by Yash Dansena 3 years ago
- 1 answers
Pranav Rijhwani 3 years ago
Posted by Shivam Bansal 3 years ago
- 0 answers
Posted by Hooda 23578 3 years ago
- 2 answers
Posted by Divya Dalpatia 3 years ago
- 1 answers
Posted by Divya Dalpatia 3 years ago
- 0 answers
Posted by Divya Dalpatia 3 years ago
- 0 answers
Posted by Chandan Jain Chandan Jain 3 years ago
- 0 answers
Posted by Omansh Gupta 3 years ago
- 1 answers
Posted by Vansh Sharma 3 years, 1 month ago
- 1 answers
Posted by Roshan Sahu 3 years, 1 month ago
- 1 answers
Posted by Alka Singh 3 years, 1 month ago
- 2 answers
Posted by Shiv. Kumar 3 years, 1 month ago
- 0 answers
Posted by Shiv. Kumar 3 years, 1 month ago
- 0 answers
Posted by Shravani Mahagade 3 years, 1 month ago
- 1 answers
Posted by Prithvi Raj Jangid 3 years ago
- 1 answers
Preeti Dabral 3 years ago
We are given that, p = 4 and ω = 150
Now, {tex}\cos 15^{\circ}=\frac{\sqrt{3}+1}{2 \sqrt{2}}{/tex}
and {tex}\sin 15^{\circ}=\frac{\sqrt{3}-1}{2 \sqrt{2}}{/tex}
The equation of the line is x cos ω + y sin ω = p
{tex}x \cos 15^{\circ}+y \sin 15^{\circ}{/tex}
or {tex}\frac{\sqrt{3}+1}{2 \sqrt{2}} x+\frac{\sqrt{3}-1}{2 \sqrt{2}} y=4{/tex}
or {tex}(\sqrt{3}+1) x+(\sqrt{3}-1) y=8 \sqrt{2}{/tex}
This is the required equation.
Posted by Aditya Chauhan 3 years, 1 month ago
- 0 answers
Posted by Bhumi Bhatt 3 years, 1 month ago
- 0 answers
Posted by Ishu Anand 3 years, 1 month ago
- 2 answers
Posted by Mokshika Sharma 3 years, 1 month ago
- 2 answers
Saptak Das 3 years, 1 month ago
Posted by Sachin Kumar 3 years, 1 month ago
- 1 answers
Posted by Mohit Pathak 3 years, 1 month ago
- 0 answers
Posted by Avinash Alawa 3 years, 1 month ago
- 2 answers
Rohit Patel 3 years, 1 month ago
Posted by Liza Barman 3 years, 1 month ago
- 2 answers
Niha Kamali 3 years ago
Posted by Liza Barman 3 years, 1 month ago
- 1 answers
Anshi Singh 3 years ago

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Shahil Singh 3 years ago
0Thank You