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{tex}\mathrm{H}_2 \mathrm{O} \rightarrow 2 \mathrm{H}^{+}+\frac{1}{2} \mathrm{O}_2+2 \mathrm{e}^{-}{/tex}
Oxidation of one mole of water will require 2×96500=1.93×105C.
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Sumit Kumar 3 years, 2 months ago (13566050)
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