Ask questions, doubts, problems and we will help you..
Ask questions which are clear, concise and easy to understand.
Ask Question
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Deepanshu Ghangas 3 years, 1 month ago (13629718)
- 1 answers
Posted by Kiruba M 3 years, 1 month ago (13629669)
- 0 answers
Posted by Jatin Kumar 3 years, 1 month ago (13629635)
- 3 answers
Posted by Aakanksha Chaudhary 3 years, 1 month ago (13629596)
- 5 answers
イシャントク ゲーマー 3 years, 1 month ago (10045800)
Posted by Anushka Gupta 3 years, 1 month ago (13629592)
- 5 answers
Posted by Vikram Dhawai 3 years, 1 month ago (13629476)
- 2 answers
Posted by Vikram Dhawai 3 years, 1 month ago (13629476)
- 2 answers
Posted by Anirudh Mittal 3 years, 1 month ago (3658422)
- 0 answers
Posted by Anshika Gupta 3 years, 1 month ago (12836846)
- 3 answers
Cbse Cbse Cbs Ecbs E Sususududududuudukukkukukukuk 3 years, 1 month ago (11982787)
Posted by Aditya Batra 3 years, 1 month ago (10811156)
- 0 answers
Posted by Saili Gawande 3 years, 1 month ago (13573721)
- 5 answers
Posted by Diksha Rai 3 years, 1 month ago (12736794)
- 2 answers
Posted by Jannat Mehra Mehra 3 years, 1 month ago (13629139)
- 2 answers
Posted by Mehak Sampla 3 years, 1 month ago (3854297)
- 3 answers
Aditya Kumar Jha 2 years, 10 months ago (11811590)
Saini.Satwinder Saini Satwinder 3 years, 1 month ago (13334050)
Khushi Rana 3 years, 1 month ago (13421496)
Posted by Viyu Thakor 3 years, 1 month ago (13628918)
- 2 answers
Posted by Aditya Prakash 3 years, 1 month ago (11151414)
- 1 answers
Posted by Naine Keer 3 years, 1 month ago (13256974)
- 1 answers
Posted by Krishnaveer Chahar 3 years, 1 month ago (13605996)
- 1 answers
Posted by Laxman Das 2 years, 11 months ago (2005238)
- 1 answers
Preeti Dabral 2 years, 11 months ago (2983787)
Distance to market s=2.5km=2.5×103 =2500m
Speed with which he goes to market =5km/h={tex}5 \frac{10^3}{3600}=\frac{25}{18} \mathrm{~m} / \mathrm{s}{/tex}
Speed with which he comes back = {tex}7.5 \mathrm{~km} / \mathrm{h}=7.5 \times \frac{10^3}{3600}=\frac{75}{36} \mathrm{~m} / \mathrm{s}{/tex}
(a)Average velocity is zero since his displacement is zero.
(b) (i)Since the initial speed is 5km/s and the market is 2.5 km away,time taken to reach market: {tex}\frac{2.5}{5}=1 / 2 \mathrm{~h}=30 \text { minutes. }{/tex}
Average speed over this interval =5km/h
(ii)After 30 minutes,the man is travelling wuth 7.5 km/h speed for 50-30=20 minutes.The distance he covers in 20 minutes :{tex}7.5 \times \frac{1}{3}=2.5 \mathrm{~km}{/tex}
His average speed in 0 to 50 minutes: Vavg =distance traveled/time {tex}=\frac{2.5+2.5}{(50 / 60)}=6 \mathrm{~km} / \mathrm{h}{/tex}
(iii)In 40-30=10 minutes he travels a distance of : {tex}7.5 \times \frac{1}{6}=1.25 \mathrm{~km}{/tex}
{tex}\mathrm{V}_{\mathrm{avg}}=\frac{2.5+1.25}{(40 / 60)}=5.625 \mathrm{~km} / \mathrm{h}{/tex}
Posted by Yash Yadav 3 years, 1 month ago (13598645)
- 4 answers
Shagun Choudhary 2 years, 10 months ago (10333627)
Seema Singh 3 years ago (4886307)
Posted by Neha Soni 3 years, 1 month ago (13628647)
- 0 answers
Posted by Chongneu Gangte 3 years, 1 month ago (13582651)
- 1 answers
Sakshi Gupta 3 years, 1 month ago (13524456)
Posted by Anushka Kaira 3 years, 1 month ago (11421494)
- 0 answers
Posted by Arjyasini Mahapatro 3 years, 1 month ago (13585826)
- 4 answers
Soumya Sanjan Swain 3 years, 1 month ago (13633481)
Lakshmishree Lekana 3 years, 1 month ago (10466715)
Dibyanshi Satapathy 3 years, 1 month ago (13631892)
イシャントク ゲーマー 3 years, 1 month ago (10045800)
Posted by Md Shahwali 3 years, 1 month ago (1359914)
- 5 answers
Posted by Jay And Jiya Chaubal 3 years, 1 month ago (13618144)
- 4 answers
Posted by Shehzad C 3 years, 1 month ago (13610540)
- 1 answers
Posted by Darshan Darshan 3 years, 1 month ago (13628221)
- 5 answers
Posted by Lakshay S2 3 years, 1 month ago (13628208)
- 0 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Amit Thakur 3 years, 1 month ago (13556478)
2 Thank You