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Preeti Dabral 3 years ago (2983787)
In the steady-state,
Rate of flow of heat through cube A
= Rate of flow of heat through cube B.
or {tex}\frac{K_{1} A(100-T)}{x}=\frac{K_{2} A(T-0)}{x}{/tex}
or {tex}\frac{300 A(100-T)}{x}=\frac{200 A(T-0)}{x}{/tex}
or 300 - 3T = 2T or 5T = 300
T = 60°C
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