Coordinate Geometry class 10 Notes Mathematics

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CBSE Guide Coordinate Geometry class 10 Notes

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10 Mathematics notes Chapter 7 Coordinate Geometry

Download CBSE class 10th revision notes for Chapter 7 Coordinate Geometry in PDF format for free. Download revision notes for Coordinate Geometry class 10 Notes and score high in exams. These are the Coordinate Geometry class 10 Notes prepared by team of expert teachers. The revision notes help you revise the whole chapter in minutes. Revising notes in exam days is on of the the best tips recommended by teachers during exam days.

CBSE Class 10 Mathematics
Revision Notes
CHAPTER 07
COORDINATE GEOMETRY

1. Distance Formula
2. Section Formula
3. Area of a Triangle
4. Distance Formula: The length of a line segment joining A and B is the distance
between two points $A({x_1}, {y_1})$ and $({x_2},{y_2})$ is $\sqrt {(x_2 - x_1)^2 + (y_2 - y_1)^2}$
5. The distance of a point $\left( {x,y} \right)$ from the origin is $\sqrt {({x^2} + {y^2})}$. The distance of P from x-axis is y units and from y-axis is x-units.
6. Section Formula: The co-ordinates of the points p(x, y) which divides the line segment joining the points $A({x_1}, {y_1})$ and $B({x_{2\;,\;}}{y_2})$ in the ratio ${m_{1\;}}:\;{m_2}$ are $\left( {{{{m_1}{x_2} + {m_2}{x_1}} \over {{m_1} + {m_2}}},{{{m_1}{y_2} + {m_2}{y_1}} \over {{m_1} + {m_2}}}} \right)$ we can take ratio as $k\;:\;1,\;\;k = \frac{{{m_1}}}{{{m_2}}}$
7. Mid-point Formula: The mid-points of the line segment joining the points $P({x_1},{y_2})\;\;\;and\;\;\;Q({x_2},{y_2})$ is $\left( {\frac{{{x_1} + {x_2}}}{2},\frac{{{y_1} + {y_2}}}{2}} \right)$
8. Area of a Triangle: The area of the triangle formed by the points $({x_1},{y_1}),\;({x_2},{y_2})\;and\;({x_3},{y_3})$ is the numeric value of the expressions ${1 \over 2}\left| {{x_1}\left( {{y_2} - {y_3}} \right) + {x_2}\left( {{y_3} - {y_1}} \right) + {x_3}\left( {{y_1} - {y_2}} \right)} \right|$.
9. If three points are collinear then we cannot draw a triangle, so the area will be zero i.e. $|{x_1}({y_2} - {y_3}) + {x_2}({y_3} - {y_1}) + {x_3}({y_1} - {y_2})| = 0$