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Ask QuestionPosted by Abhishek Kumar2 2 years, 11 months ago
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Posted by Abhishek Kumar2 2 years, 11 months ago
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Boddepalli Chandra Hasini 2 years, 11 months ago
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Posted by Aditya . 2 years, 11 months ago
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Posted by Chandan Gouri 2 years, 11 months ago
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Hitesh Chaudhary Solution 2 years, 11 months ago
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Posted by T G Full 2 years, 10 months ago
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Preeti Dabral 2 years, 10 months ago
Let the digits of the required 3 - digit number at hundreds, tens and ones places be {tex}a - d, ~ a , ~ a + d{/tex} respectively
Then their sum = 15
i.e, {tex}a - d + a + a + d{/tex} = 15
{tex}\Rightarrow{/tex} {tex}3a{/tex} = 15
{tex}\Rightarrow{/tex} {tex}a{/tex} = 5
Required three digit number = {tex}100(a - d) + 10a + a + d{/tex}
= {tex}100a - 100d + 10a + a + d{/tex}
= {tex}111a - 99d{/tex}
Number obtained by reversing the digits = {tex}100(a + d) + 10a + a - d{/tex}
= {tex}100a + 100d + 10a + a - d{/tex}
= {tex}111a + 99d{/tex}
According to the question,
{tex}111a + 99d = 111a - 99d - 594{/tex}
{tex}\Rightarrow{/tex} {tex}594 = 111a - 99d - 111a - 99d{/tex}
{tex}\Rightarrow{/tex}{tex}594 = -198d{/tex}
{tex}\Rightarrow{/tex}{tex}\frac { - 594 } { 198 } = d{/tex}
{tex}d = -3{/tex}
The number is 111a - 99d
{tex}111 \times 5 - 99 \times - 3{/tex}= 852
555 + 297 = 852
Therefore, Number is 852.
Posted by Anuj Tanwar 2 years, 11 months ago
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Posted by Ronak Chavan 2 years, 10 months ago
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Preeti Dabral 2 years, 10 months ago
Ebright grew up north of Reading, Pennsylvania. He was the only child of his parents. His father died when he was in third grade. He excelled in school and enjoyed collecting rocks, fossils, and coins as a child.
Posted by Adarsh Jha 2 years, 11 months ago
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Parth Yadav 2 years, 11 months ago
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Samiksha Pandey 2 years, 11 months ago
Posted by Pawan Kaur 2 years, 10 months ago
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Preeti Dabral 2 years, 10 months ago
Procrastinating is an act of delaying tasks or actions which are significant for achieving growth in life. Time is precious, and being on time only shows that we value our time. People who are punctual are most trusted and respected, they are held at higher stature and kept in more important positions.
Posted by Ajay Gupta 2 years, 11 months ago
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Parth Yadav 2 years, 11 months ago
Posted by Srusthi Sb 2 years, 10 months ago
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Preeti Dabral 2 years, 10 months ago

As per given condition
Area of sector OAPB = {tex}\frac { 5 } { 36 }{/tex}times the area of circle
{tex}\therefore \quad \pi r ^ { 2 } \times \frac { \theta } { 360 } = \frac { 5 } { 36 } \pi r ^ { 2 }{/tex}
{tex}\therefore \quad \pi r ^ { 2 } \times \frac { x } { 360 } = \frac { 5 } { 36 } \pi r ^ { 2 }{/tex}
{tex}\frac { x } { 360 } = \frac { 5 } { 36 }{/tex} or,
{tex}\begin{array}{l}36\mathrm x=360\;\times5\end{array}{/tex}
{tex}\\\mathrm x=\frac{360\;\times5}{36}{/tex}
{tex}\\\mathrm x=\;10\;\times5{/tex}
{tex}\\\mathrm x\;=\;50{/tex}
Posted by Jainpriyanka Mehta 2 years, 11 months ago
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Muzaif Ur Rahman 2 years, 11 months ago
1Thank You