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Maximum Effort Rule ensures that participants are competing with Maximum Effort at all stages of competition.
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Navita Jha 2 years ago

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Manav Sharma 2 years ago

To find the equations of the medians through points A and B, we first find the midpoints of the sides opposite to these vertices: 1. Midpoint of BC (opposite to A): \((-0.5, 2, 0)\) 2. Midpoint of AC (opposite to B): \((-0.5, 1.5, -0.5)\) Now, let's find the equations of the medians: ### Median through A: Equation: \(x + 1.5y - 2.5 = 0\) ### Median through B: Equation: \(2x + 3y - 2z - 4 = 0\) Now, let's solve these equations simultaneously to find the centroid's coordinates. By solving the equations of the medians simultaneously, we find the centroid's coordinates as (1.5, 5/4, 11/8).
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Manav Sharma 2 years ago

The integration of \( \frac{e^x}{(1 + x^2)^{3/2}} \times \frac{x}{\sqrt{1 + x^2}} \) is \( -\frac{e^x}{\sqrt{1 + x^2}} + C \), where \( C \) is the constant of integration.
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Dolly Kumari 2 years ago

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Aman Bamal 1 year, 6 months ago

Lambda /2πr efsinote

Saina Aska 2 years ago

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Mayank Kumar 2 years ago

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It refers to absence of menstruation during intense lactation

Pranjali Rathod 2 years ago

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Mohini Patel 2 years, 1 month ago

A way for breastfeeding to temporarily help prevent pregnancy. It must be used correctly to work. Lactation means your body is making breastmilk and amenorrhea means you aren't having a monthly period. Breastfeeding hormones may stop your body from releasing eggs.
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1 January 2015

Anshika Rawal 2 years ago

2014

Shiv Bansal 2 years ago

2015

Tarun Kothari 2 years ago

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Vipul Goyal 2 years, 1 month ago

1 January 2015
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Vipul Goyal 2 years, 1 month ago

1 January 2015
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Manav Sharma 2 years ago

To find the number of onto (surjective) functions from set \( A \) to set \( B \), where \( |A| = 4 \) and \( |B| = 3 \), we can use the formula: \[ \text{Number of onto functions} = |B|^{|A|} - \binom{|B|}{1} \times (|B| - 1)^{|A|} + \binom{|B|}{2} \times (|B| - 2)^{|A|} - \binom{|B|}{3} \times (|B| - 3)^{|A|} \] In this case, \( |A| = 4 \) and \( |B| = 3 \), so we have: \[ \text{Number of onto functions} = 3^4 - \binom{3}{1} \times 2^4 + \binom{3}{2} \times 1^4 - \binom{3}{3} \times 0^4 \] \[ = 81 - 3 \times 16 + 3 \times 1 - 1 \times 0 \] \[ = 81 - 48 + 3 - 0 \] \[ = 36 \] So, there are \( 36 \) possible onto functions from set \( A \) to set \( B \).
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1. Size of heart increases. 2. Cardiac output increases. 3. Tidal volume increases. 4. Stroke volume increases. 5. Vital capacity increases.
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Krishna Chaurasiya 2 years, 1 month ago

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Gitasha Thakur 2 years, 1 month ago

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Aanchal Kashyap 2 years, 1 month ago

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Shagun Singh 2 years, 1 month ago

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Lakshya Kundu 2 years, 1 month ago

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Manav Sharma 2 years, 1 month ago

To find the number of distinct integers between 100 and 1000, we subtract 1 from 1000 (to exclude 1000 itself), then subtract 99 (to account for the numbers from 100 to 999), and add 1 (to include 100). So, the number of distinct integers between 100 and 1000 is \(1000 - 100 - 1 + 1 = 900\). Therefore, there are 900 distinct integers that can be arranged between 100 and 1000.

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