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Ragini Ragini 2 years, 6 months ago

Molecular formula=n×Empirical formula N=mol. Wt /mass of EF VD Molecular weight=2×VD =2×15 Molecular weight=30 Total %= [100 -(40+6.66 )]=%of oxygen 100= 100 - 46.66 = 53.34% Atomic mass percent. C. 12. 40 H. 1. 6.66 O. 10. 53.34 At. Ratio. Simple ratio 40\12 =3.33. 3.33\3.33 6.66\1=6.66. 6.66\3.33 53.34\16=3.33 3.33\3.33 C:H:O =1:2:1 Empirical formula=CH2O Mass = 12+(1+2)+16 = 30 N= mol. Wt\mass of EF = 30\30=1 Then, Molecular formula=1×CH²O CH²O
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Umaina Urooj 2 years, 5 months ago

Dpsp mean directive principle of state policy

Aysha Aysha 2 years, 6 months ago

Why India adopt the first pass the post system
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Prince Danu 2 years, 4 months ago

Hi

Priyanka Chauhan 2 years, 5 months ago

Hlo
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Shivani Verma 2 years, 6 months ago

Jjaa
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Harsh Tiwary 2 years, 6 months ago

What is ledger
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Inayat Kashyap 2 years, 5 months ago

, U={1,2,3,4,5,6,7} A={1,2,5,7} B={3,4,5,6} (A∪B)′=U−(A∪B) ={1,2,3,4,5,6,7}−{1,2,3,4,5,6,7} =ϕ A′∩B′=(U−A)n(U−B) ={3,4,6}n{1,2,7} =ϕ Hence (A∪B)′=A′∩B′.

Himanshu Singh Chauhan 1221 2 years, 6 months ago

7,8,9,10=7,8,9,10
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Navroop Kaur 2 years, 6 months ago

Ch 1 introduction of accounting notes

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