In given fig. O is the …
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Preeti Dabral 1 year ago
As per given condition
Area of sector OAPB = {tex}\frac { 5 } { 36 }{/tex}times the area of circle
{tex}\therefore \quad \pi r ^ { 2 } \times \frac { \theta } { 360 } = \frac { 5 } { 36 } \pi r ^ { 2 }{/tex}
{tex}\therefore \quad \pi r ^ { 2 } \times \frac { x } { 360 } = \frac { 5 } { 36 } \pi r ^ { 2 }{/tex}
{tex}\frac { x } { 360 } = \frac { 5 } { 36 }{/tex} or,
{tex}\begin{array}{l}36\mathrm x=360\;\times5\end{array}{/tex}
{tex}\\\mathrm x=\frac{360\;\times5}{36}{/tex}
{tex}\\\mathrm x=\;10\;\times5{/tex}
{tex}\\\mathrm x\;=\;50{/tex}
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