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Posted by Siddharth Jangid 5 years, 4 months ago (5283669)
- 0 answers
Posted by Siddharth Jangid 5 years, 4 months ago (5283669)
- 2 answers
Boobala Guru 5 years, 4 months ago (9204318)
Yogita Ingle 5 years, 4 months ago (2577571)
6x² – x – 2 = 0
6x² – 4x+ 3x – 2 = 0
2x(3x - 2) + 1 (3x - 2) = 0
(3x -2) ( 2x + 1) = 0
3x - 2 = 0 and 2x + 1 = 0
3x = 2 and 2x = -1
x = 2/3 and x = -1/2
Posted by Aman Kumar 5 years, 4 months ago (9712159)
- 1 answers
Yogita Ingle 5 years, 4 months ago (2577571)
The narrator’s uncle was considered to be a crazy man. Actually, he was the natural descendant of the crazy streak in the family. He was a huge and powerful man. He had a big strong head with black hair. He was a man of furious nature. He was short tempered and of irritable nature. He would not let anybody talk before him. He would stop him shouting. “It is no harm ; pay no attention to it.”
Posted by Siddharth Jangid 5 years, 4 months ago (5283669)
- 1 answers
Posted by Mikail Shaikh 5 years, 4 months ago (9628137)
- 1 answers
Yogita Ingle 5 years, 4 months ago (2577571)
SP = Rs 5225
Let MP be x
discount = 5% of x
=(5/100)x = 0.05x
SP = MP - discount
⇒5225 = x - 0.05x
⇒0.95x = 5225
⇒x = 5225/0.95 = 5500
∴MP = Rs 5500
Posted by Siddharth Jangid 5 years, 4 months ago (5283669)
- 2 answers
Yogita Ingle 5 years, 4 months ago (2577571)
Sum of first 5 multiples of 3:
Sum of an AP is: n/2 ×(2a+(n−1)d)
a=3,d=3,n=5
Then,
Sum = 5/2 ×(2×3+(5−1)×(3))
= 5/2×(6+12)
= 45
Posted by Siddharth Jangid 5 years, 4 months ago (5283669)
- 1 answers
Yogita Ingle 5 years, 4 months ago (2577571)
(sin30+cos30) - (sin60+cos60)
sin30 = 1/2
sin60= √3/2
cos30= √3/2
cos60= 1/2
= (1/2+√3/2) - (√3/2+1/2)
=1+√3/2 - √3+1/2
= 1+1+√3-√3 /2
= 2/2
= 1
Posted by Rahil Khokhariya 5 years, 4 months ago (9698942)
- 2 answers
Posted by Siddharth Jangid 5 years, 4 months ago (5283669)
- 2 answers
Yogita Ingle 5 years, 4 months ago (2577571)
The value of cosec 30 is
cosec 30 = 1/sin 30
cosec 30 = 1/ 1/2= 2
Posted by Siddharth Jangid 5 years, 4 months ago (5283669)
- 2 answers
Posted by Siddharth Jangid 5 years, 4 months ago (5283669)
- 1 answers
Yogita Ingle 5 years, 4 months ago (2577571)
Using the section formula, if a point (x,y) divides the line joining the
points (x1,y1) and (x2,y2) internally in the
ratio m:n, then (x,y)=(mx2+nx1)/m+n ,(my2+ny1)/m+n
Substituting (x1,y1)=(7,−6) and (x2,y2)=(3,4) and m=1,n=2 in the section formula, we get
After solving we get x = 17/3 and y = -8/3
Since, x− cordinate is positive and y− cordinate is negative, the point lies in the IV quadrant.
Posted by Nisheryee Jain 5 years, 4 months ago (9651548)
- 0 answers
Posted by Siddharth Jangid 5 years, 4 months ago (5283669)
- 3 answers
Yogita Ingle 5 years, 4 months ago (2577571)
a=10 and d=10
a1 = 10
a2 = a1 + d = 10 + 10 = 20
a3 = a2 + d = 20 + 10 = 30
a4 = a3 + d = 30 + 10 = 40
If a=10 and d=10, then first four terms will be: 10, 20, 30, 40,.........
Posted by Yug Patel 5 years, 4 months ago (9667770)
- 1 answers
Yogita Ingle 5 years, 4 months ago (2577571)
Stomatal apparatus is a pair of guard cells with or without surrounding subsidiary cells which function as a value to open or close a stomatal pore for gaseous exchange and transpiration.
Each stoma is made of two bean-shaped cells called the guard cells. The guard cells are dumb-bell shaped in grasses. They contain chloroplasts and small vacuoles. They are thick-walled in the area of contact and thin-walled elsewhere. As the guard cells swell up due to endosmosis, their thin-walled sides expand. The thick walls of the two guard cells also bend outwardly and create a pore in between them.
Posted by Siddharth Jangid 5 years, 4 months ago (5283669)
- 1 answers
Yogita Ingle 5 years, 4 months ago (2577571)
Let the points A(-4,0),B(4,0)and C(0,3)are the vertices
∴AB=√(4−(−4))2+(0−0)2=√(8)2=√64=8
∴BC=√(0−4)2+(0−3)2= √16+9 = √25 = 5
∴CA=√(−4−0)2+(0−3)2=√16+9=√25=5
As we know that two points are equal in the given vertices
∴This is the vertices of a isosceles triangle.
Posted by Rukesh Rukesh Sangwan 5 years, 4 months ago (9707869)
- 2 answers
Posted by Siddharth Jangid 5 years, 4 months ago (5283669)
- 1 answers
Posted by Siddharth Jangid 5 years, 4 months ago (5283669)
- 1 answers
Boobala Guru 5 years, 4 months ago (9204318)
Posted by Siddharth Jangid 5 years, 4 months ago (5283669)
- 2 answers
Posted by Siddharth Jangid 5 years, 4 months ago (5283669)
- 1 answers
Posted by Siddharth Jangid 5 years, 4 months ago (5283669)
- 1 answers
Posted by Yug Patel 5 years, 4 months ago (9667770)
- 1 answers
Meghna Thapar 5 years, 4 months ago (6237)
Vascular bundles wherein xylem and phloem lie side by side are called as radial bundles while conjoint vascular bundles have xylem and phloem separated from one another as are found in leaves.
A conjoint vascular bundle can be collateral or bicollateral. Collateral vascular bundles have xylem and phloem arranged in same radium with xylem present towards the inner side and phloem towards the outer side. Bicollateral bundles have phloem on both sides of the xylem as compared to collateral bundles wherein phloem is present on one side of xylem only. In leaves, xylem is present near upper epidermis and phloem near the lower one with phloem on one side of xylem thus collateral, not bicollateral bundles. On the basis of the presence of absence of cambium, collateral bundles are grouped as open or close bundles, those with cambium are termed as open vascular bundles while the vascular bundles without cambium are termed as closed.
Leaves lack cambium in vascular bundles making them closed type, this vascular bundles in leaves are found irregularly scattered in the mesophyll with the largest and the oldest one at centre and is termed as midrib vein. Each vascular bundle has a bundle sheath of compactly arranged barrel shaped parenchyma cells which cover both xylem and phloem. Xylem is present near upper epidermis and phloem near the lower one. Xylem has protoxylem and metaxylem vessels with protoxylem present towards upper epidermis, thus conjoint, collateral close vascular bundle with endarch xylem.
Posted by Navdeep Choudhary 5 years, 4 months ago (9706522)
- 2 answers
Posted by Siddharth Jangid 5 years, 4 months ago (5283669)
- 0 answers
Posted by Siddharth Jangid 5 years, 4 months ago (5283669)
- 0 answers
Posted by Siddharth Jangid 5 years, 4 months ago (5283669)
- 0 answers
Posted by Siddharth Jangid 5 years, 4 months ago (5283669)
- 0 answers
Posted by Raunaq Singh 5 years, 4 months ago (2335398)
- 2 answers
Posted by Yug Patel 5 years, 4 months ago (9667770)
- 1 answers
Meghna Thapar 5 years, 4 months ago (6237)
Simple permanent tissues are composed of cells which are structurally and functionally similar. They are of three types – parenchyma, collenchyma and sclerenchyma.
- Parenchyma –
Parenchyma tissue consists of relatively unspecialised cells with thin cell walls. They are live cells. They are usually loosely packed, so that large spaces between them. This tissue provides support to plants and also stores food. In some cases, it contains chlorophyll and performs photosynthesis, and then it is called as chlorenchyma. In aquatic plants, large air cavities are present in parenchyma to give buoyancy to the plants to help them float. Such a parenchyma type is called aerenchyma. The parenchyma of stems and roots also stores nutrients and water.
ii. Collenchyma –
The cells of collenchyma tissue are living, elongated and irregularly thickened at the corners. There is very little or no intercellular space. It allows easy bending in various parts of a plant (leaf, stem) without breaking. Thus, provides flexibility to the plant. It also provides mechanical support to plants.
iii. Sclerenchyma –
The cells of sclerenchyma tissue are dead. They are long and narrow as the walls are thickened due to deposition of lignin. The walls of cells are so thick that there is no internal space inside the cell. This tissue is present in stems, around vascular bundles, in the veins of leaves and in the hard covering of seeds and nuts. It provides strength to the plant parts and makes the plant hard and stiff.
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