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Physics is the branch of science that deals with the structure of matter and how the fundamental constituents of the universe interact.
We use physics in our everyday life activities such as walking, playing, watching, listening, cutting, cooking, and opening and closing things.
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Preeti Dabral 3 years ago
The relative stability of the +2 oxidation state increases on moving from top to bottom. This is because on moving from top to bottom, it becomes more and more difficult to remove the third electron from the d-orbital.
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Preeti Dabral 3 years ago
Land reforms in India during planning period were as:
- Abolition of the colonial system of zamindari. this bold act not only released land from the clutches of a class that had little interest in agriculture, but it also reduced the capacity of the landlords to dominate politics.
- Lands were consolidated to bring small pieces of land together in one place so that the farm size could become viable for agriculture.
Drawbacks:
- The laws were made to put an upper limit or ‘ceiling’, to how much agricultural land one person could own, people with excess land managed to evade the law.
- The tenants, who worked on someone else’s land were given greater legal security which rarely implemented.
- Landowners were very powerful and wielded considerable political influence.
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Preeti Dabral 3 years ago
The boiling point of the solution is 273.41 k
GIVEN
Weight of urea = 6 grams
weight of Glucose = 9 grams.
Weight of water = 300 grams
TO FIND
The boiling point of the solution.
SoOLUTION
We can simply solve the given problem as follows-
To calculate the boiling point of the solution, we will apply the following formula -
∆Tₒ = Kb× b × i (eq 1)
Where,
∆Tₒ = boiling point elevation
Kb = ebullioscopic constant of the solvent ( kb = o.515 kg/mol)
b = molality of the solute
i = van't Hoff factor of solute ( since urea and glucose are non-ionic compounds, so, i= 1)
We know that,
Boiling point elevation is defined as :
ΔTₒ = T₁ - T ........(eq2)
where,
T₁ = boiling point of the solution
T = boiling point of the solvent (T = 273.15 k of water)
Now,
{tex}\begin{aligned} & \text { number of moles of urea }=\frac{\text { given weight of urea }}{\text { molar mass of urea }} \\ & = \\ & \frac{6}{60}=0.1 \text { moles } \\ & \text { number of moles of glucose }=\frac{\text { given weight of glucose }}{\text { molar mass of glucose }} \\ & =\frac{9}{180}=0.05 \text { moles } \\ & \text { Total moles of solute }=0.1+0.05=0.15 \text { moles } \\ & \text { molality of solute }(b)=\frac{\text { moles of solute }}{\text { mass of solvent in } \mathrm{kg}} \\ & b=\frac{0.15 \times 1000}{300} \\ & b=0.5 \mathrm{M} \end{aligned}{/tex}
putting the values in ( eq 1) we have
ΔTₒ = 0.512 × 0.5 × 1
ΔTₒ = 0.26 k
Now, putting the value of ΔTₒ in (eq 2)
ΔTₒ = T₁ - T
0.26 = T₁ - 273.15
T₁ = 273.15 + 0.26
T₁ = 273.41 k
Hence, The boiling point of the solution is 273.41 k
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Preeti Dabral 3 years ago
An intrinsic semiconductor, also called an undoped semiconductor or i-type semiconductor, is a pure semiconductor without any significant dopant species present. The number of charge carriers is therefore determined by the properties of the material itself instead of the amount of impurities.
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