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Here, {tex}\frac {3}{13} \div \frac {-4}{65}{/tex}
= {tex}\frac {3}{13} \times \frac {65}{-4}{/tex}
= {tex}\frac {65 \times 3}{13 \times (-4)}{/tex}
= {tex}\frac {15}{-4}{/tex}
Therefore, the reciprocal is {tex}\frac {-4}{15}{/tex}
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Sia ? 4 years, 2 months ago (6945213)
Divisibility by 3: sum of digits needs to be divisible by 3.
Smallest 3 digit number:100
1+0+0=1.
3–1=2
100+2=102 is the smallest divisible by 3.
Largest 3 digit number: 999
9+9+9=27
27 is divisible by 3 and so is 999.
Your difference is 999–102=897
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