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Farhat Shaikh Shaikh 6 years, 6 months ago
Posted by Ashu Kumar 6 years, 6 months ago
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Posted by Susmita Majhi 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
We know that, {tex}v = \frac { d x } { d t }{/tex}
{tex}v = \frac { d } { d t } ( a + b t ^2){/tex}= 2bt = 5t m/s (i)
at t = 0, from equation (i) we have v = 0,
at t = 2 from equation (i) we have v = 10 m/s
Average velocity = {tex}\frac { x ( 3 ) - x ( 2 ) } { 3 - 2 } = \frac { a + 9 b - a - 4 b } { 1 }{/tex}
= {tex}5 \times b = 5 \times 2.5{/tex}= 12.5 m/s
Posted by Sadhana Raheza 6 years, 6 months ago
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Posted by Surendra Jangir 6 years, 6 months ago
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Posted by Aniketa Kumari 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
The given system of equations is
{tex}3x - \frac{{y + 7}}{{11}} + 2 = 10{/tex} ...(i)
{tex}2y + \frac{{x - 11}}{7} = 10{/tex} ....(ii)
From (i), we get
{tex}\frac{{33x - y - 7 + 22}}{{11}} = 10{/tex}
{tex}\Rightarrow{/tex} {tex}33x - y + 15 = 10 × 11{/tex}
{tex}\Rightarrow{/tex} {tex}33x + 15 - 110 = y{/tex}
{tex}\Rightarrow{/tex} {tex}y = 33x - 95{/tex}
From (ii), we get
{tex}\frac{{14y + x + 11}}{7} = 10{/tex}
{tex}\Rightarrow{/tex} {tex}14y + x + 11 = 10 × 7{/tex}
{tex}\Rightarrow{/tex} {tex}14y + x + 11 = 70{/tex}
{tex}\Rightarrow{/tex} {tex}14y + x = 70 - 11{/tex}
{tex}\Rightarrow{/tex} {tex}14y + x = 59{/tex} ....(iii)
Substituting y = 33x - 95 in (iii), we get
14(33x - 95) + x = 59
{tex}\Rightarrow{/tex} 462x - 1330 + x = 59
{tex}\Rightarrow{/tex} 463x = 59 + 1330
{tex}\Rightarrow{/tex} 463x = 1389
{tex}\Rightarrow x = \frac{{1389}}{{463}} = 3{/tex}
Putting x = 3, in y = 33x - 95, we get
y = 33 {tex}\times{/tex} 3 - 95
{tex}\Rightarrow{/tex} y = 99 - 95 = 4
{tex}\Rightarrow{/tex} y = 4
Hence, Solution of the given system of equation is x = 3, y = 4.
Posted by Amanpreet Singh Singh 6 years, 6 months ago
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Posted by Neharika Rai 6 years, 6 months ago
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Ananya Bhimsaria 6 years, 6 months ago
Posted by Kabir Dhankhar 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
Instructive (comparative more instructive, superlative most instructive) Conveying knowledge, information or instruction.
Well, that was an instructive lesson.
Posted by Jagdeep Kaur 6 years, 6 months ago
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Posted by James Bhatti 6 years, 6 months ago
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Yogita Ingle 6 years, 6 months ago
- They have a long and segmented body.
- Annelids are bilaterally symmetrical.
- They are triploblastic.
- Also, they exhibit organ system grade of organisation, showing organ differentiation.
- The body is covered with a thin cuticle.
- They are coelomate. A body cavity or coelom is present.
- Annelids live in moist environments, moist soil, freshwater and marine water.
- They have parapodia and chitinous setae, used for locomotion.
- Their body appears red due to the presence of haemoglobin.
- Excretory and nervous systems are present.
- The digestive system is complete and developed.
Posted by Narendra Singh Bhadoriya 6 years, 6 months ago
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Yash Goswami????? 6 years, 6 months ago
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Diksha Rathor 6 years, 6 months ago
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Ananya Bhimsaria 6 years, 6 months ago
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Komal Sharma 6 years, 6 months ago
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Japisher Singh 6 years, 6 months ago

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Kaushal Kumar Kaushal Kumar 6 years, 6 months ago
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