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NCERT solutions for Class 7 Integers Maths Download as PDF
NCERT Solutions for Class 7 Maths Integers
Class –VII Mathematics (Ex. 1.2)
Question 1.Write down a pair of integers whose:
(a) sum is {tex} – 7{/tex}
(b) difference is {tex} – 10{/tex}
(c) sum is 0
Answer:
(a) One such pair whose sum is {tex} – 7{/tex}: {tex} – 5 + \left( { – 2} \right) = – 7{/tex}
(b) One such pair whose difference is {tex} – 10{/tex}: {tex} – 2 – 8 = – 10{/tex}
(c) One such pair whose sum is 0: {tex} – 5 + 5 = 0{/tex}
NCERT Solutions for Class 7 Maths Exercise 1.2
Question 2.(a) Write a pair of negative integers whose difference gives 8.
(b) Write a negative integer and a positive integer whose is {tex} – 5.{/tex}
(c) Write a negative integer and a positive integer whose difference is {tex} – 3.{/tex}
Answer:
(a) {tex} – 2 – \left( { – 10} \right) – 2 + 10 = 8{/tex}
(b) {tex}\left( { – 7} \right) + 2 = – 5{/tex}
(c) {tex}\left( { – 2} \right) – 1 = – 2 – 1 = – 3{/tex}
NCERT Solutions for Class 7 Maths Exercise 1.2
Question 3.In a quiz, team A scored {tex} – 40,10,0{/tex} and team B scores 10, 0, {tex} – 40{/tex} in three successive rounds. Which team scored more? Can we say that we can add integers in any order?
Answer:
Team A scored {tex} – 40,10,0{/tex}
Total score of Team A = {tex} – 40 + 10 + 0 = – 30{/tex}
Team B scored {tex}10,0, – 40{/tex}
Total score of Team B = {tex}10 + 0 + \left( { – 40} \right) = 10 + 0 – 40 = – 30{/tex}
Thus, scores of both teams are same.
Yes, we can add integers in any order due to commutative property.
NCERT Solutions for Class 7 Maths Exercise 1.2
Question 4.Fill in the blanks to make the following statements true:
(i){tex}\left( { – 5} \right) + \left( { – 8} \right) = \left( { – 8} \right) + \left( {…….} \right){/tex}
(ii){tex} – 53 + ……. = – 53{/tex}
(iii)17 + ……. = 0
(iv){tex}\left[ {13 + \left( { – 12} \right)} \right] + \left( {…….} \right) = 13 + \left[ {\left( { – 12} \right) + \left( { – 7} \right)} \right]{/tex}
(v){tex}\left( { – 4} \right) + \left[ {15 + \left( { – 3} \right)} \right] = \left[ { – 4 + 15} \right] + …….{/tex}
Answer:
(i) {tex}\left( { – 5} \right) + \left( { – 8} \right) = \left( { – 8} \right) + \underline {\left( { – 5} \right)} {/tex} [Commutative property]
(ii) {tex} – 53 + \underline 0 = – 53{/tex} [Zero additive property]
(iii) {tex}17 + \underline {\left( { – 17} \right)} = 0{/tex} (Additive identity]
(iv){tex}\left[ {13 + \left( {12} \right)} \right] + \underline {\left( { – 7} \right)} = 13 + \left[ {\left( { – 12} \right) + \left( { – 7} \right)} \right]{/tex} [Associative property]
{tex}\left( { – 4} \right) + \left[ {15 + \left( { – 3} \right)} \right] = \left[ { – 4 + 15} \right] + \underline {\left( { – 3} \right)} {/tex} [Associative property]
NCERT Solutions for Class 7 Maths Exercise 1.2
NCERT Solutions Class 7 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 7 Maths includes text book solutions from Class 7 Maths Book . NCERT Solutions for CBSE Class 7 Maths have total 15 chapters. 7 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 7 solutions PDF and Maths ncert class 7 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.
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