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Anjali Anand 2 years, 8 months ago (974632)
3x2+ 8x +k
let a and b are zeroes then b = 1/a (given)
product of zeroes = constant/ coefficient of x2 = k/3
a x b = a x 1/a = 1
so k/3 = 1
so k =3
Posted by #Student _ 2 years, 8 months ago (12965500)
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Anjali Anand 2 years, 8 months ago (974632)
L.H.S
(1- COS2A ) COSEC2A = SIN2 A (1/SIN2A) (SIN2A + COS2 A =1) COSEC A = 1/ SIN A
=1
HENCE PROVED
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Rimi Chakma 2 years, 7 months ago (14398965)
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