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Sia ? 6 years, 2 months ago
जिन्स-ए-कामिल से अभिप्राय सर्वोत्तम फसले जैसे कपास और गन्ना। जिन्स- ए- कामिल के अतंर्गत आने वाली फसलों से राज्य को कर अधिक मिलता था।
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Gaurav Seth 6 years, 2 months ago
Yes, Torque is a example of vector quantity.
Explanation:
Torque is calculated by multiplying force and distance. It is a vector quantity, meaning it has both a direction and a magnitude. Either the angular velocity for the moment of inertia of an object is changing, or both.
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Any limestone or dolomitic region showing typical landforms produced by the action of groundwater through the processes of solution and deposition is called Karst topography after the typical topography developed in limestone rocks of Karst region in the Balkans adjacent to Adriatic sea. The karst topography is also characterised by erosional and depositional landforms
Depositional Landforms
Many depositional forms develop within the limestone caves. The chief chemical in limestone is calcium carbonate which is easily soluble in carbonated water (carbon dioxide absorbed rainwater). This calcium carbonate is deposited when the water carrying it in solution evaporates or loses its carbon dioxide as it trickles over rough rock surfaces.
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Yogita Ingle 6 years ago
In biphosphate is any salt of phosphoric acid in which only one of the hydrogen atom has been replaced by a metal ion whereas bisphosphate is a diphosphate and it has two phosphate groups attached to a sugar residue.
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Sia ? 6 years, 2 months ago
Let the period of oscillation T of a large fluid star depends on the radius of star, R, the mean density of fluid, {tex}\rho{/tex} and universal gravitational constant, G as:
T = k Ra {tex}\rho{/tex}b Gc, where k is a dimensionless constant and a, b, c are their exponents.
Now, equating the dimensions on both the sides, we have,
[Mo Lo T1] = [L]a [M L-3]b [M-1 L3 T-2]c = Mb-c La-3b+3c T-2c
On comparing powers of M, L and T on both sides, we get,
b - c = 0 ...(i)
a - 3b + 3c = 0 ...(ii)
and - 2c = 1 ...(iii)
On simplifying these equations, we get c = {tex}-\frac{1}{2}{/tex}, b = {tex}-\frac{1}{2}{/tex} and a = 0
Thus, period of oscillation, T = {tex}k \rho^{-\frac{1}{2}} G^{-\frac{1}{2}}{/tex}= {tex}\frac{k}{\sqrt{\rho G}}{/tex}
This is the required expression.
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