• Not all stress is harmful. You can remain motivated, focused, and capable of taking on new challenges at work with a little bit of stress. It keeps you alert and on your toes during presentations so you can avoid mishaps or expensive errors.
• But in today's busy world, the office seems like an emotional roller coaster all too frequently. You might feel stressed, worn out, and overburdened as a result of long hours, strict deadlines, and rising demands. And when stress becomes too much for you to handle, it stops being beneficial and starts harming your mind, body, and job satisfaction.
• Summary of The Tale of Melon City in English. Through this poem, Vikram Seth mocks those in positions of authority. He has amusingly put forth the idea that as long as people can live in peace, liberty, and decency.
• The poem "The Tale of a Melon City" describes how the city found a melon as its new King. In the course of the narrative, their King commands the construction of an arch, but it ends up being too low. It struck the King, knocking his crown off his head.

Intellectual disability is a term used when there are limits to a person's ability to learn at an expected level and function in daily life. Levels of intellectual disability vary greatly in children.

Distance to market s=2.5km=2.5×10³ =2500m

Speed with which he goes to market =5km/h={tex}5 \frac{10^3}{3600}=\frac{25}{18} \mathrm{~m} / \mathrm{s}{/tex}

Speed with which he comes back = {tex}7.5 \mathrm{~km} / \mathrm{h}=7.5 \times \frac{10^3}{3600}=\frac{75}{36} \mathrm{~m} / \mathrm{s}{/tex}

(a)Average velocity is zero since his displacement is zero.

(b) (i)Since the initial speed is 5km/s and the market is 2.5 km away,time taken to reach market: {tex}\frac{2.5}{5}=1 / 2 \mathrm{~h}=30 \text { minutes. }{/tex}

Average speed over this interval =5km/h

(ii)After 30 minutes,the man is travelling wuth 7.5 km/h speed for 50-30=20 minutes.The distance he covers in 20 minutes :{tex}7.5 \times \frac{1}{3}=2.5 \mathrm{~km}{/tex}

His average speed in 0 to 50 minutes: V_avg ​ =distance traveled/time {tex}=\frac{2.5+2.5}{(50 / 60)}=6 \mathrm{~km} / \mathrm{h}{/tex}

(iii)In 40-30=10 minutes he travels a distance of : {tex}7.5 \times \frac{1}{6}=1.25 \mathrm{~km}{/tex}

{tex}\mathrm{V}_{\mathrm{avg}}=\frac{2.5+1.25}{(40 / 60)}=5.625 \mathrm{~km} / \mathrm{h}{/tex}

As the depth increased the mass of the earth decreases. At the surface of earth this value will be maximum because radius will be maximum. When radius becomes less this value also decreases. Hence acceleration due to gravity decreases with increase in the depth.

A solid cylinder rolling up an inclination is shown in the following figure.

Initial velocity of the solid cylinder, v = 5 m/s
Angle of inclination, {tex}\theta = 30 ^ { \circ }{/tex}
Height reached by the cylinder = h

1. Energy of the cylinder at point A will be purely kinetic due to the rotation and translational motion. Hence, total energy at A
   = KE_rot + KE_trans
   =   {tex}\frac { 1 } { 2 } I \omega ^ { 2 } + \frac { 1 } { 2 } m v ^ { 2 }{/tex}

   The energy of the cylinder at point B will be purely in the form of gravitational potential energy  = mgh
   Using the law of conservation of energy, we can write:
   {tex}\frac { 1 } { 2 } I \omega ^ { 2 } +\frac { 1 } { 2 } m v ^ { 2 } = m g h{/tex}
   Moment of inertia of the solid cylinder, {tex}I = \frac { 1 } { 2 } m r ^ { 2 }{/tex}
   {tex}\therefore \frac { 1 } { 2 } \left( \frac { 1 } { 2 } m r ^ { 2 } \right) \omega ^ { 2 } + \frac { 1 } { 2 } m v ^ { 2 } = m g h{/tex}
   {tex}\frac { 1 } { 4 } I \omega ^ { 2 } + \frac { 1 } { 2 } m v ^ { 2 } = m g h{/tex}
   But we have the relation, {tex}v = r \omega{/tex}
   {tex}\therefore \frac { 1 } { 4 } v ^ { 2 } + \frac { 1 } { 2 } v ^ { 2 } = g h{/tex}
   {tex}\frac { 3 } { 4 } v ^ { 2 } = g h{/tex}
   {tex}\therefore h = \frac { 3 } { 4 } \frac { v ^ { 2 } } { g }{/tex}
   {tex}= \frac { 3 } { 4 } \times \frac { 5 \times 5 } { 9.8 } = 1.91 \mathrm { m }{/tex}

   To find the distance covered along the inclined plane
   In {tex}\Delta A B C{/tex}:
   {tex}\sin \theta = \frac { B C } { A B }{/tex}
   {tex}\sin 30 ^ { \circ } = \frac { h } { A B }{/tex}
   {tex}A B = \frac { 1.91 } { 0.5 } = 3.82 \mathrm { m }{/tex}
   Hence, the cylinder will travel 3.82 m up the inclined plane.

2. {tex}v = \left( \frac { 2 g h } { 1 + \frac { K ^ { 2 } } { R ^ { 2 } } } \right) ^ { \frac { 1 } { 2 } }{/tex}
   {tex}\therefore v = \left( \frac { 2 g A B \sin \theta } { 1 + \frac { K ^ { 2 } } { R ^ { 2 } } } \right) ^ { \frac { 1 } { 2 } }{/tex}
   For the solid cylinder, {tex}K ^ { 2 } = \frac { R ^ { 2 } } { 2 }{/tex}
   {tex}\therefore v = \left( \frac { 2 g A B \sin \theta } { 1 + \frac { 1 } { 2 } } \right) ^ { \frac { 1 } { 2 } }{/tex}
   {tex}= \left( \frac { 4 } { 3 } g A B \sin \theta \right) ^ { \frac { 1 } { 2 } }{/tex}
   The time taken to return to the bottom is:
   {tex}t = \frac { A B } { v }{/tex}
   {tex}= \frac { A B } { \left( \frac { 4 } { 3 } g A B \sin \theta \right) ^ { \frac { 1 } { 2 } } } = \left( \frac { 3 A B } { 4 g \sin \theta } \right) ^ { \frac { 1 } { 2 } }{/tex}
   {tex}= \left( \frac { 11.46 } { 19.6 } \right) ^ { \frac { 1 } { 2 } } = 0.7645{/tex}
   So the total time taken by the cylinder to return to the bottom is (2 {tex}\times{/tex} 0.764)= 1.53 s.as time of ascend is equal to time of descend for the following problem.

The central problem of “for whom to produce” refers to the selection of the category of the people who will ultimately consume the goods., i.e, whether to produce goods for poorer and less rich or richer and less poor. Since resources are scarce in every economy, no society can satisfy all the wants of its people. Thus, a problem of choice arises. Goods are produced for those people who have the paying capacity. The capacity of people to pay for goods depends upon their level of income. It means this problem is concerned with the distribution of income among the factors of production(land, labour, capital and enterprise) who contribute to the production process. Income is distributed in the form of wages,rent, interest and profit.

Multimedia is a form of communication that combines different content forms such as text, audio, images, animations or video into a single presentation, in contrast to traditional mass media, such as printed material or audio recordings.

931.5 MeV

The members of the club used to call George Pearson, Pompy-ompy Pearson because they used to think that he was slow and pompous. They used to laugh at him behind his back.

We know that 180° = π radian.
40° 20'  = 40 1/3 degree = π /180 × 121/3 radian = 121π /540radian
Therefore 40° 20′ = 121π/540 radian.