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Posted by Suman Sharma 3 years, 3 months ago (13788599)
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Vikash Kumar 3 years, 3 months ago (13789474)
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Swastika, Yeshvi Kumari, Kumari 3 years, 3 months ago (13797791)
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Saini.Satwinder Saini Satwinder 3 years, 3 months ago (13334050)
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Divya Kumari 3 years, 3 months ago (13382633)
Sujeet Kumar 3 years, 3 months ago (13797019)
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Preeti Dabral 3 years, 3 months ago (2983787)
A carbon footprint is the total amount of greenhouse gases (including carbon dioxide and methane) that are generated by our actions. The average carbon footprint for a person in the United States is 16 tons, one of the highest rates in the world.
Aanya Sharma 3 years, 3 months ago (13709873)
Posted by Simrat Raj 3 years, 3 months ago (11257098)
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Kashu Verma 3 years, 3 months ago (13616747)
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Manya & Keshav Garg 3 years, 3 months ago (13240109)
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Ruhani Arora 3 years, 3 months ago (9206609)
Posted by Suman Sharma 3 years, 3 months ago (13788599)
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Posted by Nitin Kumar 3 years, 3 months ago (10137650)
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Posted by Dhruv Sharma 3 years, 3 months ago (13788427)
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Preeti Dabral 3 years, 3 months ago (2983787)
|
BAL VIKAS PUBLIC SCHOOL, AMBALA NOTICE 17th February 2019 Library Book Lost A library book has been lost. The book is NCERT Maths and it bears the library stamp. The book has a blue cover on it. If found, please return to the undersigned. |
Posted by Akshitha Meghana 3 years, 3 months ago (13788286)
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Posted by Bishal Rawani 3 years, 3 months ago (12738793)
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Preeti Dabral 3 years, 3 months ago (2983787)
as men went to battle, women stepped in to undertake jobs that earlier only men were expected to do. The war led to the snapping of economic links between some of the world's largest economic powers which were now fighting each other to pay for them.
Posted by Kajal Akash Bansal 3 years, 3 months ago (13788147)
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Posted by E.Malathi E.Malathi 3 years, 3 months ago (13638552)
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Preeti Dabral 3 years, 3 months ago (2983787)
the ability to move freely or be easily moved: Some neck injuries cause total loss of mobility below the point of injury.
Posted by Dhanya G Kulkarni 3 years, 3 months ago (12759423)
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Dhanya G Kulkarni 3 years, 3 months ago (12759423)
Posted by Arvind Kumar 3 years, 3 months ago (13787861)
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Preeti Dabral 3 years, 3 months ago (2983787)
{tex}\text { Let } \alpha \text { and } \beta \text { are the zeroes of the polynomial } f(x)=a x^2+b x+c \text {. }{/tex}
{tex}\therefore \quad(\alpha+\beta)=\frac{-\mathbf{b}}{\mathbf{a}} and \alpha \beta=\frac{\mathbf{c}}{\mathbf{a}} According to the question, \frac{1}{\alpha} and \frac{1}{\beta} are the zeroes of the required quadratic polynomial{/tex}
Sum of zeroes of required polynomial
{tex} \begin{aligned} \mathbf{S}^{\prime} & =\frac{1}{\alpha}+\frac{1}{\beta} \\ & =\frac{\alpha+\beta}{\alpha \beta} \\ & =\frac{-\mathbf{b}}{\mathbf{c}} \end{aligned} [From equation (i) and (ii)] and product of zeroes of required polynomial =\frac{1}{\alpha} \times \frac{1}{\beta}. P^{\prime}=\frac{1}{\alpha \beta} =\frac{a}{c} [From equation (ii)]{/tex}
Equation of the required polynomial.
{tex} =\mathbf{k}\left(\mathbf{x}^2-\mathbf{S}^{\prime} \mathbf{x}+\mathbf{p}^{\prime}\right) where $k$ is any non-zero constant =k\left(x^2-\left(\frac{-b}{c}\right) x+\frac{a}{c}\right) [From equation (iii) and (iv)] =k\left(x^2+\frac{b}{c} x+\frac{a}{c}\right) {/tex}
Posted by Shiv Santosh Kushwaha 3 years, 3 months ago (13617393)
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Posted by Pem Lhamu Sherpa 3 years, 3 months ago (13786540)
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Aman Chaurasiya 2 years, 8 months ago (10288913)
3 Thank You