Ask questions, doubts, problems and we will help you..
Ask questions which are clear, concise and easy to understand.
Ask Question
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Sunil Patri 4 years, 4 months ago (11552171)
- 1 answers
Posted by Archna Kumari Kumari 4 years, 4 months ago (11552186)
- 3 answers
Sakshi Keshri 4 years, 4 months ago (9504191)
Posted by Komalpreet Kaur 4 years, 4 months ago (11552181)
- 1 answers
Posted by Dayanand Yadav 4 years, 4 months ago (11552041)
- 3 answers
Mohammad Shish 4 years, 4 months ago (4606752)
Sher Singh 4 years, 4 months ago (10787241)
Posted by Tikaram Ghimire 4 years, 4 months ago (5625899)
- 3 answers
Posted by Vanshika Dwivedi 4 years, 4 months ago (11551976)
- 2 answers
Pushpanjali Singh 4 years, 3 months ago (9339279)
ẞevíú Çhéú 4 years, 4 months ago (9529992)
Posted by Kanak Jaiswal 4 years, 4 months ago (10120529)
- 0 answers
Posted by Aryan Panwar 4 years, 4 months ago (11551768)
- 3 answers
Posted by Amrita Mukesh 4 years, 4 months ago (10029750)
- 0 answers
Posted by Pooja Unnamalai Suresh 4 years, 4 months ago (11490208)
- 1 answers
Mehak Rai 4 years, 4 months ago (9337892)
Posted by Akansha Yadav 4 years, 4 months ago (11520401)
- 3 answers
Posted by Sayan Jana 4 years, 4 months ago (11446643)
- 4 answers
Posted by Rakesh Agrawal 4 years, 4 months ago (8762177)
- 1 answers
Shashank 11 4 years, 4 months ago (11652158)
Posted by ☆€$H!Ţ@✌? ♡Ťh@Kur♡ 4 years, 4 months ago (11357791)
- 5 answers
Posted by Sibani M 3 years ago (10222313)
- 1 answers
Preeti Dabral 3 years ago (2983787)
Step 1 of 2
Two cards are drawn simultaneously,
Let, denotes the number of aces in 2 draws from a pack of 52 cards
∴ X can takes values 0, 1, 2
Step 2
{tex}\begin{aligned} & P(X=0)=\frac{{ }^{48} C_2}{{ }^{52} C_2}=\frac{48 \times 47}{52 \times 51}=\frac{12 \times 47}{13 \times 51}=\frac{188}{221} \\ & \therefore P(X=0)=\frac{188}{221} \\ & P(X=1)=\frac{{ }^4 C_1 \times{ }^{48} C_1}{{ }^{52} C_2}=\frac{4 \times 48 \times 2}{52 \times 51}=\frac{32}{221} \\ & \therefore P(X=1)=\frac{32}{221} \\ & P(X=2)=\frac{{ }^4 C_2}{{ }^{52} C_2}=\frac{4 \times 3}{52 \times 51}=\frac{1}{221} \\ & \therefore P(X=2)=\frac{1}{221} \\ & \end{aligned}{/tex}
Thus the probability distribution of random variable is
{tex}\begin{array}{|l|l|l|l|}
\hline X & 0 & 1 & 2 \\
\hline P(X) & \frac{188}{221}= & \frac{32}{221}= & \frac{1}{221}= \\
\hline
\end{array}{/tex}
Posted by Patel Manav 4 years, 4 months ago (11366200)
- 1 answers
Posted by Dipu Mangela 4 years, 4 months ago (8602536)
- 1 answers
Pra Jit 4 years, 4 months ago (11352040)
Posted by Priyal Prajapat 4 years, 4 months ago (11091804)
- 2 answers
Posted by Aryan Gupta 4 years, 4 months ago (11551077)
- 2 answers
Sia ? 4 years, 4 months ago (6945213)
A computer is a machine that can be programmed to carry out sequences of arithmetic or logical operations automatically. Modern computers can perform generic sets of operations known as programs. These programs enable computers to perform a wide range of tasks.
Posted by Irshad Mansuri 4 years, 4 months ago (11514978)
- 2 answers
Sucheta Priyadarshini 4 years, 4 months ago (11117421)
Posted by Nishant Kar 4 years, 4 months ago (11367182)
- 1 answers
Ankita Shaw 4 years, 4 months ago (9430359)
Posted by Priyanshu Kumar Singh 4 years, 4 months ago (10342231)
- 2 answers
Posted by Bhawna . 4 years, 4 months ago (10859389)
- 1 answers
Nandini Ladda 4 years, 4 months ago (5739260)
Posted by Binamra Tewary 4 years, 4 months ago (11550964)
- 1 answers
Tejaswini Maurya 4 years, 4 months ago (11552296)
Posted by Ruma Halder 4 years, 4 months ago (11550269)
- 5 answers
Ashi Parcha 4 years, 4 months ago (11558180)
Yash Yadav 4 years, 4 months ago (11557018)
Posted by Jai Sapra 4 years, 4 months ago (8106190)
- 0 answers
Posted by Manikanth Luwang 4 years, 4 months ago (11550866)
- 3 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sanket ... 4 years, 4 months ago (5722231)
5 Thank You