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  • 1 answers

Ragini Ragini 2 years, 7 months ago (14368280)

Molecular formula=n×Empirical formula N=mol. Wt /mass of EF VD Molecular weight=2×VD =2×15 Molecular weight=30 Total %= [100 -(40+6.66 )]=%of oxygen 100= 100 - 46.66 = 53.34% Atomic mass percent. C. 12. 40 H. 1. 6.66 O. 10. 53.34 At. Ratio. Simple ratio 40\12 =3.33. 3.33\3.33 6.66\1=6.66. 6.66\3.33 53.34\16=3.33 3.33\3.33 C:H:O =1:2:1 Empirical formula=CH2O Mass = 12+(1+2)+16 = 30 N= mol. Wt\mass of EF = 30\30=1 Then, Molecular formula=1×CH²O CH²O
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Deepak Meena 2 years, 7 months ago (9617650)

We can use the formula for electrostatic potential energy to calculate the work done in bringing the two point charges closer. The formula for electrostatic potential energy is: U = k*q1*q2/r where U is the electrostatic potential energy, k is Coulomb's constant (= 9 x 10^9 Nm^2/C^2), q1 and q2 are the magnitudes of the charges in Coulombs, and r is the distance between the charges in meters. Initially, the charges are 10 cm = 0.1 m apart, so the initial distance r1 is 0.1 m. The final distance r2 when the charges are 4 cm = 0.04m apart. The magnitudes of the charges are q1 = 12 uC = 12 x 10^-6 C, and q2 = 8 uC = 8 x 10^-6 C. Using the formula and plugging in the values, we get: U1 = k*q1*q2/r1 = (9 x 10^9 Nm^2/C^2)(12 x 10^-6 C)(8 x 10^-6 C)/(0.1 m) ≈ 8.64 x 10^-5 J U2 = k*q1*q2/r2 = (9 x 10^9 Nm^2/C^2)(12 x 10^-6 C)(8 x 10^-6 C)/(0.04 m) ≈ 3.456 x 10^-4 J The change in electric potential energy ΔU is U2 - U1 = 2.594 x 10^-4 J. Therefore, the work done in bringing the charges 4cm closer is 2.594 x 10^-4 Joules.
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Banu Priya 2 years, 7 months ago (14452544)

Biotic is a living things
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Sanjeevani Mishra 2 years, 7 months ago (14272649)

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Shubh Asati Shubh Asati 2 years, 7 months ago (14526161)

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Varsha Khangarot 2 years, 7 months ago (13247850)

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Anushka Gupta 2 years, 7 months ago (14448196)

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