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Posted by Akhil Negi 5 years ago (10395122)
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Posted by Aditi Ringusia 4 years, 7 months ago (10234718)
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Sia ? 4 years, 7 months ago (6945213)
u = - 18 cm
v = 4 cm
1 / f = 1 / v + 1 / u
1 / f = 1 / 4 + 1 / (- 18)
1 / f = 1 / 4 - 1 / 1 8
1 / f = 9 - 2 / 36 = 7 / 36
f = 36 / 7 cm
focal length is positive so mirror is convex.
R = 2 × 36 / 7
= 72 / 7 cm
Posted by Ayan Bapu 5 years ago (10394451)
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Posted by Aditi Ringusia 4 years, 7 months ago (10234718)
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Sia ? 4 years, 7 months ago (6945213)
radius of curvature = 90 cm
focal length = r/2 = +45 cm(since it is on the direction on the incident light)
object distance, u = - 15 cm (since it is on the opposite direction of the incident light)
we have to find v= ?
using mirror formula we get ,
1/v + 1/u = 1/f
so 1/ v = 1/f - 1/u
1/v = 1/ 45 - (1/-15) = 1/45 + 1/15 = 4/45
so v =45 / 4 cm
therefore image distance = 45 / 4 cm (positive sice it is in the direction of incident light)
Posted by Sumit Pandey 5 years ago (9944238)
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Aditi Ringusia 5 years ago (10234718)
Posted by Aditi Ringusia 4 years, 7 months ago (10234718)
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Sia ? 4 years, 7 months ago (6945213)
Large distance =infinity
The image will form on principle focus of convex mirror because rays coming from infinity when touch mirror get diverged but virtually they meet at principle focus
Radius of curvature=40cm
Focal length=Radius of curvature/2
f=40/2
f=20cm
Posted by Aniruddha Debnath. 5 years ago (9324289)
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Sumesh ☺️☺️☺️ 5 years ago (8504833)
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Sia ? 4 years, 7 months ago (6945213)
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