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he 'dust of snow' means the fine particles or flakes of snow. The sudden shower in the form of the dust of snow changed the poet's mood.
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Write it as cos (45-30) - sin(45-30)
Now open both the functions as
= cos 45 cos 30 + sin 45 sin 30 - sin 45 cos 30 + sin 30 cos 45
Putting the values as learned in class X
{tex}{1\over \sqrt2} *{\sqrt3\over2} +{1\over \sqrt2} *{1\over2} - {1\over \sqrt2} *{\sqrt3\over2} +{1\over2} *{1\over \sqrt2} {/tex}
Solving we get
= {tex}1\over\sqrt2{/tex}
Answer.
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Here I will tell you how to find F0g & hope you will find the remaining.
f0g is pronounced as f of g(x)
f0g = f{g(x)} = f {{tex}x \over x^2 +1{/tex}}
We have put the value of g(x) given in question.
Now let us assume that {tex}{x \over x^2 +1} = y{/tex}
Therefore, f {{tex}x \over x^2 +1{/tex}} = f{y}
as f{x} = 3x+2
f{y} = 3y +2
Therefore
f{{tex}{x \over x^2 +1}{/tex}} = 3 * {tex}{x \over x^2 +1}{/tex} + 2
=> f0g = {tex}{3x \over x^2 +1} +2 {/tex}
On Solving
f0g = {tex}{3x + 2x^2 +2\over x^2 +1}{/tex}
Answer.
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Komal Meena 4 years, 7 months ago (9421619)
2 Thank You