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Sia ? 6 years, 2 months ago
Rf values are always less than 1. An Rf value of 1 or too close to it means that the spot and the solvent front travel close together and is therefore unreliable. This happens when the eluting solvent is too polar for the sample.
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जब दो या दो से अधिक व्यक्ति आपस में कुछ सार्थक चिह्नों, संकेतों या प्रतीकों के माध्यम से विचारों या भावनाओं का आदान-प्रदान करते हैं तो उसे संचार कहते हैं।
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Sia ? 6 years, 2 months ago
Plasma and red blood cells transport carbon dioxide. This is because they are readily soluble in water.
- Through plasma:
About 7% of CO2 is carried in a dissolved state through plasma. Carbon dioxide combines with water and forms carbonic acid.
{tex}CO_2\;+H_2O\rightarrow\underset{Carbonic\;acid)}{H_2CO_3}{/tex}
Since the process of forming carbonic acid is slow, only a small amount of carbon dioxide is carried this way. - Through RBCs:
About 20 – 25% of CO2 is transported by the red blood cells as carbaminohaemoglobin. Carbon dioxide binds to the amino groups on the polypeptide chains of haemoglobin and forms a compound known as carbaminohaemoglobin. - Through sodium bicarbonate:
About 70% of carbon dioxide is transported as sodium bicarbonate. As CO2 diffuses into the blood plasma, a large part of it combines with water to form carbonic acid in the presence of the enzyme carbonic anhydrase. Carbonic anhydrase is a zinc enzyme that speeds up the formation of carbonic acid. This carbonic acid dissociates into bicarbonate (HCO3–) and hydrogen ions (H+).
{tex}\mathrm{CO}_{2}+\mathrm{H}_{2} \mathrm{O} \stackrel{\text { Carbonicanhydrase }}{\longrightarrow} \mathrm{H}_{2} \mathrm{CO}_{3}{/tex}
{tex}\mathrm{H}_{2} \mathrm{CO}_{3} \frac{\text { Carbonic }}{\text { anhydrase }} \mathrm{HCO}_{3}^{-}+\mathrm{H}^{+}{/tex}
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Sia ? 6 years, 2 months ago
{tex}\frac{4x}{7}{/tex} - {tex}\frac{2}{3}{/tex} = {tex}\frac{11}{2}{/tex}
{tex}\Rightarrow{/tex} {tex}\frac{4x}{7}{/tex}= {tex}\frac{11}{2}{/tex} + {tex}\frac{2}{3}{/tex}
{tex}\Rightarrow{/tex} {tex}\frac{4x}{7}{/tex} = {tex}\frac{37}{6}{/tex}
{tex}\Rightarrow{/tex} 4x = {tex}\frac{37}{6}\times7{/tex}
{tex}\Rightarrow{/tex} x = {tex}\frac{37}{6}\times\frac{7}{4}{/tex}
{tex}\Rightarrow{/tex} x ={tex}\frac{259}{24}{/tex}
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Sia ? 6 years, 2 months ago
Given: {tex}{S_1} = {n \over 2}\left[ {2a + (n - 1)d} \right]{/tex} …..(i)
{tex}{S_2} = {{2n} \over 2}\left[ {2a + (2n - 1)d} \right]{/tex}…..(ii)
And {tex}{S_3} = {{3n} \over 2}\left[ {2a + (3n - 1)d} \right]{/tex}
Now, {tex}{S_2} - {S_1} = {{2n} \over 2}\left[ {2a + (2n - 1)d} \right] - {n \over 2}\left[ {2a + (n - 1)d} \right]{/tex}
{tex}\Rightarrow {S_2} - {S_1} = (n - {n \over 2})2a + \left[ {n(2n - 1) - {n \over 2}(n - 1)} \right]d{/tex}
{tex}= na + {1 \over 2}\left[ {4{n^2} - 2n - {n^2} + n} \right]d{/tex}
{tex}= {n \over 2}\left[ {2a + (3n - 1)d} \right] = {1 \over 3}\left\{ {{{3n} \over 2}\left[ {2a + (3n - 1)d} \right]} \right\} = {1 \over 3}{S_3}{/tex}
{tex}\Rightarrow {/tex} 3(S2 - S1) = S3
Hence proved.
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Sia ? 6 years, 2 months ago
Mesopotamia is a historical region of Western Asia situated within the Tigris–Euphrates river system, in the northern part of the Fertile Crescent, in modern days roughly corresponding to most of Iraq, Kuwait, the eastern parts of Syria, Southeastern Turkey, and regions along the Turkish–Syrian and Iran–Iraq borders.
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