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Sia ? 2 years, 6 months ago
Divisibility by 3: sum of digits needs to be divisible by 3.
Smallest 3 digit number:100
1+0+0=1.
3–1=2
100+2=102 is the smallest divisible by 3.
Largest 3 digit number: 999
9+9+9=27
27 is divisible by 3 and so is 999.
Your difference is 999–102=897
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