NCERT Solutions for Class 7 Maths Exercise 2.2

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NCERT solutions for Maths Fractions and Decimals Download as PDF

NCERT Solutions for Class 7 Maths Fractions and Decimals

Class –VII Mathematics (Ex. 2.2)

Question 1.Which of the drawings {tex}\left( a \right){/tex} to {tex}\left( d \right){/tex} show:

(i){tex}2 \times \frac{1}{5}{/tex}

(ii){tex}2 \times \frac{1}{2}{/tex}

(iii){tex}3 \times \frac{2}{3}{/tex}

(iv){tex}3 \times \frac{1}{4}{/tex}

Answer:

(i) – (d) Since {tex}2 \times \frac{1}{5} = \frac{1}{5} + \frac{1}{5}{/tex}

(ii) – (b) Since {tex}2 \times \frac{1}{2} = \frac{1}{2} + \frac{1}{2}{/tex}

(iii) – (a) Since {tex}3 \times \frac{2}{3} = \frac{2}{3} + \frac{2}{3} + \frac{2}{3}{/tex}

(iv) – (c) Since {tex}3 \times \frac{1}{4} = \frac{1}{4} + \frac{1}{4} + \frac{1}{4}{/tex}

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NCERT Solutions for Class 7 Maths Exercise 2.2

Question 2.Some pictures {tex}\left( a \right){/tex} to {tex}\left( c \right){/tex} are given below. Tell which of them show:

(i){tex}3 \times \frac{1}{5} = \frac{3}{5}{/tex}

(ii){tex}2 \times \frac{1}{3} = \frac{2}{3}{/tex}

(iii){tex}3 \times \frac{3}{4} = 2\frac{1}{4}{/tex}

Answer:

(i) – (c) Since {tex}3 \times \frac{1}{5} = \frac{1}{5} + \frac{1}{5} + \frac{1}{5}{/tex}

(ii) – (a) Since {tex}2 \times \frac{1}{3} = \frac{1}{3} + \frac{1}{3}{/tex}

(iii) – (b) Since {tex}3 \times \frac{3}{4} = \frac{3}{4} + \frac{3}{4} + \frac{3}{4}{/tex}

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NCERT Solutions for Class 7 Maths Exercise 2.2

Question 3.Multiply and reduce to lowest form and convert into a mixed fraction:

(i) {tex}7 \times \frac{3}{5}{/tex}

(ii) {tex}4 \times \frac{1}{3}{/tex}

(iii) {tex}2 \times \frac{6}{7}{/tex}

(iv) {tex}5 \times \frac{2}{9}{/tex}

(v) {tex}\frac{2}{3} \times 4{/tex}

(vi) {tex}\frac{5}{2} \times 6{/tex}

(vii) {tex}11 \times \frac{4}{7}{/tex}

(viii) {tex}20 \times \frac{4}{5}{/tex}

(ix) {tex}13 \times \frac{1}{3}{/tex}

(x) {tex}15 \times \frac{3}{5}{/tex}

Answer:

(i) {tex}7 \times \frac{3}{5}{/tex} = {tex}\frac{{7 \times 3}}{5}{/tex} = {tex}\frac{{21}}{5} = 4\frac{1}{5}{/tex}

(ii) {tex}4 \times \frac{1}{3}{/tex} = {tex}\frac{{4 \times 1}}{3}{/tex} = {tex}\frac{4}{3} = 1\frac{1}{3}{/tex}

(iii){tex}2 \times \frac{6}{7}{/tex} = {tex}\frac{{2 \times 6}}{7}{/tex} = {tex}\frac{{12}}{7} = 1\frac{5}{7}{/tex}

(iv) {tex}5 \times \frac{2}{9}{/tex} = {tex}\frac{{5 \times 2}}{9}{/tex} = {tex}\frac{{10}}{9} = 1\frac{1}{9}{/tex}

(v) {tex}\frac{2}{3} \times 4{/tex} = {tex}\frac{{2 \times 4}}{3}{/tex} = {tex}\frac{8}{3}{/tex} = {tex}2\frac{2}{3}{/tex}

(vi) {tex}\frac{5}{2} \times 6{/tex} = {tex}5 \times 3{/tex} = 15

(vii){tex}11 \times \frac{4}{7}{/tex} = {tex}\frac{{11 \times 4}}{7}{/tex} = {tex}\frac{{44}}{7}{/tex} = {tex}6\frac{2}{7}{/tex}

(viii){tex}20 \times \frac{4}{5}{/tex} = 4 x 4 = 16

(ix){tex}13 \times \frac{1}{3}{/tex} = {tex}\frac{{13 \times 1}}{3}{/tex} = {tex}\frac{{13}}{3} = 4\frac{1}{3}{/tex}

(x){tex}15 \times \frac{3}{5}{/tex} = 3 x 3 = 9

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NCERT Solutions for Class 7 Maths Exercise 2.2

Question 4.Shade:

(i) {tex}\frac{1}{2}{/tex} of the circles in box

(ii) {tex}\frac{2}{3}{/tex} of the triangles in box

(iii){tex}\frac{3}{5}{/tex} of the squares inbox

Answer:

(i) {tex}\frac{1}{2}{/tex} of 12 circles = {tex}\frac{1}{2} \times 12{/tex} = 6 circles

(ii) {tex}\frac{2}{3}{/tex} of 9 triangles = {tex}\frac{2}{3} \times 9{/tex} = 2 x 3 = 6 triangles

(iii) {tex}\frac{3}{5}{/tex} of 15 squares = {tex}\frac{3}{5} \times 15{/tex} 3 x 3 = 9 squares

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NCERT Solutions for Class 7 Maths Exercise 2.2

Question 5.Find:

(a) {tex}\frac{1}{2}{/tex} of (i) 24 (ii) 46

(b) {tex}\frac{2}{3}{/tex} of (i) 18 (ii) 27

(c) {tex}\frac{3}{4}{/tex} of (i) 16 (ii) 36

(d) {tex}\frac{4}{5}{/tex} of (i) 20 (ii) 35

Answer:

(a)

(i) {tex}\frac{1}{2}{/tex} of 24 = 12

(ii) {tex}\frac{1}{2}{/tex} of 46 = = 23

(b)

(i) {tex}\frac{2}{3}{/tex} of 18 = {tex}\frac{2}{3} \times 18{/tex} = 2 x 6 = 12

(ii) {tex}\frac{2}{3}{/tex} of 27 = {tex}\frac{2}{3} \times 27{/tex} = 2 x 9 = 18

(c)

(i) {tex}\frac{3}{4}{/tex} of 16 = {tex}\frac{3}{4} \times 16{/tex} = 3 x 4 = 12

(ii) {tex}\frac{3}{4}{/tex} of 36 = {tex}\frac{3}{4} \times 36{/tex} = 3 x 9 = 27

(d)

(i) {tex}\frac{4}{5}{/tex} of 20 = {tex}\frac{4}{5} \times 20{/tex} = 4 x 4 = 16

(ii) {tex}\frac{4}{5}{/tex} of 35 = {tex}\frac{4}{5} \times 35{/tex} = 4 x 7 = 28

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NCERT Solutions for Class 7 Maths Exercise 2.2

Question 6.Multiply and express as a mixed fraction:

(a) {tex}3 \times 5\frac{1}{5}{/tex}

(b) {tex}5 \times 6\frac{3}{4}{/tex}

(c) {tex}7 \times 2\frac{1}{4}{/tex}

(d) {tex}4 \times 6\frac{1}{3}{/tex}

(e) {tex}3\frac{1}{4} \times 6{/tex}

(f) {tex}3\frac{2}{5} \times 8{/tex}

Answer:

(a) {tex}3 \times 5\frac{1}{5} = 3 \times \frac{{26}}{5} = \frac{{3 \times 26}}{5} = \frac{{78}}{5} = 15\frac{3}{5}{/tex}

(b) {tex}5 \times 6\frac{3}{4} = 5 \times \frac{{27}}{4} = \frac{{5 \times 27}}{4} = \frac{{135}}{4} = 33\frac{3}{4}{/tex}

(c) {tex}7 \times 2\frac{1}{4} = 7 \times \frac{9}{4} = \frac{{7 \times 9}}{4} = \frac{{63}}{4} = 15\frac{3}{4}{/tex}

(d) {tex}4 \times 6\frac{1}{3} = 4 \times \frac{{19}}{3} = \frac{{4 \times 19}}{3} = \frac{{76}}{3} = 25\frac{1}{3}{/tex}

(e) {tex}3\frac{1}{4} \times 6 = \frac{{13}}{4} \times 6 = \frac{{13 \times 3}}{2} = \frac{{39}}{2} = 19\frac{1}{2}{/tex}

(f) {tex}3\frac{2}{5} \times 8 = \frac{{17}}{5} \times 8 = \frac{{17 \times 8}}{5} = \frac{{136}}{5} = 27\frac{1}{5}{/tex}

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NCERT Solutions for Class 7 Maths Exercise 2.2

Question 7.Find:

(a) {tex}\frac{1}{2}{/tex} of (i) {tex}2\frac{3}{4}{/tex} (ii) {tex}4\frac{2}{9}{/tex}

(b) {tex}\frac{5}{8}{/tex} of (i) {tex}3\frac{5}{6}{/tex} (ii) {tex}9\frac{2}{3}{/tex}

Answer:

Given: Total quantity of water in bottle = 5 litres

(i) Vidya consumed = {tex}\frac{2}{5}{/tex} of 5 litres = {tex}\frac{2}{5} \times 5{/tex} = 2 litres

Thus, Vidya drank 2 litres water from the bottle.

(ii) Pratap consumed = {tex}\left( {1 – \frac{2}{5}} \right){/tex} part of bottle

= {tex}\frac{{5 – 2}}{5} = \frac{3}{5}{/tex} part of bottle

Pratap consumed {tex}\frac{3}{5}{/tex} of 5 litres water = {tex}\frac{3}{5} \times 5{/tex} = 3 litres

Thus, Pratap drank {tex}\frac{3}{5}{/tex} part of the total quantity of water.

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NCERT Solutions for Class 7 Maths Exercise 2.2

Question 8. Vidya and Pratap went for a picnic. Their mother gave them a water bottle that contained 5 litres of water. Vidya consumed {tex}\frac{2}{5}{/tex} of the water. Pratap consumed the remaining water.

(i)How much water did Vidya drink?

(ii)What fraction of the total quantity of water did Pratap drink?

Answer:

Given: Total quantity of water in bottle = 5 litres

(i) Vidya consumed = {tex}\frac{2}{5}{/tex} of 5 litres = {tex}\frac{2}{5} \times 5{/tex} = 2 litres

Thus, Vidya drank 2 litres water from the bottle.

(ii) Pratap consumed = {tex}\left( {1 – \frac{2}{5}} \right){/tex} part of bottle

= {tex}\frac{{5 – 2}}{5} = \frac{3}{5}{/tex} part of bottle

Pratap consumed {tex}\frac{3}{5}{/tex} of 5 litres water = {tex}\frac{3}{5} \times 5{/tex} = 3 litres

Thus, Pratap drank {tex}\frac{3}{5}{/tex} part of the total quantity of water.

NCERT Solutions for Class 7 Maths Exercise 2.2

NCERT Solutions Class 7 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 7 Maths includes text book solutions from Class 7 Maths Book . NCERT Solutions for CBSE Class 7 Maths have total 15 chapters. 7 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 7 solutions PDF and Maths ncert class 7 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.

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