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Anshika Sharma 4 years, 6 months ago (11043402)
Anshika Sharma 4 years, 6 months ago (11043402)
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Akshita Gupta 4 years, 6 months ago (8495477)
Riyanshi ... 4 years, 6 months ago (11328983)
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Riya Jain 4 years, 6 months ago (11106452)
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Posted by Priyanshi Dubey 4 years, 6 months ago (11026697)
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Preeti Dabral 4 years, 6 months ago (2983787)
x³ - 2x² - x + 2
=> x²(x - 2) - 1(x - 2)
=> (x - 2)(x² - 1)
=> (x - 2){(x)² - (1)²}
=> (x - 2)(x - 1)(x + 1)
Posted by Shuvasmita Nayak 4 years, 6 months ago (11368736)
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Posted by Khushi Tanwar 4 years, 6 months ago (11363811)
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Preeti Dabral 4 years, 6 months ago (2983787)
Step-by-step explanation:
Solution :-
Let the tens place digit be x.
And the units place digit be y.
According to the Question,
⇒ xy = 18
⇒ y = 18/x .....(i)
And, (10x + y) - 63 = 10y + x
⇒ 9x - 9y = 63
⇒ x - y = 7 .... (ii)
Putting y's value in Eq (ii), we get
⇒ x - 18/x = 7
⇒ x² - 18 = 7x
⇒ x² - 7x - 18 = 0
⇒ x² - 9x + 2x - 18 = 0
⇒x(x - 9) + 2(x - 9) = 0
⇒ (x - 9) (x + 2) = 0
⇒ x - 9 = 0 or x + 2 = 0
⇒ x = 9, - 2 (As x can't be negative)
⇒ x = 9
Putting x's value in Eq (i), we get
⇒ xy = 18
⇒ 9y = 18
⇒ y = 18/9
⇒ y = 2
Number = 92
Hence, the required number is 92.
Posted by Óp Łùciferyt 4 years, 6 months ago (11368634)
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Anshika Sharma 4 years, 6 months ago (11043402)
Posted by Linkan Giri 4 years, 6 months ago (11343933)
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