Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Sona , 3 years, 1 month ago
- 0 answers
Posted by Sona , 3 years, 1 month ago
- 1 answers
Posted by Sona , 3 years, 1 month ago
- 0 answers
Posted by Sona , 3 years, 1 month ago
- 1 answers
Posted by Kash Brar 3 years, 1 month ago
- 2 answers
Posted by Kishan Kumawat 3 years, 1 month ago
- 0 answers
Posted by Tanisha Upadhayay 3 years, 1 month ago
- 1 answers
Posted by Sachin Pal 3 years, 1 month ago
- 1 answers
Akshat Neeraj 3 years, 1 month ago
Posted by Vijina Ns 3 years, 1 month ago
- 0 answers
Posted by Rakhi Ramesh 3 years, 1 month ago
- 1 answers
Nidhi Saini 3 years, 1 month ago
Posted by Rishi Uniyal 3 years, 1 month ago
- 1 answers
Posted by Karan Tuteja 3 years, 1 month ago
- 1 answers
Posted by Priu S 3 years ago
- 1 answers
Preeti Dabral 3 years ago
The dual cell heat exchanger consists of two porous fluid zones, namely a primary zone and an auxiliary zone. The two zones are solved simultaneously and are coupled only through heat transfer.
Posted by Ishita Ratwaya 3 years, 1 month ago
- 0 answers
Posted by Roshan Pal 3 years, 1 month ago
- 0 answers
Posted by Ashu Roy 3 years, 1 month ago
- 2 answers
Posted by Aniket . 3 years, 1 month ago
- 1 answers
Posted by Baba Tushir 3 years ago
- 1 answers
Preeti Dabral 3 years ago
{tex}\int {x\log 2xdx} {/tex}
{tex} = \int {\left( {\log 2x} \right)xdx} {/tex}
{tex}= \left( {\log 2x} \right)\int {xdx - \int {\left[ {\frac{d}{{dx}}\log 2x\int {xdx} } \right]dx} } {/tex}
[Applying product rule]
{tex}= \left( {\log 2x} \right)\frac{{{x^2}}}{2} - \int {\frac{1}{{2x}}.2.\frac{{{x^2}}}{2}dx} {/tex}
{tex} = \frac{1}{2}{x^2}\log 2x - \frac{1}{2}\int {xdx} {/tex}
{tex}= \frac{1}{2}{x^2}\log 2x - \frac{1}{2}\frac{{{x^2}}}{2} + c{/tex}
{tex}= \frac{{{x^2}}}{2}\log 2x - \frac{{{x^2}}}{4} + c{/tex}
Posted by Anu Bhigasra 3 years, 1 month ago
- 0 answers
Posted by Lalit Kumar 3 years ago
- 1 answers
Preeti Dabral 3 years ago
Given {tex}^a{\mu _g} = 1.5{/tex} and {tex}^a{\mu _w} = 1.3{/tex}
As, {tex}\delta = (\mu - 1)A{/tex}
For deviation in air, {tex}\mu = \frac{{{\mu _g}}}{{{\mu _a}}} = \frac{{1.5}}{1} = 1.50{/tex}
{tex}\therefore \delta = (1.5 - 1) \times 60^\circ{/tex} = 30°
For deviation in water, {tex}\mu = \frac{{{\mu _g}}}{{{\mu _w}}} = \frac{{1.5}}{{1.3}} = 1.15{/tex}
{tex}\therefore \delta = (1.15 - 1) \times 60^\circ {/tex} = 9°
Therefore, the angle of deviation is decreased.
Posted by Pragya Shukla 3 years, 1 month ago
- 0 answers
Posted by Anuraj Yadav 3 years, 1 month ago
- 4 answers
Himani . 3 years ago
Priyanshu Setia 3 years, 1 month ago
Akshat Neeraj 3 years, 1 month ago
Abhishek Nishad 3 years, 1 month ago
Posted by Shalu Shrivastav 3 years, 1 month ago
- 0 answers
Posted by Ankit Kumar 3 years, 1 month ago
- 2 answers
Posted by Shaurya Singh 3 years, 1 month ago
- 3 answers
Posted by Ajon Konyak 3 years, 1 month ago
- 2 answers
Posted by Himanshu Mishra 3 years, 1 month ago
- 0 answers
Posted by Sonam Gurjar 3 years, 1 month ago
- 0 answers
Posted by Rigzin Chosphel 3 years, 1 month ago
- 1 answers
Rigzin Chosphel 3 years, 1 month ago

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide